我试图写一个脚本,将完全清空SQL Server数据库。这是我目前所拥有的:

USE [dbname]
GO
EXEC sp_msforeachtable 'ALTER TABLE ? NOCHECK CONSTRAINT all'
EXEC sp_msforeachtable 'DELETE ?'

当我在管理工作室运行它时,我得到:

命令执行成功。

但当我刷新表列表时,它们都还在那里。我做错了什么?


当前回答

如果删除整个数据库,然后重新创建它呢?这对我很有用。

DROP DATABASE mydb;
CREATE DATABASE mydb;

其他回答

你差不多说对了,可以用:

EXEC sp_msforeachtable 'ALTER TABLE ? NOCHECK CONSTRAINT all'
EXEC sp_msforeachtable 'DROP TABLE ?'

但是第二行你可能需要执行不止一次,直到你停止得到错误:

Could not drop object 'dbo.table' because it is referenced by a FOREIGN KEY constraint.

信息:

Command(s) completed successfully.

表示已成功删除所有表。

sp_msforeachtable在Azure SQL中不可用

对于Azure SQL:

此查询将删除外键约束

DECLARE @Name VARCHAR(200)
DECLARE @Constraint VARCHAR(300)
DECLARE @SQL VARCHAR(300)

SELECT @Name = (SELECT TOP 1 TABLE_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE constraint_catalog=DB_NAME() AND CONSTRAINT_TYPE = 'FOREIGN KEY' ORDER BY TABLE_NAME)

WHILE @Name is not null
BEGIN
    SELECT @Constraint = (SELECT TOP 1 CONSTRAINT_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE constraint_catalog=DB_NAME() AND CONSTRAINT_TYPE = 'FOREIGN KEY' AND TABLE_NAME = @Name ORDER BY CONSTRAINT_NAME)
    WHILE @Constraint IS NOT NULL
    BEGIN
        SELECT @SQL = 'ALTER TABLE [dbo].[' + RTRIM(@Name) +'] DROP CONSTRAINT [' + RTRIM(@Constraint) +']'
        EXEC (@SQL)
        PRINT 'Dropped FK Constraint: ' + @Constraint + ' on ' + @Name
        SELECT @Constraint = (SELECT TOP 1 CONSTRAINT_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE constraint_catalog=DB_NAME() AND CONSTRAINT_TYPE = 'FOREIGN KEY' AND CONSTRAINT_NAME <> @Constraint AND TABLE_NAME = @Name ORDER BY CONSTRAINT_NAME)
    END
SELECT @Name = (SELECT TOP 1 TABLE_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE constraint_catalog=DB_NAME() AND CONSTRAINT_TYPE = 'FOREIGN KEY' ORDER BY TABLE_NAME)
END
GO

这将从数据库中删除所有表

DECLARE @Name VARCHAR(200)
DECLARE @SQL VARCHAR(300)

SELECT @Name = (SELECT TOP 1 [name] FROM sysobjects WHERE [type] = 'U' AND category = 0 ORDER BY [name])

WHILE @Name IS NOT NULL
BEGIN
    SELECT @SQL = 'DROP TABLE [dbo].[' + RTRIM(@name) +']' /*here you can change schema if it is different from dbo*/
    EXEC (@SQL)
    PRINT 'Dropped Table: ' + @Name
    SELECT @Name = (SELECT TOP 1 [name] FROM sysobjects WHERE [type] = 'U' AND category = 0 AND [name] > @Name ORDER BY [name])
END
GO

如果删除整个数据库,然后重新创建它呢?这对我很有用。

DROP DATABASE mydb;
CREATE DATABASE mydb;

对于时态表来说,由于可能会有一些外键和例外,这有点复杂:

在表XXX上执行删除表操作失败,因为在系统版本的时态表上不支持该操作

你可以使用的是:

-- Disable constraints (foreign keys)
EXEC sp_MSForEachTable 'ALTER TABLE ? NOCHECK CONSTRAINT ALL'
GO

-- Disable system versioning (temporial tables)
EXEC sp_MSForEachTable '
 IF OBJECTPROPERTY(object_id(''?''), ''TableTemporalType'') = 2
  ALTER TABLE ? SET (SYSTEM_VERSIONING = OFF)
'
GO

-- Removing tables
EXEC sp_MSForEachTable 'DROP TABLE ?'
GO

在地对地导弹:

右键单击数据库 转到“任务” 点击“生成脚本” 在“选择对象”部分,选择“脚本整个数据库和所有数据库对象” 在“设置脚本选项”部分,单击“高级”按钮 在“脚本删除和创建”上切换“脚本创建”到“脚本删除”并按“确定” 然后,保存到文件,剪贴板,或新的查询窗口。 运行脚本。

现在,这将删除所有内容,包括数据库。确保删除您不希望删除的项目的代码。或者,在“选择对象”部分,而不是选择脚本整个数据库,只是选择你想要删除的项目。