使用此查询获取Schema, Table, Column,Type, max_length, is_nullable

SELECT QUOTENAME(SCHEMA_NAME(tb.[schema_id])) AS 'Schema'
    ,QUOTENAME(OBJECT_NAME(tb.[OBJECT_ID])) AS 'Table'
    ,C.NAME as 'Column'
    ,T.name AS 'Type'
    ,C.max_length
    ,C.is_nullable
FROM SYS.COLUMNS C INNER JOIN SYS.TABLES tb ON tb.[object_id] = C.[object_id]
    INNER JOIN SYS.TYPES T ON C.system_type_id = T.user_type_id
WHERE tb.[is_ms_shipped] = 0
ORDER BY tb.[Name]

我认为在Microsoft SQL Server Management Studio中最简单和最有用的方法是:

EXEC [ServerName].[DatabaseName].dbo.sp_help 'TableName'

在oracle SQL中，你可以这样做:

SELECT
    DATA_TYPE
FROM
    all_tab_columns 
WHERE
    table_name = 'TABLE NAME' -- in uppercase
AND column_name = 'COLUMN NAME' -- in uppercase

USE [YourDatabaseName]
GO

SELECT column_name 'Column Name',
data_type 'Data Type'
FROM information_schema.columns
WHERE table_name = 'YourTableName'
GO

这将返回值Column Name，显示列的名称，以及这些列的数据类型(int, varchars等)。

使用SQL Server:

SELECT DATA_TYPE 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE 
     TABLE_SCHEMA = 'yourSchemaName' AND
     TABLE_NAME   = 'yourTableName' AND 
     COLUMN_NAME  = 'yourColumnName'

MS SQL的另一个选项是用你想要的类型的查询替换这里的选择查询:

declare @sql varchar(4000);

set @sql = 'select ''hi'' as greeting';

select * from master.sys.dm_exec_describe_first_result_set (@sql, Null, 0);