隐式连接可能是最干净的解决方案:

s = "this is my really, really, really, really, really, really," \
    " really long string that I'd like to shorten."

编辑经过反思，我同意托德的建议，使用括号而不是行接续更好，因为他给出了所有的理由。我唯一的犹豫是，用括号括起来的字符串和元组比较容易混淆。

可用的选项:

反斜杠:"foo" \ "bar" "foo" + " \ "bar" 括号: (“foo”“酒吧”) 带加号的括号:("foo" + "bar") PEP8, E502:括号之间的反斜杠是多余的

避免

避免使用逗号:("foo"， "bar")来定义一个元组。

>>> s = "a" \
... "b"
>>> s
'ab'
>>> type(s)
<class 'str'>

>>> s = "a" + \
... "b"
>>> s
'ab'
>>> type(s)
<class 'str'>

>>> s = ("a"
... "b")
>>> type(s)
<class 'str'>
>>> print(s)
ab

>>> s = ("a",
... "b")
>>> type(s)
<class 'tuple'>

>>> s = ("a" + 
... "b")
>>> type(s)
<class 'str'>
>>> print(s)
ab
>>> 

我以前用过textwrap.dedent。这有点麻烦，所以我现在更喜欢行延续，但如果你真的想要块缩进，我认为这很好。

示例代码(其中trim是去掉带有切片的第一个'\n'):

import textwrap as tw
x = """\
       This is a yet another test.
       This is only a test"""
print(tw.dedent(x))

解释:

Dedent根据新行前第一行文本中的空白计算缩进。如果你想调整它，你可以使用re模块轻松地重新实现它。

这种方法有局限性，很长的行可能仍然比你想要的长，在这种情况下，其他方法连接字符串更适合。

使用\你可以将语句扩展到多行:

s = "this is my really, really, really, really, really, really" + \
"really long string that I'd like to shorten."

应该工作。

反斜杠:

s = "this is my really, really, really, really, really, really" +  \
    "really long string that I'd like to shorten."

或者用括号括起来:

s = ("this is my really, really, really, really, really, really" + 
    "really long string that I'd like to shorten.")

隐式连接可能是最干净的解决方案:

s = "this is my really, really, really, really, really, really," \
    " really long string that I'd like to shorten."

编辑经过反思，我同意托德的建议，使用括号而不是行接续更好，因为他给出了所有的理由。我唯一的犹豫是，用括号括起来的字符串和元组比较容易混淆。