非常好的代码。

http://www.rgagnon.com/javadetails/java-0585.html

import java.util.concurrent.TimeUnit;

long startTime = System.currentTimeMillis();
........
........
........
long finishTime = System.currentTimeMillis();

String diff = millisToShortDHMS(finishTime - startTime);


  /**
   * converts time (in milliseconds) to human-readable format
   *  "<dd:>hh:mm:ss"
   */
  public static String millisToShortDHMS(long duration) {
    String res = "";
    long days  = TimeUnit.MILLISECONDS.toDays(duration);
    long hours = TimeUnit.MILLISECONDS.toHours(duration)
                   - TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(duration));
    long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)
                     - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(duration));
    long seconds = TimeUnit.MILLISECONDS.toSeconds(duration)
                   - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(duration));
    if (days == 0) {
      res = String.format("%02d:%02d:%02d", hours, minutes, seconds);
    }
    else {
      res = String.format("%dd%02d:%02d:%02d", days, hours, minutes, seconds);
    }
    return res;
  }

下面是打印好的字符串，格式化后的秒数，类似于谷歌搜索所需的时间:

        long startTime = System.nanoTime();
        //  ... methodToTime();
        long endTime = System.nanoTime();
        long duration = (endTime - startTime);
        long seconds = (duration / 1000) % 60;
        // formatedSeconds = (0.xy seconds)
        String formatedSeconds = String.format("(0.%d seconds)", seconds);
        System.out.println("formatedSeconds = "+ formatedSeconds);
        // i.e actual formatedSeconds = (0.52 seconds)

有几种方法可以做到。我通常会使用这样的方法:

long start = System.currentTimeMillis();
// ... do something ...
long end = System.currentTimeMillis();

或者System.nanoTime();

关于基准测试方面的更多内容，似乎还有这个:http://jetm.void.fm/但从未尝试过。

在Java 8中引入了一个名为Instant的新类。根据文件:

Instant represents the start of a nanosecond on the time line. This class is useful for generating a time stamp to represent machine time. The range of an instant requires the storage of a number larger than a long. To achieve this, the class stores a long representing epoch-seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The epoch-seconds are measured from the standard Java epoch of 1970-01-01T00:00:00Z where instants after the epoch have positive values, and earlier instants have negative values. For both the epoch-second and nanosecond parts, a larger value is always later on the time-line than a smaller value.

这可以用于:

Instant start = Instant.now();
try {
    Thread.sleep(7000);
} catch (InterruptedException e) {
    e.printStackTrace();
}
Instant end = Instant.now();
System.out.println(Duration.between(start, end));

打印pt7.001。

如果你想要时间

long start_time = System.currentTimeMillis();
object.method();
long end_time = System.currentTimeMillis();
long execution_time = end_time - start_time;

对于java 8+，另一种可能的解决方案(更通用，函数风格，没有方面)可能是创建一些实用程序方法，将代码作为参数接受

public static <T> T timed (String description, Consumer<String> out, Supplier<T> code) {
    final LocalDateTime start = LocalDateTime.now ();
    T res = code.get ();
    final long execTime = Duration.between (start, LocalDateTime.now ()).toMillis ();
    out.accept (String.format ("%s: %d ms", description, execTime));
    return res;
}

调用代码可以是这样的smth:

public static void main (String[] args) throws InterruptedException {
    timed ("Simple example", System.out::println, Timing::myCode);
}

public static Object myCode () {
    try {
        Thread.sleep (1500);
    } catch (InterruptedException e) {
        e.printStackTrace ();
    }
    return null;
}