下面是一种使用RxJava的方法:

override fun onCreate(...) {
    backPresses.timeInterval(TimeUnit.MILLISECONDS, Schedulers.io())
            .skip(1) //Skip initial event; delay will be 0.
            .onMain()
            .subscribe {
                if (it.time() < 7000) super.onBackPressed() //7000 is the duration of a Toast with length LENGTH_LONG.
            }.addTo(compositeDisposable)

    backPresses.throttleFirst(7000, TimeUnit.MILLISECONDS, Schedulers.io())
            .subscribe { Toast.makeText(this, "Press back again to exit.", LENGTH_LONG).show() }
            .addTo(compositeDisposable)
}

override fun onBackPressed() = backPresses.onNext(Unit)

boolean doubleBackToExitPressedOnce = false;

@Override
public void onBackPressed() {
    if (doubleBackToExitPressedOnce) {
        super.onBackPressed();
        return;
    }

    this.doubleBackToExitPressedOnce = true;

    Snackbar.make(findViewById(R.id.photo_album_parent_view), "Please click BACK again to exit", Snackbar.LENGTH_SHORT).show();

    new Handler().postDelayed(new Runnable() {

        @Override
        public void run() {
            doubleBackToExitPressedOnce=false;
        }
    }, 2000);
}

我已经尝试为此创建了一个utils类，因此任何活动或片段都可以实现这一点，从而变得更简单。

代码是用Kotlin编写的，并且具有java互操作。

我使用协程来延迟和重置标志变量。但是您可以根据自己的需要进行修改。

其他文件:SafeToast.kt

lateinit var toast: Toast

fun Context.safeToast(msg: String, length: Int = Toast.LENGTH_LONG, action: (Context) -> Toast = default) {
    toast = SafeToast.makeText(this@safeToast, msg, length).apply {
        // do anything new here
        action(this@safeToast)
        show()
    }
}

fun Context.toastSpammable(msg: String) {
    cancel()
    safeToast(msg, Toast.LENGTH_SHORT)
}

fun Fragment.toastSpammable(msg: String) {
    cancel()
    requireContext().safeToast(msg, Toast.LENGTH_SHORT)
}

private val default: (Context) -> Toast = { it -> SafeToast.makeText(it, "", Toast.LENGTH_LONG) }

private fun cancel() {
    if (::toast.isInitialized) toast.cancel()
}

ActivityUtils.kt

@file:JvmMultifileClass
@file:JvmName("ActivityUtils")
package your.company.com

import android.app.Activity
import your.company.com.R
import kotlinx.coroutines.GlobalScope
import kotlinx.coroutines.delay
import kotlinx.coroutines.launch


private var backButtonPressedTwice = false

fun Activity.onBackPressedTwiceFinish() {
    onBackPressedTwiceFinish(getString(R.string.msg_back_pressed_to_exit), 2000)
}

fun Activity.onBackPressedTwiceFinish(@StringRes message: Int, time: Long) {
    onBackPressedTwiceFinish(getString(message), time)
}

fun Activity.onBackPressedTwiceFinish(message: String, time: Long) {
    if (backButtonPressedTwice) {
        onBackPressed()
    } else {
        backButtonPressedTwice = true
        toastSpammable(message)
        GlobalScope.launch {
            delay(time)
            backButtonPressedTwice = false
        }
    }
}

Kotlin中的用法

// ActivityA.kt
override fun onBackPressed() {
    onBackPressedTwiceFinish()
}

在Java中使用

@Override 
public void onBackPressed() {
    ActivityUtils.onBackPressedTwiceFinish()
}

这段代码的灵感来自这里的@webserveis

 private static final int TIME_DELAY = 2000;
    private static long back_pressed;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }
    @Override
    public void onBackPressed() {
        if (back_pressed + TIME_DELAY > System.currentTimeMillis()) {
            super.onBackPressed();
        } else {
            Toast.makeText(getBaseContext(), "Press once again to exit!",
                    Toast.LENGTH_SHORT).show();
        }
        back_pressed = System.currentTimeMillis();
    }

以下是我的看法:

 int oddeven = 0;
 long backBtnPressed1;
 long backBtnPressed2;
 @Override
 public void onBackPressed() {
     oddeven++;
     if(oddeven%2==0){
         backBtnPressed2 = System.currentTimeMillis();
         if(backBtnPressed2-backBtnPressed1<2000) {
            super.onBackPressed();
            return;
         }
     }
     else if(oddeven%2==1) { 
         backBtnPressed1 = System.currentTimeMillis();    
        //  Insert toast back button here
     }
 }

这个答案很容易使用，但我们需要双击退出。我只是修改了答案，

    @Override
public void onBackPressed() {
    ++k;
    if(k==1){
        Toast.makeText(this, "Press back one more time to exit", Toast.LENGTH_SHORT).show();
        new Handler(Looper.getMainLooper()).postDelayed(new Runnable() {
            @Override
            public void run() {
                --k;
            }
        },1000);
    }else{
        //do whatever you want to do on the click after the first for example:
        finishAffinity();
    }
}