我得到这段代码通过PHP隐蔽大小字节。

现在我想使用JavaScript将这些大小转换为人类可读的大小。我尝试将这段代码转换为JavaScript,看起来像这样:

function formatSizeUnits(bytes){
  if      (bytes >= 1073741824) { bytes = (bytes / 1073741824).toFixed(2) + " GB"; }
  else if (bytes >= 1048576)    { bytes = (bytes / 1048576).toFixed(2) + " MB"; }
  else if (bytes >= 1024)       { bytes = (bytes / 1024).toFixed(2) + " KB"; }
  else if (bytes > 1)           { bytes = bytes + " bytes"; }
  else if (bytes == 1)          { bytes = bytes + " byte"; }
  else                          { bytes = "0 bytes"; }
  return bytes;
}

这是正确的做法吗?有没有更简单的方法?


当前回答

这对我很有用。

bytesForHuman(bytes) {
    let units = ['B', 'KB', 'MB', 'GB', 'TB', 'PB']

    let i = 0
    
    for (i; bytes > 1024; i++) {
        bytes /= 1024;
    }

    return bytes.toFixed(1) + ' ' + units[i]
}

其他回答

我正在更新@ al冰岛的答案。由于小数点对于1,2位数的数字很重要,所以我舍入了第一个小数点并保留第一个小数点。对于3位数的数字,我舍入个位数,忽略所有小数点后的位置。

getMultiplers : function(bytes){
    var unit = 1000 ;
    if (bytes < unit) return bytes ;
    var exp = Math.floor(Math.log(bytes) / Math.log(unit));
    var pre = "kMGTPE".charAt(exp-1);
    var result = bytes / Math.pow(unit, exp);
    if(result/100 < 1)
        return (Math.round( result * 10 ) / 10) +pre;
    else
        return Math.round(result) + pre;
}

更灵活和考虑最大pow尺寸列表 (升级后的l2aelba答案)

function formatBytes(bytes, decimals = 2, isBinary = false) {
      const sizes = ['Bytes', 'KB', 'MB', 'GB', 'TB']; // or ['B', 'KB', 'MB', 'GB', 'TB']
    
      if (!+bytes) {
        return `0 ${sizes[0]}`;
      }
    
      const inByte = isBinary ? 1024 : 1000;
      const dm = decimals < 0 ? 0 : decimals;
    
      const pow = Math.floor(Math.log(bytes) / Math.log(inByte));
      const maxPow = Math.min(pow, sizes.length - 1);
    
      return `${parseFloat((bytes / Math.pow(inByte, maxPow)).toFixed(dm))} ${
        sizes[maxPow]
      }`;
    }

使用位操作将是一个更好的解决方案。试试这个

function formatSizeUnits(bytes)
{
    if ( ( bytes >> 30 ) & 0x3FF )
        bytes = ( bytes >>> 30 ) + '.' + ( bytes & (3*0x3FF )) + 'GB' ;
    else if ( ( bytes >> 20 ) & 0x3FF )
        bytes = ( bytes >>> 20 ) + '.' + ( bytes & (2*0x3FF ) ) + 'MB' ;
    else if ( ( bytes >> 10 ) & 0x3FF )
        bytes = ( bytes >>> 10 ) + '.' + ( bytes & (0x3FF ) ) + 'KB' ;
    else if ( ( bytes >> 1 ) & 0x3FF )
        bytes = ( bytes >>> 1 ) + 'Bytes' ;
    else
        bytes = bytes + 'Byte' ;
    return bytes ;
}

我有一个问题的元数据从服务器返回不同大小的单位。我使用了@Alicejim response,并试图让它更通用。在这里分享代码,也许会帮助到一些人。

enum SizeUnits {
   Bytes = 'Bytes',
   KB = 'KB',
   MB = 'MB',
   GB = 'GB',
   TB = 'TB',
   PB = 'PB',
   EB = 'EB',
   ZB = 'ZB',
   YB = 'YB'
}
function convertSizeUnites(size: number, sourceSizeUnits: SizeUnits, targetSizeUnits: SizeUnits) {
    const i = Object.keys(SizeUnits).indexOf(sourceSizeUnits);
    const sizeInBytes = size * Math.pow(1024, i);
    const j = Object.keys(SizeUnits).indexOf(targetSizeUnits);
    return sizeInBytes / Math.pow(1024, j);
}
function formatSize(size: number, measureUnit: SizeUnits, decimals = 2) {
    if (size === 0) return '0 Bytes';
    const sizeInBytes = convertSizeUnites(size, measureUnit, SizeUnits.Bytes);
    const dm = decimals < 0 ? 0 : decimals;
    const i = Math.floor(Math.log(sizeInBytes) / Math.log(1024));
    return parseFloat((sizeInBytes / Math.pow(1024, i)).toFixed(dm)) + ' ' + 
    Object.keys(SizeUnits)[i];
}

我使用递归和分配水平变量为适当的单位。

函数getReadableByte(count, decimal=0, level=0) { 让unitList =[“字节”,“知识库”,“m”,“g”、“肺结核”,“PT”); if (count >= 1024.0 && (level+1 < unitList.length)) { 返回getReadableByte(count/1024, decimal, ++level) } 返回' ${小数?(count).toFixed(decimal): Math.round(count)}${unitList[level]} ' } 2) console.log (getReadableByte (120)