这是我做的另一种方法

    StringBuilder str=new StringBuilder("pirai sudie test test");

    str.setCharAt(0,Character.toUpperCase(str.charAt(0)));

    for(int i=str.length()-1;i>=0;i--)
    {
        if(Character.isSpaceChar(str.charAt(i)))
            str.setCharAt(i+1,Character.toUpperCase(str.charAt(i+1)));
    }

    System.out.println(str);

这是我的解决方案。

今晚我偶然发现了这个问题，并决定研究一下。我发现Neelam Singh的答案几乎在那里，所以我决定解决这个问题(断在空字符串上)，导致系统崩溃。

您正在寻找的方法名为capString(String s)。 它把“这里才早上5点”变成了“这里才早上5点”。

代码注释得很好，喜欢吧。

package com.lincolnwdaniel.interactivestory.model;

    public class StringS {

    /**
     * @param s is a string of any length, ideally only one word
     * @return a capitalized string.
     * only the first letter of the string is made to uppercase
     */
    public static String capSingleWord(String s) {
        if(s.isEmpty() || s.length()<2) {
            return Character.toUpperCase(s.charAt(0))+"";
        } 
        else {
            return Character.toUpperCase(s.charAt(0)) + s.substring(1);
        }
    }

    /**
     *
     * @param s is a string of any length
     * @return a title cased string.
     * All first letter of each word is made to uppercase
     */
    public static String capString(String s) {
        // Check if the string is empty, if it is, return it immediately
        if(s.isEmpty()){
            return s;
        }

        // Split string on space and create array of words
        String[] arr = s.split(" ");
        // Create a string buffer to hold the new capitalized string
        StringBuffer sb = new StringBuffer();

        // Check if the array is empty (would be caused by the passage of s as an empty string [i.g "" or " "],
        // If it is, return the original string immediately
        if( arr.length < 1 ){
            return s;
        }

        for (int i = 0; i < arr.length; i++) {
            sb.append(Character.toUpperCase(arr[i].charAt(0)))
                    .append(arr[i].substring(1)).append(" ");
        }
        return sb.toString().trim();
    }
}

我需要做一个通用的toString(Object obj)帮助类函数，在那里我必须将字段名转换为方法名-传递对象的getXXX()。

下面是代码

/**
 * @author DPARASOU
 * Utility method to replace the first char of a string with uppercase but leave other chars as it is.
 * ToString() 
 * @param inStr - String
 * @return String
 */
public static String firstCaps(String inStr)
{
    if (inStr != null && inStr.length() > 0)
    {
        char[] outStr = inStr.toCharArray();
        outStr[0] = Character.toUpperCase(outStr[0]);
        return String.valueOf(outStr);
    }
    else
        return inStr;
}

我的toString()实用程序是这样的

public static String getToString(Object obj)
{
    StringBuilder toString = new StringBuilder();
    toString.append(obj.getClass().getSimpleName());
    toString.append("[");
    for(Field f : obj.getClass().getDeclaredFields())
    {
        toString.append(f.getName());
        toString.append("=");
        try{
            //toString.append(f.get(obj)); //access privilege issue
            toString.append(invokeGetter(obj, firstCaps(f.getName()), "get"));
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        toString.append(", ");        
    }
    toString.setCharAt(toString.length()-2, ']');
    return toString.toString();
}

来自Java 9+

你可以像这样使用String::replaceAll:

public static void upperCaseAllFirstCharacter(String text) {
    String regex = "\\b(.)(.*?)\\b";
    String result = Pattern.compile(regex).matcher(text).replaceAll(
            matche -> matche.group(1).toUpperCase() + matche.group(2)
    );

    System.out.println(result);
}

例子:

upperCaseAllFirstCharacter("hello this is Just a test");

输出

Hello This Is Just A Test

这里是一个lil程序，我是用来大写每个第一个字母单词在每个子文件夹的父目录。

private void capitalize(String string)
{
    List<String> delimiters = new ArrayList<>();
    delimiters.add(" ");
    delimiters.add("_");

    File folder = new File(string);
    String name = folder.getName();
    String[] characters = name.split("");

    String newName = "";
    boolean capitalizeNext = false;

    for (int i = 0; i < characters.length; i++)
    {
        String character = characters[i];

        if (capitalizeNext || i == 0)
        {
            newName += character.toUpperCase();
            capitalizeNext = false;
        }
        else
        {
            if (delimiters.contains(character)) capitalizeNext = true;
            newName += character;
        }
    }

    folder.renameTo(new File(folder.getParent() + File.separator + newName));
}

Use:

    String text = "jon skeet, miles o'brien, old mcdonald";

    Pattern pattern = Pattern.compile("\\b([a-z])([\\w]*)");
    Matcher matcher = pattern.matcher(text);
    StringBuffer buffer = new StringBuffer();
    while (matcher.find()) {
        matcher.appendReplacement(buffer, matcher.group(1).toUpperCase() + matcher.group(2));
    }
    String capitalized = matcher.appendTail(buffer).toString();
    System.out.println(capitalized);