Java中是否内置了一个函数，使字符串中每个单词的第一个字符大写，而不影响其他字符?
例子:
乔恩·斯基特->乔恩·斯基特 miles o'Brien -> miles o'Brien (B仍然是大写，这排除了Title Case) 老麦当劳->
*(老麦当劳也会被发现，但我不指望它有那么聪明。)
快速浏览一下Java字符串文档就会发现只有toUpperCase()和toLowerCase()，它们当然没有提供所需的行为。当然，谷歌的结果主要是这两个函数。它看起来像一个已经被发明出来的轮子，所以问一下也无妨，这样我以后就可以用它了。
当前回答
public static String toTitleCase(String word){
return Character.toUpperCase(word.charAt(0)) + word.substring(1);
}
public static void main(String[] args){
String phrase = "this is to be title cased";
String[] splitPhrase = phrase.split(" ");
String result = "";
for(String word: splitPhrase){
result += toTitleCase(word) + " ";
}
System.out.println(result.trim());
}
其他回答
String toBeCapped = "i want this sentence capitalized";
String[] tokens = toBeCapped.split("\\s");
toBeCapped = "";
for(int i = 0; i < tokens.length; i++){
char capLetter = Character.toUpperCase(tokens[i].charAt(0));
toBeCapped += " " + capLetter + tokens[i].substring(1);
}
toBeCapped = toBeCapped.trim();
试试这个:
private String capitalizer(String word){
String[] words = word.split(" ");
StringBuilder sb = new StringBuilder();
if (words[0].length() > 0) {
sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
for (int i = 1; i < words.length; i++) {
sb.append(" ");
sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
}
}
return sb.toString();
}
如果你只担心第一个单词的首字母大写:
private String capitalize(final String line) {
return Character.toUpperCase(line.charAt(0)) + line.substring(1);
}
这条适用于姓氏的情况……
使用不同类型的分隔符，并且它保持相同的分隔符:
jean-frederic -> jean-frederic jean frederic——> jean frederic
该代码与GWT客户端一起工作。
public static String capitalize (String givenString) {
String Separateur = " ,.-;";
StringBuffer sb = new StringBuffer();
boolean ToCap = true;
for (int i = 0; i < givenString.length(); i++) {
if (ToCap)
sb.append(Character.toUpperCase(givenString.charAt(i)));
else
sb.append(Character.toLowerCase(givenString.charAt(i)));
if (Separateur.indexOf(givenString.charAt(i)) >=0)
ToCap = true;
else
ToCap = false;
}
return sb.toString().trim();
}
s.toLowerCase().trim();
result += Character.toUpperCase(s.charAt(0));
result += s.substring(1, s.indexOf(" ") + 1);
s = s.substring(s.indexOf(" ") + 1);
do {
if (s.contains(" ")) {
result += " ";
result += Character.toUpperCase(s.charAt(0));
result += s.substring(1, s.indexOf(" "));
s = s.substring(s.indexOf(" ") + 1);
} else {
result += " ";
result += Character.toUpperCase(s.charAt(0));
result += s.substring(1);
break;
}
} while (true);
System.out.println(result);
