有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?

我知道有一个名为UIDevice.currentDevice()的属性。模型,但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。

我也知道在Objective-C中使用以下方法可以轻松完成:

#import <sys/utsname.h>

struct utsname systemInfo;
uname(&systemInfo);

NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];

但是我正在Swift中开发我的iPhone应用程序,所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?


当前回答

当你使用Swift 3时,接受的答案有一些问题! 这个答案(灵感来自NAZIK)适用于Swift 3和新款iPhone:

import UIKit


public extension UIDevice {
var modelName: String {
    #if (arch(i386) || arch(x86_64)) && os(iOS)
        let DEVICE_IS_SIMULATOR = true
    #else
        let DEVICE_IS_SIMULATOR = false
    #endif

    var machineString = String()

    if DEVICE_IS_SIMULATOR == true
    {
        if let dir = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
            machineString = dir
        }
    }
    else {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        machineString = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8 , value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
    }
    switch machineString {
    case "iPod4,1":                                 return "iPod Touch 4G"
    case "iPod5,1":                                 return "iPod Touch 5G"
    case "iPod7,1":                                 return "iPod Touch 6G"
    case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return "iPhone 4"
    case "iPhone4,1":                               return "iPhone 4s"
    case "iPhone5,1", "iPhone5,2":                  return "iPhone 5"
    case "iPhone5,3", "iPhone5,4":                  return "iPhone 5c"
    case "iPhone6,1", "iPhone6,2":                  return "iPhone 5s"
    case "iPhone7,2":                               return "iPhone 6"
    case "iPhone7,1":                               return "iPhone 6 Plus"
    case "iPhone8,1":                               return "iPhone 6s"
    case "iPhone8,2":                               return "iPhone 6s Plus"
    case "iPhone8,4":                               return "iPhone SE"
    case "iPhone9,1", "iPhone9,3":                  return "iPhone 7"
    case "iPhone9,2", "iPhone 9,4":                 return "iPhone 7 Plus"
    case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
    case "iPad3,1", "iPad3,2", "iPad3,3":           return "iPad 3"
    case "iPad3,4", "iPad3,5", "iPad3,6":           return "iPad 4"
    case "iPad4,1", "iPad4,2", "iPad4,3":           return "iPad Air"
    case "iPad5,3", "iPad5,4":                      return "iPad Air 2"
    case "iPad2,5", "iPad2,6", "iPad2,7":           return "iPad Mini"
    case "iPad4,4", "iPad4,5", "iPad4,6":           return "iPad Mini 2"
    case "iPad4,7", "iPad4,8", "iPad4,9":           return "iPad Mini 3"
    case "iPad5,1", "iPad5,2":                      return "iPad Mini 4"
    case "iPad6,3", "iPad6,4":                      return "iPad Pro (9.7 inch)"
    case "iPad6,7", "iPad6,8":                      return "iPad Pro (12.9 inch)"
    case "AppleTV5,3":                              return "Apple TV"
    default:                                        return machineString
    }
}
}

其他回答

维基设备

异步库,从iphonewiki给你答案

A crazy little experiment for automation fans like me. I made this algorithm that reads the identification code of the device, physical or simulated, and load the theiphonewiki page to extrapolate the model name based on the identification code (example iPhone11,2 -> iPhone XS). The algorithm interfaces with the WIKI page using the internal Wiki API Sandbox tool that allows you to have a JSON response, however the content is not obtainable in JSON (just the part that was needed, that is the wikitables) so I parsed the HTML content to get to the device name, without using third parts HTML parsing libraries.

优点:总是更新,你不需要添加新的设备

缺点:异步回答使用维基页面从网络

附注:请随意改进我的代码,以获得更精确的结果和更优雅的语法 P.S.S.如果你需要更直接的答案,请使用我之前在本页的答案

public extension UIDevice {
    var identifier: String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let modelCode = withUnsafePointer(to: &systemInfo.machine) {
            $0.withMemoryRebound(to: CChar.self, capacity: 1) {
                ptr in String.init(validatingUTF8: ptr)
            }
        }
        if modelCode == "x86_64" {
            if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
                if let simMap = String(validatingUTF8: simModelCode) {
                    return simMap
                }
            }
        }
        return modelCode ?? "?unrecognized?"
    }
}
class WikiDevice {
    static func model(_ completion: @escaping ((String) -> ())){
        let unrecognized = "?unrecognized?"
        guard let wikiUrl=URL(string:"https://www.theiphonewiki.com//w/api.php?action=parse&format=json&page=Models") else { return completion(unrecognized) }
        var identifier: String {
            var systemInfo = utsname()
            uname(&systemInfo)
            let modelCode = withUnsafePointer(to: &systemInfo.machine) {
                $0.withMemoryRebound(to: CChar.self, capacity: 1) {
                    ptr in String.init(validatingUTF8: ptr)
                }
            }
            if modelCode == "x86_64" {
                if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
                    if let simMap = String(validatingUTF8: simModelCode) {
                        return simMap
                    }
                }
            }
            return modelCode ?? unrecognized
        }
        guard identifier != unrecognized else { return completion(unrecognized)}
        let request = URLRequest(url: wikiUrl)
        URLSession.shared.dataTask(with: request) { (data, response, error) in
            do {
                guard let data = data,
                    let response = response as? HTTPURLResponse, (200 ..< 300) ~= response.statusCode,
                    error == nil else { return completion(unrecognized) }
                guard let convertedString = String(data: data, encoding: String.Encoding.utf8) else { return completion(unrecognized) }
                var wikiTables = convertedString.components(separatedBy: "wikitable")
                wikiTables.removeFirst()
                var tables = [[String]]()
                wikiTables.enumerated().forEach{ index,table in
                    let rawRows = table.components(separatedBy: #"<tr>\n<td"#)
                    var counter = 0
                    var rows = [String]()
                    while counter < rawRows.count {
                        let rawRow = rawRows[counter]
                        if let subRowsNum = rawRow.components(separatedBy: #"rowspan=\""#).dropFirst().compactMap({ sub in
                            (sub.range(of: #"\">"#)?.lowerBound).flatMap { endRange in
                                String(sub[sub.startIndex ..< endRange])
                            }
                        }).first {
                            if let subRowsTot = Int(subRowsNum) {
                                var otherRows = ""
                                for i in counter..<counter+subRowsTot {
                                    otherRows += rawRows[i]
                                }
                                let row = rawRow + otherRows
                                rows.append(row)
                                counter += subRowsTot-1
                            }
                        } else {
                            rows.append(rawRows[counter])
                        }
                        counter += 1
                    }
                    tables.append(rows)
                }
                for table in tables {
                    if let rowIndex = table.firstIndex(where: {$0.lowercased().contains(identifier.lowercased())}) {
                        let rows = table[rowIndex].components(separatedBy: "<td>")
                        if rows.count>0 {
                            if rows[0].contains("title") { //hyperlink
                                if let (cleanedGen) = rows[0].components(separatedBy: #">"#).dropFirst().compactMap({ sub in
                                    (sub.range(of: "</")?.lowerBound).flatMap { endRange in
                                        String(sub[sub.startIndex ..< endRange]).replacingOccurrences(of: #"\n"#, with: "")
                                    }
                                }).first {
                                    completion(cleanedGen)
                                }
                            } else {
                                let raw = rows[0].replacingOccurrences(of: "<td>", with: "")
                                let cleanedGen = raw.replacingOccurrences(of: #"\n"#, with: "")
                                completion(cleanedGen)
                            }
                            return
                        }
                    }
                }
                completion(unrecognized)
            }
        }.resume()
    }
}

用法:

var deviceModel:String = ""
WikiDevice.model { (model) in
     print("Using WikiDevice, running on: \(model)")
     deviceModel = model
}

输出:

Using WikiDevice, running on: iPhone 11 Pro Max

GitHUB:

如果您需要测试这个库,您可以从这里下载测试项目

我已经实现了一个超轻量级的库,可以根据给出的一些答案来检测使用的设备:https://github.com/schickling/Device.swift

它可以通过迦太基安装,并像这样使用:

import Device

let deviceType = UIDevice.currentDevice().deviceType

switch deviceType {
case .IPhone6: print("Do stuff for iPhone6")
case .IPadMini: print("Do stuff for iPad mini")
default: print("Check other available cases of DeviceType")
}

这是一个用于检测apple设备的新库

import DeviceDetector

let detector = DeviceDetector.shared
let deviceName = detector.currentDeviceName
let deviceSet = detector.currentDevice
        
let information = """
Model: \(deviceName)
iPhone?: \(detector.isiPhone)
iPad?: \(detector.isiPad)
Notch?: \(detector.hasSafeArea)
        
4inch?: \(DeviceSet.iPhone4inchSet.contains(deviceSet))
4.7inch?: \(DeviceSet.iPhone4_7inchSet.contains(deviceSet))
iPhoneSE?: \(DeviceSet.iPhoneSESet.contains(deviceSet))
iPhonePlus?: \(DeviceSet.iPhonePlusSet.contains(deviceSet))
iPadPro?: \(DeviceSet.iPadProSet.contains(deviceSet))
"""

结果

还有另一个简单的替代方案(模型标识符参考可在https://www.theiphonewiki.com/wiki/Models):找到)

Swift 3/4/5的更新答案,包括字符串修剪和模拟器支持:

func modelIdentifier() -> String {
    if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
    var sysinfo = utsname()
    uname(&sysinfo) // ignore return value
    return String(bytes: Data(bytes: &sysinfo.machine, count: Int(_SYS_NAMELEN)), encoding: .ascii)!.trimmingCharacters(in: .controlCharacters)
}

对于设备和模拟器, 创建一个名为UIDevice.swift的新swift文件

添加以下代码

import UIKit


public extension UIDevice {

var modelName: String {
    #if (arch(i386) || arch(x86_64)) && os(iOS)
        let DEVICE_IS_SIMULATOR = true
    #else
        let DEVICE_IS_SIMULATOR = false
    #endif

    var machineString : String = ""

    if DEVICE_IS_SIMULATOR == true
    {

        if let dir = NSProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
            machineString = dir
        }
    }
    else {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        machineString = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8 where value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
    }
    switch machineString {
    case "iPod5,1":                                 return "iPod Touch 5"
    case "iPod7,1":                                 return "iPod Touch 6"
    case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return "iPhone 4"
    case "iPhone4,1":                               return "iPhone 4s"
    case "iPhone5,1", "iPhone5,2":                  return "iPhone 5"
    case "iPhone5,3", "iPhone5,4":                  return "iPhone 5c"
    case "iPhone6,1", "iPhone6,2":                  return "iPhone 5s"
    case "iPhone7,2":                               return "iPhone 6"
    case "iPhone7,1":                               return "iPhone 6 Plus"
    case "iPhone8,1":                               return "iPhone 6s"
    case "iPhone8,2":                               return "iPhone 6s Plus"
    case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
    case "iPad3,1", "iPad3,2", "iPad3,3":           return "iPad 3"
    case "iPad3,4", "iPad3,5", "iPad3,6":           return "iPad 4"
    case "iPad4,1", "iPad4,2", "iPad4,3":           return "iPad Air"
    case "iPad5,3", "iPad5,4":                      return "iPad Air 2"
    case "iPad2,5", "iPad2,6", "iPad2,7":           return "iPad Mini"
    case "iPad4,4", "iPad4,5", "iPad4,6":           return "iPad Mini 2"
    case "iPad4,7", "iPad4,8", "iPad4,9":           return "iPad Mini 3"
    case "iPad5,1", "iPad5,2":                      return "iPad Mini 4"
    case "iPad6,7", "iPad6,8":                      return "iPad Pro"
    case "AppleTV5,3":                              return "Apple TV"
    default:                                        return machineString
    }
}
}

然后在你的视图控制器中,

 let deviceType = UIDevice.currentDevice().modelName

    if deviceType.lowercaseString.rangeOfString("iphone 4") != nil {
       print("iPhone 4 or iphone 4s")
    }
    else if deviceType.lowercaseString.rangeOfString("iphone 5") != nil {
        print("iPhone 5 or iphone 5s or iphone 5c")
    }
   else if deviceType.lowercaseString.rangeOfString("iphone 6") != nil {
        print("iPhone 6 Series")
    }