我想进行base64编码和解码,但我无法从iPhone SDK中找到任何支持。我怎么能做base64编码和解码与或没有一个库?


当前回答

更好的解决方案:

NSData中有一个内置函数

[data base64Encoding]; //iOS < 7.0
[data base64EncodedStringWithOptions:NSDataBase64Encoding76CharacterLineLength]; //iOS >= 7.0

其他回答

在mvds的出色改进中,存在两个问题。更改代码如下:

raw = tmpbuf;
inp = 0;
outbuf[outp++] = base64EncodingTable[(raw[inp] & 0xFC) >> 2];
outbuf[outp++] = base64EncodingTable[((raw[inp] & 0x03) << 4) | ((raw[inp+1] & 0xF0) >> 4)];
if ( left == 2 ) outbuf[outp++] = base64EncodingTable[((raw[inp+1] & 0x0F) << 2) | ((raw[inp+2] & 0xC0) >> 6)];
else outbuf[outp++] = '=';
outbuf[outp++] = '=';

更好的解决方案:

NSData中有一个内置函数

[data base64Encoding]; //iOS < 7.0
[data base64EncodedStringWithOptions:NSDataBase64Encoding76CharacterLineLength]; //iOS >= 7.0

这是一个紧凑的Objective-C版本,作为NSData的类别。这需要一些思考……

@implementation NSData (DataUtils)

static char base64[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";

- (NSString *)newStringInBase64FromData
{
 NSMutableString *dest = [[NSMutableString alloc] initWithString:@""];
 unsigned char * working = (unsigned char *)[self bytes];
 int srcLen = [self length];

 // tackle the source in 3's as conveniently 4 Base64 nibbles fit into 3 bytes
 for (int i=0; i<srcLen; i += 3)
 {
  // for each output nibble
  for (int nib=0; nib<4; nib++)
  {
   // nibble:nib from char:byt
   int byt = (nib == 0)?0:nib-1;
   int ix = (nib+1)*2;

   if (i+byt >= srcLen) break;

   // extract the top bits of the nibble, if valid
   unsigned char curr = ((working[i+byt] << (8-ix)) & 0x3F);

   // extract the bottom bits of the nibble, if valid
   if (i+nib < srcLen) curr |= ((working[i+nib] >> ix) & 0x3F);

   [dest appendFormat:@"%c", base64[curr]];
  }
 }

 return dest;
}

@end

如果需要,可以通过扩大'byt'的范围并在(2-byt)后面附加'dest'来添加填充。返回前的"="字符。

Category可以被添加到NSString中,这样:

@implementation NSString (StringUtils)

- (NSString *)newStringInBase64FromString
{
 NSData *theData = [NSData dataWithBytes:[self UTF8String] length:[self length]]; 

 return [theData newStringInBase64FromData];
}

@end

因为这似乎是在base64编码和iphone上排名第一的谷歌,我想用上面的代码片段分享我的经验。

它是有效的,但是非常慢。在本机iphone上对随机图像(0.4 mb)进行基准测试需要37秒。主要原因可能是OOP的魔力——单字符nsstring等,只有在编码完成后才会自动释放。

这里发布的另一个建议(ab)使用openssl库,这感觉也有点过分。

下面的代码需要70毫秒——这是500倍的加速。这只做base64编码(解码将遵循一旦我遇到它)

+ (NSString *) base64StringFromData: (NSData *)data length: (int)length {
int lentext = [data length]; 
if (lentext < 1) return @"";

char *outbuf = malloc(lentext*4/3+4); // add 4 to be sure

if ( !outbuf ) return nil;

const unsigned char *raw = [data bytes];

int inp = 0;
int outp = 0;
int do_now = lentext - (lentext%3);

for ( outp = 0, inp = 0; inp < do_now; inp += 3 )
{
    outbuf[outp++] = base64EncodingTable[(raw[inp] & 0xFC) >> 2];
    outbuf[outp++] = base64EncodingTable[((raw[inp] & 0x03) << 4) | ((raw[inp+1] & 0xF0) >> 4)];
    outbuf[outp++] = base64EncodingTable[((raw[inp+1] & 0x0F) << 2) | ((raw[inp+2] & 0xC0) >> 6)];
    outbuf[outp++] = base64EncodingTable[raw[inp+2] & 0x3F];
}

if ( do_now < lentext )
{
    char tmpbuf[2] = {0,0};
    int left = lentext%3;
    for ( int i=0; i < left; i++ )
    {
        tmpbuf[i] = raw[do_now+i];
    }
    raw = tmpbuf;
    outbuf[outp++] = base64EncodingTable[(raw[inp] & 0xFC) >> 2];
    outbuf[outp++] = base64EncodingTable[((raw[inp] & 0x03) << 4) | ((raw[inp+1] & 0xF0) >> 4)];
    if ( left == 2 ) outbuf[outp++] = base64EncodingTable[((raw[inp+1] & 0x0F) << 2) | ((raw[inp+2] & 0xC0) >> 6)];
}

NSString *ret = [[[NSString alloc] initWithBytes:outbuf length:outp encoding:NSASCIIStringEncoding] autorelease];
free(outbuf);

return ret;
}

我省略了行切割,因为我不需要它,但添加它是微不足道的。

对于那些对优化感兴趣的人来说:目标是最小化主循环中发生的事情。因此,处理最后3个字节的所有逻辑都在循环之外处理。

此外,尝试就地处理数据,而不需要额外地从缓冲区复制数据。把所有算术运算都简化到最小。

观察那些放在一起查找表中的条目的位,当它们被放在一起而不移动时,它们不会重叠。因此,一个主要的改进可能是使用4个单独的256字节查找表并消除移位,如下所示:

outbuf[outp++] = base64EncodingTable1[(raw[inp] & 0xFC)];
outbuf[outp++] = base64EncodingTable2[(raw[inp] & 0x03) | (raw[inp+1] & 0xF0)];
outbuf[outp++] = base64EncodingTable3[(raw[inp+1] & 0x0F) | (raw[inp+2] & 0xC0)];
outbuf[outp++] = base64EncodingTable4[raw[inp+2] & 0x3F];

当然,你可以更进一步,但这超出了这里的范围。

我已经做到了使用以下类..

@implementation Base64Converter
static char base64EncodingTable[64] = {
'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L',  'M', 'N', 'O', 'P',
'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', 'a', 'b', 'c', 'd', 'e', 'f',
'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v',
'w', 'x', 'y', 'z', '0', '1', '2', '3', '4', '5', '6', '7',    '8', '9', '+', '/'
};
+ (NSString *) base64StringFromData: (NSData *)data length: (int)length {

unsigned long ixtext, lentext;

long ctremaining;

unsigned char input[3], output[4];

short i, charsonline = 0, ctcopy;

const unsigned char *raw;

NSMutableString *result;

lentext = [data length];

if (lentext < 1)
    return @"";

result = [NSMutableString stringWithCapacity: lentext];

raw = [data bytes];

ixtext = 0;

while (true) {

    ctremaining = lentext - ixtext;

    if (ctremaining <= 0)
        break;

    for (i = 0; i < 3; i++) {
        unsigned long ix = ixtext + i;
        if (ix < lentext)
            input[i] = raw[ix];
        else
            input[i] = 0;
    }

    output[0] = (input[0] & 0xFC) >> 2;

    output[1] = ((input[0] & 0x03) << 4) | ((input[1] & 0xF0) >> 4);

    output[2] = ((input[1] & 0x0F) << 2) | ((input[2] & 0xC0) >> 6);

    output[3] = input[2] & 0x3F;

    ctcopy = 4;

    switch (ctremaining) {
        case 1:
            ctcopy = 2;
            break;

        case 2:
            ctcopy = 3;
            break;
    }

    for (i = 0; i < ctcopy; i++)
        [result appendString: [NSString stringWithFormat: @"%c", base64EncodingTable[output[i]]]];

    for (i = ctcopy; i < 4; i++)
        [result appendString: @"="];

    ixtext += 3;

    charsonline += 4;

    if ((length > 0) && (charsonline >= length))
        charsonline = 0;
}
return result;
}
@end

打电话的时候

 [Base64Converter base64StringFromData:dataval length:lengthval];

就是这样……