在Visual Studio的即时窗口中:

> Path.Combine(@"C:\x", "y")
"C:\\x\\y"
> Path.Combine(@"C:\x", @"\y")
"\\y"

看来它们应该是一样的。

旧的FileSystemObject.BuildPath()不是这样工作的……


当前回答

正如Ryan所提到的,它正在做文档中所说的事情。

根据DOS时间,区分当前磁盘和当前路径。 \是根路径,但用于当前磁盘。

对于每个“磁盘”都有一个单独的“当前路径”。 如果您使用cd D:更改磁盘,则不会将当前路径更改为D:\,而是更改为:“D:\whatever\was\the\last\path\access \on\this\disk”…

因此,在windows中,文字@“\x”意味着:“CURRENTDISK:\x”。 因此路径。Combine(@"C:\x", @"\y")的第二个参数是根路径,不是相对路径,虽然不在已知磁盘中… 由于不知道哪个可能是«当前磁盘»,python返回“\\y”。

>cd C:
>cd \mydironC\apath
>cd D:
>cd \mydironD\bpath
>cd C:
>cd
>C:\mydironC\apath

其他回答

删除Path.Combine的第二个参数(path2)中的起始斜杠('\')。

我想解决这个问题:

string sample1 = "configuration/config.xml";
string sample2 = "/configuration/config.xml";
string sample3 = "\\configuration/config.xml";

string dir1 = "c:\\temp";
string dir2 = "c:\\temp\\";
string dir3 = "c:\\temp/";

string path1 = PathCombine(dir1, sample1);
string path2 = PathCombine(dir1, sample2);
string path3 = PathCombine(dir1, sample3);

string path4 = PathCombine(dir2, sample1);
string path5 = PathCombine(dir2, sample2);
string path6 = PathCombine(dir2, sample3);

string path7 = PathCombine(dir3, sample1);
string path8 = PathCombine(dir3, sample2);
string path9 = PathCombine(dir3, sample3);

当然,所有路径1-9最后都应该包含一个等效的字符串。这是我想出的PathCombine方法:

private string PathCombine(string path1, string path2)
{
    if (Path.IsPathRooted(path2))
    {
        path2 = path2.TrimStart(Path.DirectorySeparatorChar);
        path2 = path2.TrimStart(Path.AltDirectorySeparatorChar);
    }

    return Path.Combine(path1, path2);
}

我还认为这是相当恼人的字符串处理必须手动完成,我对这背后的原因很感兴趣。

In my opinion this is a bug. The problem is that there are two different types of "absolute" paths. The path "d:\mydir\myfile.txt" is absolute, the path "\mydir\myfile.txt" is also considered to be "absolute" even though it is missing the drive letter. The correct behavior, in my opinion, would be to prepend the drive letter from the first path when the second path starts with the directory separator (and is not a UNC path). I would recommend writing your own helper wrapper function which has the behavior you desire if you need it.

这实际上是有意义的,在某种程度上,考虑到(相对)路径通常是如何处理的:

string GetFullPath(string path)
{
     string baseDir = @"C:\Users\Foo.Bar";
     return Path.Combine(baseDir, path);
}

// Get full path for RELATIVE file path
GetFullPath("file.txt"); // = C:\Users\Foo.Bar\file.txt

// Get full path for ROOTED file path
GetFullPath(@"C:\Temp\file.txt"); // = C:\Temp\file.txt

真正的问题是:为什么以“\”开头的路径被认为是“根路径”?这对我来说也很新鲜,但它在Windows上是这样工作的:

new FileInfo("\windows"); // FullName = C:\Windows, Exists = True
new FileInfo("windows"); // FullName = C:\Users\Foo.Bar\Windows, Exists = False

这是. net Reflector for Path的反汇编代码。结合的方法。检查ispathoot函数。如果第二个路径是根路径(以DirectorySeparatorChar开头),则返回第二个路径。

public static string Combine(string path1, string path2)
{
    if ((path1 == null) || (path2 == null))
    {
        throw new ArgumentNullException((path1 == null) ? "path1" : "path2");
    }
    CheckInvalidPathChars(path1);
    CheckInvalidPathChars(path2);
    if (path2.Length == 0)
    {
        return path1;
    }
    if (path1.Length == 0)
    {
        return path2;
    }
    if (IsPathRooted(path2))
    {
        return path2;
    }
    char ch = path1[path1.Length - 1];
    if (((ch != DirectorySeparatorChar) &&
         (ch != AltDirectorySeparatorChar)) &&
         (ch != VolumeSeparatorChar))
    {
        return (path1 + DirectorySeparatorChar + path2);
    }
    return (path1 + path2);
}


public static bool IsPathRooted(string path)
{
    if (path != null)
    {
        CheckInvalidPathChars(path);
        int length = path.Length;
        if (
              (
                  (length >= 1) &&
                  (
                      (path[0] == DirectorySeparatorChar) ||
                      (path[0] == AltDirectorySeparatorChar)
                  )
              )

              ||

              ((length >= 2) &&
              (path[1] == VolumeSeparatorChar))
           )
        {
            return true;
        }
    }
    return false;
}