正如PEP8所建议的那样,在python程序中保持低于80列的规则,对于长字符串,我怎么能遵守这个规则呢?

s = "this is my really, really, really, really, really, really, really long string that I'd like to shorten."

我该如何把它扩展到下面一行呢?

s = "this is my really, really, really, really, really, really" + 
    "really long string that I'd like to shorten."

当前回答

message = f"Variable : child({type(child)}) -> is not of"\
        " type Node."

这个语法适合我。注意第二个语句的缩进,它应该缩进正确。

其他回答

使用黑色[https://github.com/psf/black],我像这样格式化它。

   help=f"""filters, lista de filtros para cargar las base de conocimiento.
   Pueden mandarse solo algunos filtros ya que no son obligatorios,
   por ejemplo, si no se manda sts, se cargarán todos las bases de todos los estados.""",

您丢失了一个空格,您可能需要一个行延续字符,即。一个\。

s = "this is my really, really, really, really, really, really" +  \
    " really long string that I'd like to shorten."

甚至:

s = "this is my really, really, really, really, really, really"  \
    " really long string that I'd like to shorten."

parns也可以代替行续符,但可能会有人认为您打算使用元组,而只是忘记了逗号。举个例子:

s = ("this is my really, really, really, really, really, really"
    " really long string that I'd like to shorten.")

对比:

s = ("this is my really, really, really, really, really, really",
    " really long string that I'd like to shorten.")

使用Python的动态类型,代码可以以任何一种方式运行,但会产生不正确的结果。

我倾向于使用几个这里没有提到的方法来指定大字符串,但这些方法适用于非常特定的场景。YMMV……

Multi-line blobs of text, often with formatted tokens (not quite what you were asking, but still useful): error_message = ''' I generally like to see how my helpful, sometimes multi-line error messages will look against the left border. '''.strip() Grow the variable piece-by-piece through whatever string interpolation method you prefer: var = 'This is the start of a very,' var = f'{var} very long string which could' var = f'{var} contain a ridiculous number' var = f'{var} of words.' Read it from a file. PEP-8 doesn't limit the length of strings in a file; just the lines of your code. :) Use brute-force or your editor to split the string into managaeble lines using newlines, and then remove all newlines. (Similar to the first technique I listed): foo = ''' agreatbigstringthatyoudonotwanttohaveanyne wlinesinbutforsomereasonyouneedtospecifyit verbatimintheactualcodejustlikethis '''.replace('\n', '')

我以前用过textwrap.dedent。这有点麻烦,所以我现在更喜欢行延续,但如果你真的想要块缩进,我认为这很好。

示例代码(其中trim是去掉带有切片的第一个'\n'):

import textwrap as tw
x = """\
       This is a yet another test.
       This is only a test"""
print(tw.dedent(x))

解释:

Dedent根据新行前第一行文本中的空白计算缩进。如果你想调整它,你可以使用re模块轻松地重新实现它。

这种方法有局限性,很长的行可能仍然比你想要的长,在这种情况下,其他方法连接字符串更适合。

如果你必须插入一个长字符串文字,并希望flake8关闭,你可以使用它的关闭指令。例如,在一个测试例程中,我定义了一些假的CSV输入。我发现把它分成更多行会非常混乱,所以我决定添加一个# noqa: E501,如下所示:

csv_test_content = """"STATION","DATE","SOURCE","LATITUDE","LONGITUDE","ELEVATION","NAME","REPORT_TYPE","CALL_SIGN","QUALITY_CONTROL","WND","CIG","VIS","TMP","DEW","SLP","AA1","AA2","AY1","AY2","GF1","MW1","REM"
"94733099999","2019-01-03T22:00:00","4","-32.5833333","151.1666666","45.0","SINGLETON STP, AS","FM-12","99999","V020","050,1,N,0010,1","22000,1,9,N","025000,1,9,9","+0260,1","+0210,1","99999,9","24,0000,9,1",,"0,1,02,1","0,1,02,1","01,99,1,99,9,99,9,99999,9,99,9,99,9","01,1","SYN05294733 11/75 10502 10260 20210 60004 70100 333 70000="
"94733099999","2019-01-04T04:00:00","4","-32.5833333","151.1666666","45.0","SINGLETON STP, AS","FM-12","99999","V020","090,1,N,0021,1","22000,1,9,N","025000,1,9,9","+0378,1","+0172,1","99999,9","06,0000,9,1",,"0,1,02,1","0,1,02,1","03,99,1,99,9,99,9,99999,9,99,9,99,9","03,1","SYN04294733 11/75 30904 10378 20172 60001 70300="
"94733099999","2019-01-04T22:00:00","4","-32.5833333","151.1666666","45.0","SINGLETON STP, AS","FM-12","99999","V020","290,1,N,0057,1","99999,9,9,N","020000,1,9,9","+0339,1","+0201,1","99999,9","24,0000,9,1",,"0,1,02,1","0,1,02,1",,"02,1","SYN05294733 11970 02911 10339 20201 60004 70200 333 70000="
"94733099999","2019-01-05T22:00:00","4","-32.5833333","151.1666666","45.0","SINGLETON STP, AS","FM-12","99999","V020","200,1,N,0026,1","99999,9,9,N","000100,1,9,9","+0209,1","+0193,1","99999,9","24,0004,3,1",,"1,1,02,1","1,1,02,1","08,99,1,99,9,99,9,99999,9,99,9,99,9","51,1","SYN05294733 11/01 82005 10209 20193 69944 75111 333 70004="
"94733099999","2019-01-08T04:00:00","4","-32.5833333","151.1666666","45.0","SINGLETON STP, AS","FM-12","99999","V020","070,1,N,0026,1","22000,1,9,N","025000,1,9,9","+0344,1","+0213,1","99999,9","06,0000,9,1",,"2,1,02,1","2,1,02,1","04,99,1,99,9,99,9,99999,9,99,9,99,9","02,1","SYN04294733 11/75 40705 10344 20213 60001 70222="
"""  # noqa: E501