这是一个简单的纯JavaScript解决方案，适用于目标数字(值为scrollTop)，目标DOM元素，或一些特殊的字符串情况:

/**
 * target - target to scroll to (DOM element, scrollTop Number, 'top', or 'bottom'
 * containerEl - DOM element for the container with scrollbars
 */
var scrollToTarget = function(target, containerEl) {
    // Moved up here for readability:
    var isElement = target && target.nodeType === 1,
        isNumber = Object.prototype.toString.call(target) === '[object Number]';

    if (isElement) {
        containerEl.scrollTop = target.offsetTop;
    } else if (isNumber) {
        containerEl.scrollTop = target;
    } else if (target === 'bottom') {
        containerEl.scrollTop = containerEl.scrollHeight - containerEl.offsetHeight;
    } else if (target === 'top') {
        containerEl.scrollTop = 0;
    }
};

下面是一些用法的例子:

// Scroll to the top
var scrollableDiv = document.getElementById('scrollable_div');
scrollToTarget('top', scrollableDiv);

or

// Scroll to 200px from the top
var scrollableDiv = document.getElementById('scrollable_div');
scrollToTarget(200, scrollableDiv);

or

// Scroll to targetElement
var scrollableDiv = document.getElementById('scrollable_div');
var targetElement= document.getElementById('target_element');
scrollToTarget(targetElement, scrollableDiv);

其他答案都不能解决我的问题。

我摆弄了scrollIntoView参数，并设法找到了一个解决方案。将inline设置为开始并将block设置为最近的位置，以防止父元素(或整个页面)滚动:

document.getElementById(chr).scrollIntoView({
   behavior: 'smooth',
   block: 'nearest',
   inline: 'start'
});

这就是我最终得到的

/** Set parent scroll to show element
 * @param element {object} The HTML object to show
 * @param parent {object} The HTML object where the element is shown  */
var scrollToView = function(element, parent) {
    //Algorithm: Accumulate the height of the previous elements and add half the height of the parent
    var offsetAccumulator = 0;
    parent = $(parent);
    parent.children().each(function() {
        if(this == element) {
            return false; //brake each loop
        }
        offsetAccumulator += $(this).innerHeight();
    });
    parent.scrollTop(offsetAccumulator - parent.innerHeight()/2);
}

我需要滚动页面上的动态加载元素，所以我的解决方案有点复杂。

这将适用于静态元素，这些静态元素不是惰性加载数据，也不是动态加载数据。

const smoothScrollElement = async (selector: string, scrollBy = 12, prevCurrPos = 0) => {
    const wait = (timeout: number) => new Promise(resolve => setTimeout(resolve, timeout));
    const el = document.querySelector(selector) as HTMLElement;
    let positionToScrollTo = el.scrollHeight;
    let currentPosition = Math.floor(el.scrollTop) || 0;
    let pageYOffset = (el.clientHeight + currentPosition);
    if (positionToScrollTo == pageYOffset) {
        await wait(1000);
    }
    if ((prevCurrPos > 0 && currentPosition <= prevCurrPos) !== true) {
        setTimeout(async () => {
            el.scrollBy(0, scrollBy);
            await smoothScrollElement(selector, scrollBy, currentPosition);
        }, scrollBy);
    }
};

如果你正在使用jQuery，你可以使用以下命令滚动动画:

$(MyContainerDiv).animate({scrollTop: $(MyContainerDiv).scrollTop() + ($('element_within_div').offset().top - $(MyContainerDiv).offset().top)});

动画是可选的:你也可以把上面计算出来的scrollTop值直接放到容器的scrollTop属性中。

代码应该是:

var divElem = document.getElementById('scrolling_div');
var chElem = document.getElementById('element_within_div');
var topPos = divElem.offsetTop;
divElem.scrollTop = topPos - chElem.offsetTop;

您希望滚动子顶部位置和div顶部位置之间的差值。

使用以下方法访问子元素:

var divElem = document.getElementById('scrolling_div'); 
var numChildren = divElem.childNodes.length;

等等....