这一定是通过触摸外部隐藏键盘的最简单方法:

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    [self.view endEditing:YES];    
}

(从如何解散键盘时，用户点击其他区域以外的文本框?)

在swift 5中，你可以使用以下代码来解除文本域外的键盘

override func viewDidLoad() {
    // ... code

    let tapGesture = UITapGestureRecognizer(target: self, action: #selector(self.dismissKeyboard(_:)))
    self.view.addGestureRecognizer(tapGesture)  
}

@objc func dismissKeyboard(_ sender: UITapGestureRecognizer) {
    self.view.endEditing(true)
}

- (void)viewDidLoad
{
    [super viewDidLoad]; 

UITapGestureRecognizer *singleTapGestureRecognizer = [[UITapGestureRecognizer alloc]
                                                          initWithTarget:self
                                                          action:@selector(handleSingleTap:)];
    [singleTapGestureRecognizer setNumberOfTapsRequired:1];
    [singleTapGestureRecognizer requireGestureRecognizerToFail:singleTapGestureRecognizer];

    [self.view addGestureRecognizer:singleTapGestureRecognizer];
}

- (void)handleSingleTap:(UITapGestureRecognizer *)recognizer
{
    [self.view endEditing:YES];
    [textField resignFirstResponder];
    [scrollView setContentOffset:CGPointMake(0, -40) animated:YES];

}

有一件事很重要……

添加手势识别到视图可以覆盖它的子视图。 所以只执行一个动作。 如果你想通过父视图和子视图执行多重识别操作… 你必须使用

 tap.cancelsTouchesInView = false

完整代码如下:

 let tap = UITapGestureRecognizer(target: self, action: #selector(self.superViewClicked))
        tap.numberOfTapsRequired = 1
        tap.delegate = self
        tap.cancelsTouchesInView = false
        self.view.addGestureRecognizer(tap)




  @objc func superViewClicked(){
        
        self.searchTF.resignFirstResponder()
    }

在外面点击关闭软键盘的最佳解决方案是什么?

我将解释一个条件:

想想看:你在顶部有UISearchBar， 然后添加头表视图!

解决方法很简单:

跟踪软键盘打开或关闭 添加手势识别头视图 实现表视图didSelectRowAt的委托

完整的代码:

   var isSoftKeyboardActive = false

    override func viewDidLoad() {
    
    
        var tap = UITapGestureRecognizer(target: self, action: #selector(self.tableHeaderClick))
            tap.numberOfTapsRequired = 1
            tap.delegate = self
            tap.cancelsTouchesInView = false
            self.headerOfTableView.addGestureRecognizer(tap)
    
    }
    
          override func viewWillAppear(_ animated: Bool) {
                  super.viewWillAppear(animated)
                 NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillDisappear), name: UIResponder.keyboardWillHideNotification, object: nil)
                  NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillAppear), name: UIResponder.keyboardWillShowNotification, object: nil)
              }
              
              override func viewWillDisappear(_ animated: Bool) {
                  super.viewWillDisappear(animated)
                  NotificationCenter.default.removeObserver(self)
              }
        


    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
          if isSoftKeyboardActive == true{
               
               self.searchTF.resignFirstResponder()
           }else{
           
               selectedRow = indexPath.row
               performSegue(withIdentifier: "segueWebview", sender: self)
               
           }
    }
    


 
    @objc func tableHeaderClick(){
         
        self.searchTF.resignFirstResponder()
    
     }
    
    
    
  @objc func keyboardWillAppear() {

        
        isSoftKeyboardActive = true
    }

    @objc func keyboardWillDisappear() {
        
        isSoftKeyboardActive = false
        
    }
 

它是如何工作的:

如果软键盘是打开的，用户点击头软键盘关闭 如果软键盘打开，用户点击单元格，键盘关闭，不执行单元格点击

我认为最简单(最好)的方法是子类化全局视图，并使用hitTest:withEvent方法来监听任何触摸。键盘上的触摸没有注册，所以hitTest:withEvent只在你触摸/滚动/滑动/捏…然后调用[self - ending:YES]。

这比使用touchesBegan要好，因为如果你点击视图顶部的按钮，touchesBegan不会被调用。它比无法识别滚动手势的UITapGestureRecognizer更好。它也比使用暗屏更好，因为在复杂和动态的用户界面中，你不能到处都放暗屏。此外，它不会阻止其他动作，你不需要点击两次来选择外面的按钮(就像在UIPopover的情况下)。

此外，这比调用[textField resignFirstResponder]更好，因为你可能在屏幕上有许多文本字段，所以这适用于所有的文本字段。

override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent) {
    super.view.endEditing(true)
    super.touchesBegan(touches, withEvent: event)
}