我有一个数据框架形式的相当大的数据集,我想知道我如何能够将数据框架分成两个随机样本(80%和20%)进行训练和测试。
谢谢!
我有一个数据框架形式的相当大的数据集,我想知道我如何能够将数据框架分成两个随机样本(80%和20%)进行训练和测试。
谢谢!
当前回答
这个怎么样? Df是我的数据框架
total_size=len(df)
train_size=math.floor(0.66*total_size) (2/3 part of my dataset)
#training dataset
train=df.head(train_size)
#test dataset
test=df.tail(len(df) -train_size)
其他回答
可以使用~(波浪符)排除使用df.sample()采样的行,让pandas单独处理索引的采样和过滤,以获得两个集。
train_df = df.sample(frac=0.8, random_state=100)
test_df = df[~df.index.isin(train_df.index)]
Scikit Learn的train_test_split就是一个很好的例子。它将拆分numpy数组和数据框架。
from sklearn.model_selection import train_test_split
train, test = train_test_split(df, test_size=0.2)
如果你想把它分成训练集、测试集和验证集,你可以使用这个函数:
from sklearn.model_selection import train_test_split
import pandas as pd
def train_test_val_split(df, test_size=0.15, val_size=0.45):
temp, test = train_test_split(df, test_size=test_size)
total_items_count = len(df.index)
val_length = total_items_count * val_size
new_val_propotion = val_length / len(temp.index)
train, val = train_test_split(temp, test_size=new_val_propotion)
return train, test, val
上面有很多很好的答案,所以我只想再加一个例子,在这种情况下,你想通过使用numpy库来指定火车和测试集的确切样本数量。
# set the random seed for the reproducibility
np.random.seed(17)
# e.g. number of samples for the training set is 1000
n_train = 1000
# shuffle the indexes
shuffled_indexes = np.arange(len(data_df))
np.random.shuffle(shuffled_indexes)
# use 'n_train' samples for training and the rest for testing
train_ids = shuffled_indexes[:n_train]
test_ids = shuffled_indexes[n_train:]
train_data = data_df.iloc[train_ids]
train_labels = labels_df.iloc[train_ids]
test_data = data_df.iloc[test_ids]
test_labels = data_df.iloc[test_ids]
如果你希望有一个数据帧和两个数据帧(不是numpy数组),这应该可以做到:
def split_data(df, train_perc = 0.8):
df['train'] = np.random.rand(len(df)) < train_perc
train = df[df.train == 1]
test = df[df.train == 0]
split_data ={'train': train, 'test': test}
return split_data