我最近发现onActivityResult已弃用。我们该怎么处理呢?
有什么替代方案吗?
我最近发现onActivityResult已弃用。我们该怎么处理呢?
有什么替代方案吗?
当前回答
在芬兰湾的科特林 我改变了我的代码
startActivityForResult(intent, Constants.MY_CODE_REQUEST)
and
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent) {
super.onActivityResult(requestCode, resultCode, data)
if (resultCode == Activity.RESULT_OK) {
when (requestCode) {
Constants.MY_CODE_REQUEST -> {
...
}
to
registerForActivityResult(StartActivityForResult()) { result ->
onActivityResult(Constants.MY_CODE_REQUEST, result)
}.launch(intent)
and
private fun onActivityResult(requestCode: Int, result: ActivityResult) {
if(result.resultCode == Activity.RESULT_OK) {
val intent = result.data
when (requestCode) {
Constants.MY_CODE_REQUEST -> {
...
我希望这对你有用。: D
其他回答
在替换已弃用的方法startActivityForResult(…)时,需要遵循4个简单的步骤。
In place of overridden method onActivityResult(..) - ActivityResultLauncher<Intent> activityResultLaunch = registerForActivityResult( new ActivityResultContracts.StartActivityForResult(), new ActivityResultCallback<ActivityResult>() { @Override public void onActivityResult(ActivityResult result) { if (result.getResultCode() == 123) { // ToDo : Do your stuff... } else if(result.getResultCode() == 321) { // ToDo : Do your stuff... } } });
对于多个自定义请求,将条件附加为
if (result.getResultCode() == 123) {
..
} else if(result.getResultCode() == 131){
..
} // so on..
Imports : import androidx.activity.result.ActivityResult; import androidx.activity.result.ActivityResultCallback; import androidx.activity.result.ActivityResultLauncher; import androidx.activity.result.contract.ActivityResultContracts; In place of startActivityForResult(intent, 123), use Intent intent = new Intent(this, SampleActivity.class); activityResultLaunch.launch(intent); In SampleActivity.java class, while returning back to source activity, code will remain the same like - Intent intent = new Intent(); setResult(123, intent); finish();
编码快乐!:)
我想出了如何从Kotlin的片段中正确地做到这一点,以捕获图像并处理返回的位图。在其他情况下也是一样的。
首先,您必须注册片段以侦听活动结果。这必须在初始化片段之前完成,这意味着创建一个成员变量,而不是在onCreate函数中初始化。
class DummyFragment : Fragment() {
//registering fragment for camera listener
private val takePhoto = registerForActivityResult(
ActivityResultContracts.StartActivityForResult()
) {
if (it.resultCode == Activity.RESULT_OK) {
val imageBitmap = it.data?.extras?.get("data") as Bitmap
// do your thing with the obtained bitmap
}
}
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
}
}
然后,像你通常做的那样调用摄像机意图。并使用上面创建的变量来启动意图。
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
someRandomButton.setOnClickListener {
val takePictureIntent = Intent(MediaStore.ACTION_IMAGE_CAPTURE)
takePhoto.launch(takePictureIntent)
}
}
startActivityForResult和onActivityResult在android 10 API 30中已弃用,现在我们有了一种新的方法来使用registerForActivityResult来获得结果
resultContract =
registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { result ->
if (result.resultCode == Activity.RESULT_OK) {
// There are no request codes
val country = result.data?.getParcelableExtra<Country>("Country")
showLiveDemoDialogue(country)
}
}
并启动活动
val intent = Intent(this, CountriesListActivity::class.java)
resultContract.launch(intent)
但你应该在呼叫发射前注册然后发射到你想去的任何地方。 否则,您将得到这个异常
attempting to register while current state is RESUMED. LifecycleOwners must call register before they are STARTED.
onActivityResult, startActivityForResult, requestPermissions和onRequestPermissionsResult从1.3.0-alpha04开始在androidx.fragment上被弃用,android.app.Activity上没有。 相反,你可以使用registerForActivityResult的活动结果api。
在我的情况下,我试图使用意图,我直接移动到下一个活动,而不使用谷歌登录。
对我有用的是:
在OnCreate中为登录按钮设置onClickListener:
btnSignIn.setOnClickListener {
signIn()
}
private fun signIn() {
val intent = client.signInIntent
mainActivityResultLauncher.launch(intent)
}
在上面的代码中,我写了去下一个活动的意图,但我必须写client.signInIntent
var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->
if(result.resultCode == Activity.RESULT_OK){
val data = result.data
val task = GoogleSignIn.getSignedInAccountFromIntent(data)
try {
// Google Sign In was successful, authenticate with Firebase
val account = task.getResult(ApiException::class.java)!!
Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
firebaseAuthWithGoogle(account.idToken!!)
} catch (e: ApiException) {
// Google Sign In failed, update UI appropriately
Log.w(TAG, "Google sign in failed", e)
}
}
}