对于从配置返回复杂JSON对象数组的情况，我调整了@djangojazz的答案，以使用匿名类型和动态而不是元组。

给定的设置部分:

"TestUsers": [
{
  "UserName": "TestUser",
  "Email": "Test@place.com",
  "Password": "P@ssw0rd!"
},
{
  "UserName": "TestUser2",
  "Email": "Test2@place.com",
  "Password": "P@ssw0rd!"
}],

你可以这样返回对象数组:

public dynamic GetTestUsers()
{
    var testUsers = Configuration.GetSection("TestUsers")
                    .GetChildren()
                    .ToList()
                    .Select(x => new {
                        UserName = x.GetValue<string>("UserName"),
                        Email = x.GetValue<string>("Email"),
                        Password = x.GetValue<string>("Password")
                    });

    return new { Data = testUsers };
}

.Net Core 7.x中处理对象的不同方法

在appsettings.json:

{
      "People": [
          { "FirstName": "Glen", "LastName": "Johnson", "Age": 30 },
          { "FirstName": "Matt", "LastName": "Smith", "Age": 40 },
          { "FirstName": "Fred", "LastName": "Williams", "Age": 50 }
      ]
}

Person类:

public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public int Age { get; set; }
}

在代码中:

var appConfig = App.Current.AppConfiguration;   // Or could be passed in through DI
var children = appConfig.GetSection("People")
    .GetChildren()
    .ToList();

var people = new List<Person>();
foreach (var child in children)
{
    var rec = new Person
    {
        FirstName = appConfig[$"{child.Path}:FirstName"],
        LastName = appConfig[$"{child.Path}:LastName"],
        Age = int.Parse(appConfig[$"{child.Path}:Age"]),
    };
    people.Add(rec);
}

最近我还需要从appsettings中读取一个简单的字符串数组。Json文件(以及其他类似的. Json配置文件)。

对于我的方法，我创建了一个简单的扩展方法:

public static class IConfigurationRootExtensions
{
    public static string[] GetArray(this IConfigurationRoot configuration, string key)
    {
        var collection = new List<string>();
        var children = configuration.GetSection(key)?.GetChildren();
        if (children != null)
        {
            foreach (var child in children) collection.Add(child.Value);
        }
        return collection.ToArray();
    }
}

原始海报的.json文件如下所示:

{
      "MyArray": [
          "str1",
          "str2",
          "str3"
      ]
}

使用上面的扩展方法，它使读取这个数组成为一个非常简单的一行事务，如下面的例子所示:

var configuration = new ConfigurationBuilder().AddJsonFile("appsettings.json").Build();
string[] values = configuration.GetArray("MyArray");

在运行时，在值上设置一个'QuickWatch'的断点，以验证我们已经成功地将.json配置文件中的值读入一个字符串数组:

appsettings.json:

"MySetting": {
  "MyValues": [
    "C#",
    "ASP.NET",
    "SQL"
  ]
},

我的设置类：

namespace AspNetCore.API.Models
{
    public class MySetting : IMySetting
    {
        public string[] MyValues { get; set; }
    }

    public interface IMySetting
    {
        string[] MyValues { get; set; }
    }
}

Startup.cs

public void ConfigureServices(IServiceCollection services)
{
    ...
    services.Configure<MySetting>(Configuration.GetSection(nameof(MySetting)));
    services.AddSingleton<IMySetting>(sp => sp.GetRequiredService<IOptions<MySetting>>().Value);
    ...
}

Controller.cs

public class DynamicController : ControllerBase
{
    private readonly IMySetting _mySetting;

    public DynamicController(IMySetting mySetting)
    {
        this._mySetting = mySetting;
    }
}

访问值:

var myValues = this._mySetting.MyValues;

对于从配置返回复杂JSON对象数组的情况，我调整了@djangojazz的答案，以使用匿名类型和动态而不是元组。

给定的设置部分:

"TestUsers": [
{
  "UserName": "TestUser",
  "Email": "Test@place.com",
  "Password": "P@ssw0rd!"
},
{
  "UserName": "TestUser2",
  "Email": "Test2@place.com",
  "Password": "P@ssw0rd!"
}],

你可以这样返回对象数组:

public dynamic GetTestUsers()
{
    var testUsers = Configuration.GetSection("TestUsers")
                    .GetChildren()
                    .ToList()
                    .Select(x => new {
                        UserName = x.GetValue<string>("UserName"),
                        Email = x.GetValue<string>("Email"),
                        Password = x.GetValue<string>("Password")
                    });

    return new { Data = testUsers };
}

在IOptions不起作用后，我发现这更简单，序列化时要做的事情也少得多。

//appsettings.json
"DatabaseModelCreationOptions": {
    "Users": [
      {
        "Id": "1",
        "UserName": "adminuser",
        "Email": "youremail@myemail.com",
        "Password": "!Ch4",
        "Player": "Admin",
        "PlayerInitials": "ADMIN",
        "ApiKey": "40753ey"
      }
    ],   
    "UserRoles": [
      {
        "Id": "af9986df",
        "Name": "Admin",
        "ConcurrencyStamp": "ddd53170"
      },
      {
        "Id": "03b82b0e",
        "Name": "Manager",
        "ConcurrencyStamp": "65da3f89"
      }
    ]
}

我需要的类，我不需要给你们看嵌套的类属性，你们可以在上面看到。

public class DatabaseModelCreationOptions
{
    public IEnumerable<User>? Users { get; set; }
    public IEnumerable<UserRole>? UserRoles { get; set; }
}

然后调用GetSection("")。得到

var dbOptions = configuration.GetSection("DatabaseModelCreationOptions")
    .Get<DatabaseModelCreationOptions>();