有没有什么简单的方法来删除所有匹配的类,例如,

color-*

如果我有一个元素:

<div id="hello" class="color-red color-brown foo bar"></div>

去除后,它将是

<div id="hello" class="foo bar"></div>

谢谢!


当前回答

在单词边界上拆分正则表达式\b并不是最好的解决方案:

var prefix = "prefix";
var classes = el.className.split(" ").filter(function(c) {
    return c.lastIndexOf(prefix, 0) !== 0;
});
el.className = classes.join(" ");

或作为jQuery mixin:

$.fn.removeClassPrefix = function(prefix) {
    this.each(function(i, el) {
        var classes = el.className.split(" ").filter(function(c) {
            return c.lastIndexOf(prefix, 0) !== 0;
        });
        el.className = classes.join(" ");
    });
    return this;
};

其他回答

我已经写了一个插件,做这个叫做alterClass -删除元素类通配符匹配。可选地添加类:https://gist.github.com/1517285

$( '#foo' ).alterClass( 'foo-* bar-*', 'foobar' )

你也可以使用元素的DOM对象的className属性:

var $hello = $('#hello');
$('#hello').attr('class', $hello.get(0).className.replace(/\bcolor-\S+/g, ''));

删除任何以begin开头的类的泛型函数:

function removeClassStartingWith(node, begin) {
    node.removeClass (function (index, className) {
        return (className.match ( new RegExp("\\b"+begin+"\\S+", "g") ) || []).join(' ');
    });
}

http://jsfiddle.net/xa9xS/2900/

Var begin = 'color-'; 函数removeClassStartingWith(node, begin) { 节点。removeClass(函数(索引,className) { 返回(类名。(新RegExp匹配(“\ \ b”+ +“\ \ S +”开始,“g ") ) || []).加入(' '); }); } removeClassStartingWith($(' #你好'),“颜色——”); console.log($(" #你好”)[0].className); < script src = " https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js " > < /脚本> <div id="hello" class="color-red - color-brown foo bar"></div>

类似于@tremby的答案,这里是@Kobi的答案作为一个插件,将匹配前缀或后缀。

ex)剥离btn-mini和btn-danger,但当stripClass(“btn-”)时不剥离btn。 当stripClass('btn', 1)剥离马btn和牛btn,但不剥离btn-mini或btn

代码:

$.fn.stripClass = function (partialMatch, endOrBegin) {
    /// <summary>
    /// The way removeClass should have been implemented -- accepts a partialMatch (like "btn-") to search on and remove
    /// </summary>
    /// <param name="partialMatch">the class partial to match against, like "btn-" to match "btn-danger btn-active" but not "btn"</param>
    /// <param name="endOrBegin">omit for beginning match; provide a 'truthy' value to only find classes ending with match</param>
    /// <returns type=""></returns>
    var x = new RegExp((!endOrBegin ? "\\b" : "\\S+") + partialMatch + "\\S*", 'g');

    // https://stackoverflow.com/a/2644364/1037948
    this.attr('class', function (i, c) {
        if (!c) return; // protect against no class
        return c.replace(x, '');
    });
    return this;
};

https://gist.github.com/zaus/6734731

这将有效地从节点的class属性中删除所有以prefix开头的类名。其他答案不支持SVG元素(在撰写本文时),但这个解决方案支持:

$.fn.removeClassPrefix = function(prefix){
    var c, regex = new RegExp("(^|\\s)" + prefix + "\\S+", 'g');
    return this.each(function(){
        c = this.getAttribute('class');
        this.setAttribute('class', c.replace(regex, ''));
    });
};