这是一个很好的通用解决方案:

objective - c:

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    [self.view endEditing:YES];    
}

迅速:

override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
    self.view.endEditing(true)
}

基于@icodebuster解决方案:https://stackoverflow.com/a/18756253/417652

只是在这里添加我的版本如何在外部触摸时取消键盘。

viewDidLoad:

UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleSingleTap:)];
[self.view addGestureRecognizer:singleTap];

在任何地方:

-(void)handleSingleTap:(UITapGestureRecognizer *)sender{
    [textFieldName resignFirstResponder];
    puts("Dismissed the keyboard");
}

有一件事很重要……

添加手势识别到视图可以覆盖它的子视图。 所以只执行一个动作。 如果你想通过父视图和子视图执行多重识别操作… 你必须使用

 tap.cancelsTouchesInView = false

完整代码如下:

 let tap = UITapGestureRecognizer(target: self, action: #selector(self.superViewClicked))
        tap.numberOfTapsRequired = 1
        tap.delegate = self
        tap.cancelsTouchesInView = false
        self.view.addGestureRecognizer(tap)




  @objc func superViewClicked(){
        
        self.searchTF.resignFirstResponder()
    }

在外面点击关闭软键盘的最佳解决方案是什么?

我将解释一个条件:

想想看:你在顶部有UISearchBar， 然后添加头表视图!

解决方法很简单:

跟踪软键盘打开或关闭 添加手势识别头视图 实现表视图didSelectRowAt的委托

完整的代码:

   var isSoftKeyboardActive = false

    override func viewDidLoad() {
    
    
        var tap = UITapGestureRecognizer(target: self, action: #selector(self.tableHeaderClick))
            tap.numberOfTapsRequired = 1
            tap.delegate = self
            tap.cancelsTouchesInView = false
            self.headerOfTableView.addGestureRecognizer(tap)
    
    }
    
          override func viewWillAppear(_ animated: Bool) {
                  super.viewWillAppear(animated)
                 NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillDisappear), name: UIResponder.keyboardWillHideNotification, object: nil)
                  NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillAppear), name: UIResponder.keyboardWillShowNotification, object: nil)
              }
              
              override func viewWillDisappear(_ animated: Bool) {
                  super.viewWillDisappear(animated)
                  NotificationCenter.default.removeObserver(self)
              }
        


    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
          if isSoftKeyboardActive == true{
               
               self.searchTF.resignFirstResponder()
           }else{
           
               selectedRow = indexPath.row
               performSegue(withIdentifier: "segueWebview", sender: self)
               
           }
    }
    


 
    @objc func tableHeaderClick(){
         
        self.searchTF.resignFirstResponder()
    
     }
    
    
    
  @objc func keyboardWillAppear() {

        
        isSoftKeyboardActive = true
    }

    @objc func keyboardWillDisappear() {
        
        isSoftKeyboardActive = false
        
    }
 

它是如何工作的:

如果软键盘是打开的，用户点击头软键盘关闭 如果软键盘打开，用户点击单元格，键盘关闭，不执行单元格点击

看看这个，这是最简单的方法，

-(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{
      [self.view endEditing:YES];// this will do the trick
}

Or

这个库将处理包括滚动条自动滚动，点击空间隐藏键盘等…

https://github.com/michaeltyson/TPKeyboardAvoiding

在viewDidLoad 斯威夫特4.2 代码是这样的

let viewTap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action:#selector(dismissKeyboard))
        view.addGestureRecognizer(viewTap)
@objc func dismissKeyboard() {
        view.endEditing(true)
    }

如果我得到你的权利，你想辞职键盘狡猾敲在文本字段之外，但你没有你的文本字段的引用。

试试这个;

Take global textField, lets call it reftextField Now in textFieldDidBeginEditing set referenced text field to - (void) textFieldDidBeginEditing:(UITextField *)textField{ reftextField = textField; } Now you can happily use on any button clock, (adding a transparent button on begin editing recomended) - (void)dismissKeyboard { [reftextField resignFirstResponder]; } Or for resigning done button try this. //for resigning on done button - (BOOL) textFieldShouldReturn:(UITextField *)textField{ [textField resignFirstResponder]; return YES; }