我想知道如何使键盘消失时,用户触摸以外的UITextField。


当前回答

我拼凑了几个答案。

使用一个在viewDidLoad期间初始化的ivar:

UIGestureRecognizer *tapper;

- (void)viewDidLoad
{
    [super viewDidLoad];
    tapper = [[UITapGestureRecognizer alloc]
                initWithTarget:self action:@selector(handleSingleTap:)];
    tapper.cancelsTouchesInView = NO;
    [self.view addGestureRecognizer:tapper];
}

删除当前正在编辑的内容:

- (void)handleSingleTap:(UITapGestureRecognizer *) sender
{
    [self.view endEditing:YES];
}

其他回答

我发现有些人在使用UITapGestureRecognizer方法时遇到了问题。我在保持现有按钮点击行为不变的情况下完成这一功能的最简单方法是只添加一行到@Jensen2k的答案:

[tap setCancelsTouchesInView:NO];

这使得我现有的按钮仍然可以工作,而不需要使用@Dmitry Sitnikov的方法。

在这里阅读有关属性(搜索CancelsTouchesInView): UIGestureRecognizer类引用

我不确定它将如何与滚动条一起工作,因为我看到有些人有问题,但希望其他人可能会遇到与我相同的情况。

@Jensen2k回答的Swift版本:

let gestureRecognizer : UITapGestureRecognizer = UITapGestureRecognizer.init(target: self, action: "dismissKeyboard")
self.view.addGestureRecognizer(gestureRecognizer)

func dismissKeyboard() {
    aTextField.resignFirstResponder()
}

一个衬套

self.view.addTapGesture(UITapGestureRecognizer.init(target: self, action: "endEditing:"))

有一件事很重要……

添加手势识别到视图可以覆盖它的子视图。 所以只执行一个动作。 如果你想通过父视图和子视图执行多重识别操作… 你必须使用

 tap.cancelsTouchesInView = false

完整代码如下:

 let tap = UITapGestureRecognizer(target: self, action: #selector(self.superViewClicked))
        tap.numberOfTapsRequired = 1
        tap.delegate = self
        tap.cancelsTouchesInView = false
        self.view.addGestureRecognizer(tap)




  @objc func superViewClicked(){
        
        self.searchTF.resignFirstResponder()
    }

在外面点击关闭软键盘的最佳解决方案是什么?

我将解释一个条件:

想想看:你在顶部有UISearchBar, 然后添加头表视图!

解决方法很简单:

跟踪软键盘打开或关闭 添加手势识别头视图 实现表视图didSelectRowAt的委托

完整的代码:

   var isSoftKeyboardActive = false

    override func viewDidLoad() {
    
    
        var tap = UITapGestureRecognizer(target: self, action: #selector(self.tableHeaderClick))
            tap.numberOfTapsRequired = 1
            tap.delegate = self
            tap.cancelsTouchesInView = false
            self.headerOfTableView.addGestureRecognizer(tap)
    
    }
    
          override func viewWillAppear(_ animated: Bool) {
                  super.viewWillAppear(animated)
                 NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillDisappear), name: UIResponder.keyboardWillHideNotification, object: nil)
                  NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillAppear), name: UIResponder.keyboardWillShowNotification, object: nil)
              }
              
              override func viewWillDisappear(_ animated: Bool) {
                  super.viewWillDisappear(animated)
                  NotificationCenter.default.removeObserver(self)
              }
        


    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
          if isSoftKeyboardActive == true{
               
               self.searchTF.resignFirstResponder()
           }else{
           
               selectedRow = indexPath.row
               performSegue(withIdentifier: "segueWebview", sender: self)
               
           }
    }
    


 
    @objc func tableHeaderClick(){
         
        self.searchTF.resignFirstResponder()
    
     }
    
    
    
  @objc func keyboardWillAppear() {

        
        isSoftKeyboardActive = true
    }

    @objc func keyboardWillDisappear() {
        
        isSoftKeyboardActive = false
        
    }
 

它是如何工作的:

如果软键盘是打开的,用户点击头软键盘关闭 如果软键盘打开,用户点击单元格,键盘关闭,不执行单元格点击

只是在这里添加我的版本如何在外部触摸时取消键盘。

viewDidLoad:

UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleSingleTap:)];
[self.view addGestureRecognizer:singleTap];

在任何地方:

-(void)handleSingleTap:(UITapGestureRecognizer *)sender{
    [textFieldName resignFirstResponder];
    puts("Dismissed the keyboard");
}

objective - c:

在ViewController中添加这段代码。M文件:

-(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    [self.view endEditing:YES];
}

迅速:

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    view.endEditing(true)
}