我如何编写两个函数,如果它以指定的字符/字符串开头或以指定的字符串结尾,那么它们将接受字符串并返回?
例如:
$str = '|apples}';
echo startsWith($str, '|'); //Returns true
echo endsWith($str, '}'); //Returns true
我如何编写两个函数,如果它以指定的字符/字符串开头或以指定的字符串结尾,那么它们将接受字符串并返回?
例如:
$str = '|apples}';
echo startsWith($str, '|'); //Returns true
echo endsWith($str, '}'); //Returns true
当前回答
function startsWith($haystack, $needle, $case = true) {
if ($case) {
return (strcmp(substr($haystack, 0, strlen($needle)), $needle) === 0);
}
return (strcasecmp(substr($haystack, 0, strlen($needle)), $needle) === 0);
}
function endsWith($haystack, $needle, $case = true) {
if ($case) {
return (strcmp(substr($haystack, strlen($haystack) - strlen($needle)), $needle) === 0);
}
return (strcasecmp(substr($haystack, strlen($haystack) - strlen($needle)), $needle) === 0);
}
贷方:
检查字符串是否以另一个字符串结尾
检查字符串是否以另一个字符串开头
其他回答
上面的正则表达式函数,但上面还建议了其他调整:
function startsWith($needle, $haystack) {
return preg_match('/^' . preg_quote($needle, '/') . '/', $haystack);
}
function endsWith($needle, $haystack) {
return preg_match('/' . preg_quote($needle, '/') . '$/', $haystack);
}
这可能奏效
function startsWith($haystack, $needle) {
return substr($haystack, 0, strlen($needle)) == $needle;
}
资料来源:https://stackoverflow.com/a/4419658
我意识到这已经完成,但您可能需要查看strncmp,因为它允许您将字符串的长度与之进行比较,因此:
function startsWith($haystack, $needle, $case=true) {
if ($case)
return strncasecmp($haystack, $needle, strlen($needle)) == 0;
else
return strncmp($haystack, $needle, strlen($needle)) == 0;
}
我希望以下答案既有效又简单:
$content = "The main string to search";
$search = "T";
//For compare the begining string with case insensitive.
if(stripos($content, $search) === 0) echo 'Yes';
else echo 'No';
//For compare the begining string with case sensitive.
if(strpos($content, $search) === 0) echo 'Yes';
else echo 'No';
//For compare the ending string with case insensitive.
if(stripos(strrev($content), strrev($search)) === 0) echo 'Yes';
else echo 'No';
//For compare the ending string with case sensitive.
if(strpos(strrev($content), strrev($search)) === 0) echo 'Yes';
else echo 'No';
无副本,无实习循环:
function startsWith(string $string, string $start): bool
{
return strrpos($string, $start, - strlen($string)) !== false;
}
function endsWith(string $string, string $end): bool
{
return ($offset = strlen($string) - strlen($end)) >= 0
&& strpos($string, $end, $offset) !== false;
}