我如何编写两个函数,如果它以指定的字符/字符串开头或以指定的字符串结尾,那么它们将接受字符串并返回?
例如:
$str = '|apples}';
echo startsWith($str, '|'); //Returns true
echo endsWith($str, '}'); //Returns true
我如何编写两个函数,如果它以指定的字符/字符串开头或以指定的字符串结尾,那么它们将接受字符串并返回?
例如:
$str = '|apples}';
echo startsWith($str, '|'); //Returns true
echo endsWith($str, '}'); //Returns true
当前回答
2016年8月23日更新
功能
function substr_startswith($haystack, $needle) {
return substr($haystack, 0, strlen($needle)) === $needle;
}
function preg_match_startswith($haystack, $needle) {
return preg_match('~' . preg_quote($needle, '~') . '~A', $haystack) > 0;
}
function substr_compare_startswith($haystack, $needle) {
return substr_compare($haystack, $needle, 0, strlen($needle)) === 0;
}
function strpos_startswith($haystack, $needle) {
return strpos($haystack, $needle) === 0;
}
function strncmp_startswith($haystack, $needle) {
return strncmp($haystack, $needle, strlen($needle)) === 0;
}
function strncmp_startswith2($haystack, $needle) {
return $haystack[0] === $needle[0]
? strncmp($haystack, $needle, strlen($needle)) === 0
: false;
}
测验
echo 'generating tests';
for($i = 0; $i < 100000; ++$i) {
if($i % 2500 === 0) echo '.';
$test_cases[] = [
random_bytes(random_int(1, 7000)),
random_bytes(random_int(1, 3000)),
];
}
echo "done!\n";
$functions = ['substr_startswith', 'preg_match_startswith', 'substr_compare_startswith', 'strpos_startswith', 'strncmp_startswith', 'strncmp_startswith2'];
$results = [];
foreach($functions as $func) {
$start = microtime(true);
foreach($test_cases as $tc) {
$func(...$tc);
}
$results[$func] = (microtime(true) - $start) * 1000;
}
asort($results);
foreach($results as $func => $time) {
echo "$func: " . number_format($time, 1) . " ms\n";
}
结果(PHP 7.0.9)
(从最快到最慢排序)
strncmp_startswith2: 40.2 ms
strncmp_startswith: 42.9 ms
substr_compare_startswith: 44.5 ms
substr_startswith: 48.4 ms
strpos_startswith: 138.7 ms
preg_match_startswith: 13,152.4 ms
结果(PHP 5.3.29)
(从最快到最慢排序)
strncmp_startswith2: 477.9 ms
strpos_startswith: 522.1 ms
strncmp_startswith: 617.1 ms
substr_compare_startswith: 706.7 ms
substr_startswith: 756.8 ms
preg_match_startswith: 10,200.0 ms
启动基准.php
其他回答
PHP 8.0及更高版本
从PHP 8.0开始,您可以使用
str_starts_with手册和
str_ends_with手动
实例
echo str_starts_with($str,'|');
8.0之前的PHP
function startsWith( $haystack, $needle ) {
$length = strlen( $needle );
return substr( $haystack, 0, $length ) === $needle;
}
function endsWith( $haystack, $needle ) {
$length = strlen( $needle );
if( !$length ) {
return true;
}
return substr( $haystack, -$length ) === $needle;
}
您可以使用substra_compare函数检查开头和结尾:
function startsWith($haystack, $needle) {
return substr_compare($haystack, $needle, 0, strlen($needle)) === 0;
}
function endsWith($haystack, $needle) {
return substr_compare($haystack, $needle, -strlen($needle)) === 0;
}
这应该是PHP7(基准脚本)上最快的解决方案之一。在8KB的干草堆、各种长度的针以及完全、部分和不匹配的情况下进行测试。strncmp是一种更快的开始方式,但它不能检查结束方式。
到目前为止,所有的答案似乎都做了大量不必要的工作、strlen计算、字符串分配(substr)等。“strpos”和“stripos”函数返回$haystack中$needle第一次出现的索引:
function startsWith($haystack,$needle,$case=true)
{
if ($case)
return strpos($haystack, $needle, 0) === 0;
return stripos($haystack, $needle, 0) === 0;
}
function endsWith($haystack,$needle,$case=true)
{
$expectedPosition = strlen($haystack) - strlen($needle);
if ($case)
return strrpos($haystack, $needle, 0) === $expectedPosition;
return strripos($haystack, $needle, 0) === $expectedPosition;
}
简而言之:
function startsWith($str, $needle){
return substr($str, 0, strlen($needle)) === $needle;
}
function endsWith($str, $needle){
$length = strlen($needle);
return !$length || substr($str, - $length) === $needle;
}
PHP 8更新
PHP 8包含了新的str_starts_with和str_ends_with函数,它们最终为这个问题提供了一个高效便捷的解决方案:
$str = "beginningMiddleEnd";
if (str_starts_with($str, "beg")) echo "printed\n";
if (str_starts_with($str, "Beg")) echo "not printed\n";
if (str_ends_with($str, "End")) echo "printed\n";
if (str_ends_with($str, "end")) echo "not printed\n";
该特性的RFC提供了更多信息,同时也讨论了明显(但不那么明显)用户区域实现的优点和问题。