另一种可能是使用内置的http.client:

from http import HTTPStatus, client
from shutil import copyfileobj

# using https
connection = client.HTTPSConnection("www.example.com")
with connection.request("GET", "/noise.mp3") as response:
    if response.status == HTTPStatus.OK:
        copyfileobj(response, open("noise.mp3")
    else:
        raise Exception("request needs work")

HTTPConnection对象被认为是“低级的”，因为它只执行一次所需的请求，并假设开发人员将对它或脚本进行子类化，以处理HTTP的细微差别。诸如请求之类的库倾向于处理更特殊的情况，例如自动跟随重定向等等。

你可以使用python请求

import os
import requests


outfile = os.path.join(SAVE_DIR, file_name)
response = requests.get(URL, stream=True)
with open(outfile,'wb') as output:
  output.write(response.content)

你可以使用shutil

import os
import requests
import shutil
 
outfile = os.path.join(SAVE_DIR, file_name)
response = requests.get(url, stream = True)
with open(outfile, 'wb') as f:
  shutil.copyfileobj(response.content, f)

如果你从受限的url下载，不要忘记在标题中包含访问令牌

Python 2/3的PabloG代码的改进版本:

#!/usr/bin/env python
# -*- coding: utf-8 -*-
from __future__ import ( division, absolute_import, print_function, unicode_literals )

import sys, os, tempfile, logging

if sys.version_info >= (3,):
    import urllib.request as urllib2
    import urllib.parse as urlparse
else:
    import urllib2
    import urlparse

def download_file(url, dest=None):
    """ 
    Download and save a file specified by url to dest directory,
    """
    u = urllib2.urlopen(url)

    scheme, netloc, path, query, fragment = urlparse.urlsplit(url)
    filename = os.path.basename(path)
    if not filename:
        filename = 'downloaded.file'
    if dest:
        filename = os.path.join(dest, filename)

    with open(filename, 'wb') as f:
        meta = u.info()
        meta_func = meta.getheaders if hasattr(meta, 'getheaders') else meta.get_all
        meta_length = meta_func("Content-Length")
        file_size = None
        if meta_length:
            file_size = int(meta_length[0])
        print("Downloading: {0} Bytes: {1}".format(url, file_size))

        file_size_dl = 0
        block_sz = 8192
        while True:
            buffer = u.read(block_sz)
            if not buffer:
                break

            file_size_dl += len(buffer)
            f.write(buffer)

            status = "{0:16}".format(file_size_dl)
            if file_size:
                status += "   [{0:6.2f}%]".format(file_size_dl * 100 / file_size)
            status += chr(13)
            print(status, end="")
        print()

    return filename

if __name__ == "__main__":  # Only run if this file is called directly
    print("Testing with 10MB download")
    url = "http://download.thinkbroadband.com/10MB.zip"
    filename = download_file(url)
    print(filename)

另一种可能是使用内置的http.client:

from http import HTTPStatus, client
from shutil import copyfileobj

# using https
connection = client.HTTPSConnection("www.example.com")
with connection.request("GET", "/noise.mp3") as response:
    if response.status == HTTPStatus.OK:
        copyfileobj(response, open("noise.mp3")
    else:
        raise Exception("request needs work")

HTTPConnection对象被认为是“低级的”，因为它只执行一次所需的请求，并假设开发人员将对它或脚本进行子类化，以处理HTTP的细微差别。诸如请求之类的库倾向于处理更特殊的情况，例如自动跟随重定向等等。

基于urllib3的新Api实现

>>> import urllib3
>>> http = urllib3.PoolManager()
>>> r = http.request('GET', 'your_url_goes_here')
>>> r.status
   200
>>> r.data
   *****Response Data****

更多信息:https://pypi.org/project/urllib3/

Urlretrieve和请求。得到的都很简单，然而现实却不。 我已经为两个站点提取了数据，包括文本和图像，以上两个可能解决了大部分任务。但如果想要更通用的解决方案，我建议使用urlopen。由于它包含在Python 3标准库中，您的代码可以在任何运行Python 3的机器上运行，而无需预先安装site-package

import urllib.request
url_request = urllib.request.Request(url, headers=headers)
url_connect = urllib.request.urlopen(url_request)

#remember to open file in bytes mode
with open(filename, 'wb') as f:
    while True:
        buffer = url_connect.read(buffer_size)
        if not buffer: break

        #an integer value of size of written data
        data_wrote = f.write(buffer)

#you could probably use with-open-as manner
url_connect.close()

当使用Python通过HTTP下载文件时，这个答案提供了HTTP 403禁止的解决方案。我只尝试了请求和urllib模块，其他模块可能会提供更好的东西，但这是我用来解决大多数问题的一个。