简式:

var myArray= configuration.GetSection("MyArray")
                        .AsEnumerable()
                        .Where(p => p.Value != null)
                        .Select(p => p.Value)
                        .ToArray();

它返回一个字符串数组:

{“str1”，“str2”，“str3”}

你可以像这样使用Microsoft.Extensions.Configuration.Binder包:

在你的appsettings.json中

{
      "MyArray": [
          "str1",
          "str2",
          "str3"
      ]
}

创建保存配置的对象:

 public class MyConfig
 {
     public List<string> MyArray { get; set; }
 }

在你的控制器绑定配置:

public class HomeController : Controller
{
    private readonly IConfiguration _config;
    private readonly MyConfig _myConfig = new MyConfig();

    public HomeController(IConfiguration config)
    {
        _config = config;
    }

    public IActionResult Index()
    {
        return Json(_config.Bind(_myConfig));
    }
}

appsettings.json:

"MySetting": {
  "MyValues": [
    "C#",
    "ASP.NET",
    "SQL"
  ]
},

我的设置类：

namespace AspNetCore.API.Models
{
    public class MySetting : IMySetting
    {
        public string[] MyValues { get; set; }
    }

    public interface IMySetting
    {
        string[] MyValues { get; set; }
    }
}

Startup.cs

public void ConfigureServices(IServiceCollection services)
{
    ...
    services.Configure<MySetting>(Configuration.GetSection(nameof(MySetting)));
    services.AddSingleton<IMySetting>(sp => sp.GetRequiredService<IOptions<MySetting>>().Value);
    ...
}

Controller.cs

public class DynamicController : ControllerBase
{
    private readonly IMySetting _mySetting;

    public DynamicController(IMySetting mySetting)
    {
        this._mySetting = mySetting;
    }
}

访问值:

var myValues = this._mySetting.MyValues;

这是一个老问题了，但是我可以给出一个用c# 7标准更新的。net Core 2.1的答案。假设我只在appsettings.Development.json中有一个列表，例如:

"TestUsers": [
  {
    "UserName": "TestUser",
    "Email": "Test@place.com",
    "Password": "P@ssw0rd!"
  },
  {
    "UserName": "TestUser2",
    "Email": "Test2@place.com",
    "Password": "P@ssw0rd!"
  }
]

我可以在Microsoft.Extensions.Configuration.IConfiguration被实现并像这样连接的任何地方提取它们:

var testUsers = Configuration.GetSection("TestUsers")
   .GetChildren()
   .ToList()
    //Named tuple returns, new in C# 7
   .Select(x => 
         (
          x.GetValue<string>("UserName"), 
          x.GetValue<string>("Email"), 
          x.GetValue<string>("Password")
          )
    )
    .ToList<(string UserName, string Email, string Password)>();

现在我有了一个良好类型对象的列表。如果我点击testUsers.First()， Visual Studio现在应该会显示“用户名”、“电子邮件”和“密码”选项。

对于从配置返回复杂JSON对象数组的情况，我调整了@djangojazz的答案，以使用匿名类型和动态而不是元组。

给定的设置部分:

"TestUsers": [
{
  "UserName": "TestUser",
  "Email": "Test@place.com",
  "Password": "P@ssw0rd!"
},
{
  "UserName": "TestUser2",
  "Email": "Test2@place.com",
  "Password": "P@ssw0rd!"
}],

你可以这样返回对象数组:

public dynamic GetTestUsers()
{
    var testUsers = Configuration.GetSection("TestUsers")
                    .GetChildren()
                    .ToList()
                    .Select(x => new {
                        UserName = x.GetValue<string>("UserName"),
                        Email = x.GetValue<string>("Email"),
                        Password = x.GetValue<string>("Password")
                    });

    return new { Data = testUsers };
}

你可以直接获得数组，而不需要在配置中增加一个新的级别:

public void ConfigureServices(IServiceCollection services) {
    services.Configure<List<String>>(Configuration.GetSection("MyArray"));
    //...
}