我在。net中有一个字符串，实际上是一个URL。我想要一种简单的方法从特定的参数中获取值。
通常，我只使用Request。Params["theThingIWant"]，但是这个字符串不是来自请求。我可以像这样创建一个新的Uri项:
Uri myUri = new Uri(TheStringUrlIWantMyValueFrom);
我可以使用myUri。查询以获取查询字符串…但显然我得找个雷克斯风的方法把它分开。
我是否遗漏了一些明显的东西，或者是否没有内置的方法来创建某种类型的正则表达式，等等?
当前回答
或者，如果您不知道URL(为了避免硬编码，请使用AbsoluteUri
例子……
//get the full URL
Uri myUri = new Uri(Request.Url.AbsoluteUri);
//get any parameters
string strStatus = HttpUtility.ParseQueryString(myUri.Query).Get("status");
string strMsg = HttpUtility.ParseQueryString(myUri.Query).Get("message");
switch (strStatus.ToUpper())
{
case "OK":
webMessageBox.Show("EMAILS SENT!");
break;
case "ER":
webMessageBox.Show("EMAILS SENT, BUT ... " + strMsg);
break;
}
其他回答
如果出于任何原因，你不能或不想使用HttpUtility.ParseQueryString()，这里有另一种选择。
这是为了在一定程度上容忍“畸形”的查询字符串，即http://test/test.html?empty=成为一个空值的参数。如果需要，调用方可以验证参数。
public static class UriHelper
{
public static Dictionary<string, string> DecodeQueryParameters(this Uri uri)
{
if (uri == null)
throw new ArgumentNullException("uri");
if (uri.Query.Length == 0)
return new Dictionary<string, string>();
return uri.Query.TrimStart('?')
.Split(new[] { '&', ';' }, StringSplitOptions.RemoveEmptyEntries)
.Select(parameter => parameter.Split(new[] { '=' }, StringSplitOptions.RemoveEmptyEntries))
.GroupBy(parts => parts[0],
parts => parts.Length > 2 ? string.Join("=", parts, 1, parts.Length - 1) : (parts.Length > 1 ? parts[1] : ""))
.ToDictionary(grouping => grouping.Key,
grouping => string.Join(",", grouping));
}
}
Test
[TestClass]
public class UriHelperTest
{
[TestMethod]
public void DecodeQueryParameters()
{
DecodeQueryParametersTest("http://test/test.html", new Dictionary<string, string>());
DecodeQueryParametersTest("http://test/test.html?", new Dictionary<string, string>());
DecodeQueryParametersTest("http://test/test.html?key=bla/blub.xml", new Dictionary<string, string> { { "key", "bla/blub.xml" } });
DecodeQueryParametersTest("http://test/test.html?eins=1&zwei=2", new Dictionary<string, string> { { "eins", "1" }, { "zwei", "2" } });
DecodeQueryParametersTest("http://test/test.html?empty", new Dictionary<string, string> { { "empty", "" } });
DecodeQueryParametersTest("http://test/test.html?empty=", new Dictionary<string, string> { { "empty", "" } });
DecodeQueryParametersTest("http://test/test.html?key=1&", new Dictionary<string, string> { { "key", "1" } });
DecodeQueryParametersTest("http://test/test.html?key=value?&b=c", new Dictionary<string, string> { { "key", "value?" }, { "b", "c" } });
DecodeQueryParametersTest("http://test/test.html?key=value=what", new Dictionary<string, string> { { "key", "value=what" } });
DecodeQueryParametersTest("http://www.google.com/search?q=energy+edge&rls=com.microsoft:en-au&ie=UTF-8&oe=UTF-8&startIndex=&startPage=1%22",
new Dictionary<string, string>
{
{ "q", "energy+edge" },
{ "rls", "com.microsoft:en-au" },
{ "ie", "UTF-8" },
{ "oe", "UTF-8" },
{ "startIndex", "" },
{ "startPage", "1%22" },
});
DecodeQueryParametersTest("http://test/test.html?key=value;key=anotherValue", new Dictionary<string, string> { { "key", "value,anotherValue" } });
}
private static void DecodeQueryParametersTest(string uri, Dictionary<string, string> expected)
{
Dictionary<string, string> parameters = new Uri(uri).DecodeQueryParameters();
Assert.AreEqual(expected.Count, parameters.Count, "Wrong parameter count. Uri: {0}", uri);
foreach (var key in expected.Keys)
{
Assert.IsTrue(parameters.ContainsKey(key), "Missing parameter key {0}. Uri: {1}", key, uri);
Assert.AreEqual(expected[key], parameters[key], "Wrong parameter value for {0}. Uri: {1}", parameters[key], uri);
}
}
}
获取参数名称的最简单方法:
using System.Linq;
string loc = "https://localhost:5000/path?desiredparam=that_value&anotherParam=whatever";
var c = loc.Split("desiredparam=").Last().Split("&").First();//that_value
HttpContext.Current.Request.QueryString.Get("id");
你也可以使用下面的方法来处理第一个参数:
var param1 =
HttpUtility.ParseQueryString(url.Substring(
new []{0, url.IndexOf('?')}.Max()
)).Get("param1");
单线LINQ解决方案:
Dictionary<string, string> ParseQueryString(string query)
{
return query.Replace("?", "").Split('&').ToDictionary(pair => pair.Split('=').First(), pair => pair.Split('=').Last());
}
