有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
我在UIDevice上做了另一个示例扩展，包括基于@HAS的答案的模拟器模型标识符。它在上面的Swift3.2(包括Swift 4)中工作得很好。x, Swift 5):
let modelName = UIDevice.current.modelName
新增型号:iPod touch(第七代)，iPhone SE(第二代)，iPhone 12 mini, iPhone 12 Pro, iPhone 12 Pro Max, iPad Pro(12.9英寸)(第四代)
import UIKit
public extension UIDevice {
/// pares the deveice name as the standard name
var modelName: String {
#if targetEnvironment(simulator)
let identifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"]!
#else
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
#endif
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPod9,1": return "iPod touch (7th generation)"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPhone12,1": return "iPhone 11"
case "iPhone12,3": return "iPhone 11 Pro"
case "iPhone12,5": return "iPhone 11 Pro Max"
case "iPhone12,8": return "iPhone SE (2nd generation)"
case "iPhone13,1": return "iPhone 12 mini"
case "iPhone13,2": return "iPhone 12"
case "iPhone13,3": return "iPhone 12 Pro"
case "iPhone13,4": return "iPhone 12 Pro Max"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)"
case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
default: return identifier
}
}
}
其他回答
对于设备和模拟器， 创建一个名为UIDevice.swift的新swift文件
添加以下代码
import UIKit
public extension UIDevice {
var modelName: String {
#if (arch(i386) || arch(x86_64)) && os(iOS)
let DEVICE_IS_SIMULATOR = true
#else
let DEVICE_IS_SIMULATOR = false
#endif
var machineString : String = ""
if DEVICE_IS_SIMULATOR == true
{
if let dir = NSProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
machineString = dir
}
}
else {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
machineString = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 where value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
}
switch machineString {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,7", "iPad6,8": return "iPad Pro"
case "AppleTV5,3": return "Apple TV"
default: return machineString
}
}
}
然后在你的视图控制器中，
let deviceType = UIDevice.currentDevice().modelName
if deviceType.lowercaseString.rangeOfString("iphone 4") != nil {
print("iPhone 4 or iphone 4s")
}
else if deviceType.lowercaseString.rangeOfString("iphone 5") != nil {
print("iPhone 5 or iphone 5s or iphone 5c")
}
else if deviceType.lowercaseString.rangeOfString("iphone 6") != nil {
print("iPhone 6 Series")
}
还有另一个简单的替代方案(模型标识符参考可在https://www.theiphonewiki.com/wiki/Models):找到)
Swift 3/4/5的更新答案，包括字符串修剪和模拟器支持:
func modelIdentifier() -> String {
if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
var sysinfo = utsname()
uname(&sysinfo) // ignore return value
return String(bytes: Data(bytes: &sysinfo.machine, count: Int(_SYS_NAMELEN)), encoding: .ascii)!.trimmingCharacters(in: .controlCharacters)
}
这是一个用于检测apple设备的新库
import DeviceDetector
let detector = DeviceDetector.shared
let deviceName = detector.currentDeviceName
let deviceSet = detector.currentDevice
let information = """
Model: \(deviceName)
iPhone?: \(detector.isiPhone)
iPad?: \(detector.isiPad)
Notch?: \(detector.hasSafeArea)
4inch?: \(DeviceSet.iPhone4inchSet.contains(deviceSet))
4.7inch?: \(DeviceSet.iPhone4_7inchSet.contains(deviceSet))
iPhoneSE?: \(DeviceSet.iPhoneSESet.contains(deviceSet))
iPhonePlus?: \(DeviceSet.iPhonePlusSet.contains(deviceSet))
iPadPro?: \(DeviceSet.iPadProSet.contains(deviceSet))
"""
结果
获取模型名称(营销名称)的最简单方法
小心使用私有API -[UIDevice _deviceinfokey:]，你不会被Apple拒绝。
// works on both simulators and real devices, iOS 8 to iOS 12
NSString *deviceModelName(void) {
// For Simulator
NSString *modelName = NSProcessInfo.processInfo.environment[@"SIMULATOR_DEVICE_NAME"];
if (modelName.length > 0) {
return modelName;
}
// For real devices and simulators, except simulators running on iOS 8.x
UIDevice *device = [UIDevice currentDevice];
NSString *selName = [NSString stringWithFormat:@"_%@ForKey:", @"deviceInfo"];
SEL selector = NSSelectorFromString(selName);
if ([device respondsToSelector:selector]) {
#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Warc-performSelector-leaks"
modelName = [device performSelector:selector withObject:@"marketing-name"];
#pragma clang diagnostic pop
}
return modelName;
}
我是怎么得到"marketing-name"这个密钥的?
运行在模拟器上的NSProcessInfo.processInfo.environment包含一个名为“SIMULATOR_CAPABILITIES”的键，其值是一个plist文件。然后你打开plist文件，你会得到模型名称的关键字“marketing-name”。
维基设备
异步库，从iphonewiki给你答案
A crazy little experiment for automation fans like me. I made this algorithm that reads the identification code of the device, physical or simulated, and load the theiphonewiki page to extrapolate the model name based on the identification code (example iPhone11,2 -> iPhone XS). The algorithm interfaces with the WIKI page using the internal Wiki API Sandbox tool that allows you to have a JSON response, however the content is not obtainable in JSON (just the part that was needed, that is the wikitables) so I parsed the HTML content to get to the device name, without using third parts HTML parsing libraries.
优点:总是更新，你不需要添加新的设备
缺点:异步回答使用维基页面从网络
附注:请随意改进我的代码，以获得更精确的结果和更优雅的语法 P.S.S.如果你需要更直接的答案，请使用我之前在本页的答案
public extension UIDevice {
var identifier: String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
if modelCode == "x86_64" {
if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
if let simMap = String(validatingUTF8: simModelCode) {
return simMap
}
}
}
return modelCode ?? "?unrecognized?"
}
}
class WikiDevice {
static func model(_ completion: @escaping ((String) -> ())){
let unrecognized = "?unrecognized?"
guard let wikiUrl=URL(string:"https://www.theiphonewiki.com//w/api.php?action=parse&format=json&page=Models") else { return completion(unrecognized) }
var identifier: String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
if modelCode == "x86_64" {
if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
if let simMap = String(validatingUTF8: simModelCode) {
return simMap
}
}
}
return modelCode ?? unrecognized
}
guard identifier != unrecognized else { return completion(unrecognized)}
let request = URLRequest(url: wikiUrl)
URLSession.shared.dataTask(with: request) { (data, response, error) in
do {
guard let data = data,
let response = response as? HTTPURLResponse, (200 ..< 300) ~= response.statusCode,
error == nil else { return completion(unrecognized) }
guard let convertedString = String(data: data, encoding: String.Encoding.utf8) else { return completion(unrecognized) }
var wikiTables = convertedString.components(separatedBy: "wikitable")
wikiTables.removeFirst()
var tables = [[String]]()
wikiTables.enumerated().forEach{ index,table in
let rawRows = table.components(separatedBy: #"<tr>\n<td"#)
var counter = 0
var rows = [String]()
while counter < rawRows.count {
let rawRow = rawRows[counter]
if let subRowsNum = rawRow.components(separatedBy: #"rowspan=\""#).dropFirst().compactMap({ sub in
(sub.range(of: #"\">"#)?.lowerBound).flatMap { endRange in
String(sub[sub.startIndex ..< endRange])
}
}).first {
if let subRowsTot = Int(subRowsNum) {
var otherRows = ""
for i in counter..<counter+subRowsTot {
otherRows += rawRows[i]
}
let row = rawRow + otherRows
rows.append(row)
counter += subRowsTot-1
}
} else {
rows.append(rawRows[counter])
}
counter += 1
}
tables.append(rows)
}
for table in tables {
if let rowIndex = table.firstIndex(where: {$0.lowercased().contains(identifier.lowercased())}) {
let rows = table[rowIndex].components(separatedBy: "<td>")
if rows.count>0 {
if rows[0].contains("title") { //hyperlink
if let (cleanedGen) = rows[0].components(separatedBy: #">"#).dropFirst().compactMap({ sub in
(sub.range(of: "</")?.lowerBound).flatMap { endRange in
String(sub[sub.startIndex ..< endRange]).replacingOccurrences(of: #"\n"#, with: "")
}
}).first {
completion(cleanedGen)
}
} else {
let raw = rows[0].replacingOccurrences(of: "<td>", with: "")
let cleanedGen = raw.replacingOccurrences(of: #"\n"#, with: "")
completion(cleanedGen)
}
return
}
}
}
completion(unrecognized)
}
}.resume()
}
}
用法:
var deviceModel:String = ""
WikiDevice.model { (model) in
print("Using WikiDevice, running on: \(model)")
deviceModel = model
}
输出:
Using WikiDevice, running on: iPhone 11 Pro Max
GitHUB:
如果您需要测试这个库，您可以从这里下载测试项目
