大多数解决方案都依赖于项目的奇数，这样你就可以把中间的项目放在中间。如果你有偶数个项目想要平均分配呢?这是一个更一般的解。这个类别将沿垂直或水平轴均匀分布任意数量的项目。

在它们的父视图中垂直分布4个标签的示例:

[self.view addConstraints:
     [NSLayoutConstraint constraintsForEvenDistributionOfItems:@[label1, label2, label3, label4]
                                        relativeToCenterOfItem:self.view
                                                    vertically:YES]];

NSLayoutConstraint + EvenDistribution.h

@interface NSLayoutConstraint (EvenDistribution)

/**
 * Returns constraints that will cause a set of views to be evenly distributed horizontally
 * or vertically relative to the center of another item. This is used to maintain an even
 * distribution of subviews even when the superview is resized.
 */
+ (NSArray *) constraintsForEvenDistributionOfItems:(NSArray *)views
                             relativeToCenterOfItem:(id)toView
                                         vertically:(BOOL)vertically;

@end

NSLayoutConstraint + EvenDistribution.m

@implementation NSLayoutConstraint (EvenDistribution)

+(NSArray *)constraintsForEvenDistributionOfItems:(NSArray *)views
                           relativeToCenterOfItem:(id)toView vertically:(BOOL)vertically
{
    NSMutableArray *constraints = [NSMutableArray new];
    NSLayoutAttribute attr = vertically ? NSLayoutAttributeCenterY : NSLayoutAttributeCenterX;

    for (NSUInteger i = 0; i < [views count]; i++) {
        id view = views[i];
        CGFloat multiplier = (2*i + 2) / (CGFloat)([views count] + 1);
        NSLayoutConstraint *constraint = [NSLayoutConstraint constraintWithItem:view
                                                                      attribute:attr
                                                                      relatedBy:NSLayoutRelationEqual
                                                                         toItem:toView
                                                                      attribute:attr
                                                                     multiplier:multiplier
                                                                       constant:0];
        [constraints addObject:constraint];
    }

    return constraints;
}

@end

Here is a solution that will vertically center any number of subviews, even if they have unique sizes. What you want to do is make a mid-level container, center that in the superview, then put all the subviews in the container and arrange them with respect to one another. But crucially you also need to constrain them to the top and bottom of the container, so the container can be correctly sized and centered in the superview. By figuring the correct height from its subviews, the container can be vertically centered.

在本例中，self是位于所有子视图居中的父视图。

NSArray *subviews = @[ (your subviews in top-to-bottom order) ];

UIView *container = [[UIView alloc] initWithFrame:CGRectZero];
container.translatesAutoresizingMaskIntoConstraints = NO;
for (UIView *subview in subviews) {
    subview.translatesAutoresizingMaskIntoConstraints = NO;
    [container addSubview:subview];
}
[self addSubview:container];

[self addConstraint:[NSLayoutConstraint constraintWithItem:container attribute:NSLayoutAttributeLeft relatedBy:NSLayoutRelationEqual
                                                    toItem:self attribute:NSLayoutAttributeLeft multiplier:1.0f constant:0.0f]];
[self addConstraint:[NSLayoutConstraint constraintWithItem:container attribute:NSLayoutAttributeRight relatedBy:NSLayoutRelationEqual
                                                    toItem:self attribute:NSLayoutAttributeRight multiplier:1.0f constant:0.0f]];
[self addConstraint:[NSLayoutConstraint constraintWithItem:container attribute:NSLayoutAttributeCenterY relatedBy:NSLayoutRelationEqual
                                                    toItem:self attribute:NSLayoutAttributeCenterY multiplier:1.0f constant:0.0f]];

if (0 < subviews.count) {
    UIView *firstSubview = subviews[0];
    [container addConstraint:[NSLayoutConstraint constraintWithItem:firstSubview attribute:NSLayoutAttributeTop relatedBy:NSLayoutRelationEqual
                                                             toItem:container attribute:NSLayoutAttributeTop multiplier:1.0f constant:0.0f]];
    UIView *lastSubview = subviews.lastObject;
    [container addConstraint:[NSLayoutConstraint constraintWithItem:lastSubview attribute:NSLayoutAttributeBottom relatedBy:NSLayoutRelationEqual
                                                             toItem:container attribute:NSLayoutAttributeBottom multiplier:1.0f constant:0.0f]];

    UIView *subviewAbove = nil;
    for (UIView *subview in subviews) {
        [container addConstraint:[NSLayoutConstraint constraintWithItem:subview attribute:NSLayoutAttributeCenterX relatedBy:NSLayoutRelationEqual
                                                                 toItem:container attribute:NSLayoutAttributeCenterX multiplier:1.0f constant:0.0f]];
        if (subviewAbove) {
            [container addConstraint:[NSLayoutConstraint constraintWithItem:subview attribute:NSLayoutAttributeTop relatedBy:NSLayoutRelationEqual
                                                                     toItem:subviewAbove attribute:NSLayoutAttributeBottom multiplier:1.0f constant:10.0f]];
        }
        subviewAbove = subview;
    }
}

在iOS 9中，苹果通过(期待已久的)UIStackView使这变得非常容易。只需选择要包含在接口构建器中的视图，并选择编辑器->嵌入->堆栈视图。为堆栈视图设置适当的宽度/高度/边距约束，并确保将Distribution属性设置为'Equal spacing':

当然，如果你需要支持iOS 8或更低版本，你必须从其他选项中选择一个。

Android has a method of chaining views together in its constraint based layout system that I wanted to mimic. Searches brought me here but none of the answers quite worked. I didn't want to use StackViews because they tend to cause me more grief down the line than they save up front. I ended up creating a solution that used UILayoutGuides placed between the views. Controlling their width's allows different types of distributions, chain styles in Android parlance. The function accepts a leading and trailing anchor instead of a parent view. This allows the chain to be placed between two arbitrary views rather than distributed inside of the parent view. It does use UILayoutGuide which is only available in iOS 9+ but that shouldn't be a problem anymore.

public enum LayoutConstraintChainStyle {
    case spread //Evenly distribute between the anchors
    case spreadInside //Pin the first & last views to the sides and then evenly distribute
    case packed //The views have a set space but are centered between the anchors.
}

public extension NSLayoutConstraint {

    static func chainHorizontally(views: [UIView],
                                  leadingAnchor: NSLayoutXAxisAnchor,
                                  trailingAnchor: NSLayoutXAxisAnchor,
                                  spacing: CGFloat = 0.0,
                                  style: LayoutConstraintChainStyle = .spread) -> [NSLayoutConstraint] {
    var constraints = [NSLayoutConstraint]()
    guard views.count > 1 else { return constraints }
    guard let first = views.first, let last = views.last, let superview = first.superview else { return constraints }

    //Setup the chain of views
    var distributionGuides = [UILayoutGuide]()
    var previous = first
    let firstGuide = UILayoutGuide()
    superview.addLayoutGuide(firstGuide)
    distributionGuides.append(firstGuide)
    firstGuide.identifier = "ChainDistribution\(distributionGuides.count)"
    constraints.append(firstGuide.leadingAnchor.constraint(equalTo: leadingAnchor))
    constraints.append(first.leadingAnchor.constraint(equalTo: firstGuide.trailingAnchor, constant: spacing))
    views.dropFirst().forEach { view in
        let g = UILayoutGuide()
        superview.addLayoutGuide(g)
        distributionGuides.append(g)
        g.identifier = "ChainDistribution\(distributionGuides.count)"
        constraints.append(contentsOf: [
            g.leadingAnchor.constraint(equalTo: previous.trailingAnchor),
            view.leadingAnchor.constraint(equalTo: g.trailingAnchor)
        ])
        previous = view
    }
    let lastGuide = UILayoutGuide()
    superview.addLayoutGuide(lastGuide)
    constraints.append(contentsOf: [lastGuide.leadingAnchor.constraint(equalTo: last.trailingAnchor),
                                    lastGuide.trailingAnchor.constraint(equalTo: trailingAnchor)])
    distributionGuides.append(lastGuide)

    //Space the according to the style.
    switch style {
    case .packed:
        if let first = distributionGuides.first, let last = distributionGuides.last {
            constraints.append(first.widthAnchor.constraint(greaterThanOrEqualToConstant: spacing))
            constraints.append(last.widthAnchor.constraint(greaterThanOrEqualToConstant: spacing))
            constraints.append(last.widthAnchor.constraint(equalTo: first.widthAnchor))
            constraints.append(contentsOf:
                distributionGuides.dropFirst().dropLast()
                    .map { $0.widthAnchor.constraint(equalToConstant: spacing) }
                )
        }
    case .spread:
        if let first = distributionGuides.first {
            constraints.append(contentsOf:
                distributionGuides.dropFirst().map { $0.widthAnchor.constraint(equalTo: first.widthAnchor) })
        }
    case .spreadInside:
        if let first = distributionGuides.first, let last = distributionGuides.last {
            constraints.append(first.widthAnchor.constraint(equalToConstant: spacing))
            constraints.append(last.widthAnchor.constraint(equalToConstant: spacing))
            let innerGuides = distributionGuides.dropFirst().dropLast()
            if let key = innerGuides.first {
                constraints.append(contentsOf:
                    innerGuides.dropFirst().map { $0.widthAnchor.constraint(equalTo: key.widthAnchor) }
                )
            }
        }
    }

    return constraints
}

我刚刚用乘数特性解决了我的问题。我不确定它是否适用于所有情况，但对我来说，它非常有效。我在Xcode 6.3供你参考。

我最后做的是:

1)首先将我的按钮放置在320px宽度的屏幕上，以我希望它在320px设备上的方式分布。

2)然后我在所有按钮的superview上添加了一个领先的空间约束。

3)然后我修改了前导空间的属性，使常量为0，乘数是x偏移量除以屏幕宽度(例如，我的第一个按钮距离左边缘8px，所以我将乘数设置为8/320)

4)那么这里重要的一步是将约束关系中的第二个Item更改为superview。尾随而不是superview.leading。这很关键，因为superview。在我的例子中，前导为0，后拖为320，所以8/320在320px设备上是8px，然后当父视图的宽度改变为640或其他什么时，视图都以相对于320px屏幕大小的宽度的比例移动。这里的数学比较容易理解。

我也有类似的问题，发现了这篇文章。但是，目前提供的答案中没有一个能以您想要的方式解决问题。他们没有使间距相等，而是平均分配标签的中心。重要的是要明白这是不一样的。我画了一个小图来说明这一点。

有3个视图，都是20点高。使用任何建议的方法都可以均匀地分布视图的中心，并为您提供插图布局。注意，视图的y中心间隔相等。但是，父视图和顶视图之间的间距是15pt，而子视图之间的间距只有5pt。为了使视图间距相等，这两个视图的间距都应该是10pt，即所有蓝色箭头的间距都应该是10pt。

然而，我还没有想出一个好的通用解决方案。目前我最好的想法是插入“间距视图”之间的子视图和设置间距视图的高度相等。