这对我很有效

f = open("history_export.csv", "r")
line= 5
for x in range(line):
    a = f.readline()
    print(a)

Python 3:

with open("datafile") as myfile:
    head = [next(myfile) for x in range(N)]
print(head)

Python 2:

with open("datafile") as myfile:
    head = [next(myfile) for x in xrange(N)]
print head

下面是另一种方法(Python 2和3都是):

from itertools import islice

with open("datafile") as myfile:
    head = list(islice(myfile, N))
print(head)

我自己最方便的方法:

LINE_COUNT = 3
print [s for (i, s) in enumerate(open('test.txt')) if i < LINE_COUNT]

基于列表理解的解决方案 函数open()支持迭代接口。enumerate()包含open()和return元组(index, item)，然后检查是否在可接受的范围内(如果i < LINE_COUNT)，然后简单地打印结果。

欣赏Python。；）

对于前5行，简单地做:

N=5
with open("data_file", "r") as file:
    for i in range(N):
       print file.next()

没有特定的方法来读取文件对象暴露的行数。

我想最简单的方法是:

lines =[]
with open(file_name) as f:
    lines.extend(f.readline() for i in xrange(N))

使用list(file_data)将CSV文件对象转换为列表

import csv;
with open('your_csv_file.csv') as file_obj:
    file_data = csv.reader(file_obj);
    file_list = list(file_data)
    for row in file_list[:4]:
        print(row)