我有一个UIView并且我添加了点击手势
let tap = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
tap.delegate = self
myView.addGesture(tap)
我试图在testfile中以编程方式调用它。
sendActionForEvent
我正在使用这个函数，但它不起作用:
myView.sendActionForEvent(UIEvents.touchUpDown)
它显示未识别的选择器发送到实例。
我该如何解决这个问题呢?
当前回答
这是它在Swift 3中的工作原理:
@IBOutlet var myView: UIView!
override func viewDidLoad() {
super.viewDidLoad()
let tap = UITapGestureRecognizer(target: self, action:#selector(handleTap))
myView.addGestureRecognizer(tap)
}
func handleTap() {
print("tapped")
}
其他回答
你需要用目标和动作初始化UITapGestureRecognizer，如下所示:
let tap = UITapGestureRecognizer(target: self, action: "handleTap:")
tap.delegate = self
myView.addGestureRecognizer(tap)
然后，你应该实现处理程序，它将在每次tap事件发生时被调用:
func handleTap(sender: UITapGestureRecognizer) {
// handling code
}
let tap = UITapGestureRecognizer(target: self, action: Selector("handleFrontTap:"))
frontView.addGestureRecognizer(tap)
// Make sure this is not private
func handleFrontTap(gestureRecognizer: UITapGestureRecognizer) {
print("tap working")
}
我使用的是Xcode 7.3.1, Swift 2.2。见下文。
func addTapGesture() {
let tap = UITapGestureRecognizer(target: self, action: #selector(MyViewController.handleTap))
tap.numberOfTapsRequired = 1
self.myView.addGestureRecognizer(tap)
}
func handleTap() {
// Your code here...
}
Swift 4的完整答案
步骤1:为视图创建一个出口
@IBOutlet weak var rightViewOutlet: UIView!
步骤2:定义一个点击手势
var tapGesture = UITapGestureRecognizer()
步骤3:创建ObjC函数(当视图被点击时调用)
@objc func rightViewTapped(_ recognizer: UIGestureRecognizer) {
print("Right button is tapped")
}
步骤4:在viewDidLoad()中添加以下内容
let rightTap = UITapGestureRecognizer(target: self, action: #selector(ViewController.rightViewTapped(_:)))
rightViewOutlet.addGestureRecognizer(rightTap)
注意:不要忘记在视图上启用交互:
let tap = UITapGestureRecognizer(target: self, action: #selector(handleTap))
view.addGestureRecognizer(tap)
// view.userInteractionEnabled = true
self.view.addSubview(view)
