我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
当前回答
我需要在pyparsing中使用一些符号常量来表示二进制运算符的左右结合性。我像这样使用类常量:
# an internal class, not intended to be seen by client code
class _Constants(object):
pass
# an enumeration of constants for operator associativity
opAssoc = _Constants()
opAssoc.LEFT = object()
opAssoc.RIGHT = object()
现在当客户端代码想要使用这些常量时,他们可以使用以下方法导入整个枚举:
import opAssoc from pyparsing
枚举是唯一的,它们可以用'is'而不是'=='来测试,它们不会在我的代码中占用很大的空间,而且它们很容易导入到客户端代码中。它们不支持任何花哨的str()行为,但到目前为止,这属于YAGNI类别。
其他回答
Alexandru对枚举使用类常量的建议效果很好。
我还喜欢为每组常量添加字典,以查找人类可读的字符串表示。
这有两个目的:a)它提供了一种简单的方法来漂亮地打印你的枚举;b)字典在逻辑上对常量进行分组,以便您可以测试成员关系。
class Animal:
TYPE_DOG = 1
TYPE_CAT = 2
type2str = {
TYPE_DOG: "dog",
TYPE_CAT: "cat"
}
def __init__(self, type_):
assert type_ in self.type2str.keys()
self._type = type_
def __repr__(self):
return "<%s type=%s>" % (
self.__class__.__name__, self.type2str[self._type].upper())
我喜欢Java枚举,这就是我在Python中的做法:
def enum(clsdef):
class Enum(object):
__slots__=tuple([var for var in clsdef.__dict__ if isinstance((getattr(clsdef, var)), tuple) and not var.startswith('__')])
def __new__(cls, *args, **kwargs):
if not '_the_instance' in cls.__dict__:
cls._the_instance = object.__new__(cls, *args, **kwargs)
return cls._the_instance
def __init__(self):
clsdef.values=lambda cls, e=Enum: e.values()
clsdef.valueOf=lambda cls, n, e=self: e.valueOf(n)
for ordinal, key in enumerate(self.__class__.__slots__):
args=getattr(clsdef, key)
instance=clsdef(*args)
instance._name=key
instance._ordinal=ordinal
setattr(self, key, instance)
@classmethod
def values(cls):
if not hasattr(cls, '_values'):
cls._values=[getattr(cls, name) for name in cls.__slots__]
return cls._values
def valueOf(self, name):
return getattr(self, name)
def __repr__(self):
return ''.join(['<class Enum (', clsdef.__name__, ') at ', str(hex(id(self))), '>'])
return Enum()
示例使用:
i=2
@enum
class Test(object):
A=("a",1)
B=("b",)
C=("c",2)
D=tuple()
E=("e",3)
while True:
try:
F, G, H, I, J, K, L, M, N, O=[tuple() for _ in range(i)]
break;
except ValueError:
i+=1
def __init__(self, name="default", aparam=0):
self.name=name
self.avalue=aparam
所有类变量都定义为元组,就像构造函数一样。到目前为止,还不能使用命名参数。
我使用元类来实现枚举(在我的想法中,它是一个const)。代码如下:
class ConstMeta(type):
'''
Metaclass for some class that store constants
'''
def __init__(cls, name, bases, dct):
'''
init class instance
'''
def static_attrs():
'''
@rtype: (static_attrs, static_val_set)
@return: Static attributes in dict format and static value set
'''
import types
attrs = {}
val_set = set()
#Maybe more
filter_names = set(['__doc__', '__init__', '__metaclass__', '__module__', '__main__'])
for key, value in dct.iteritems():
if type(value) != types.FunctionType and key not in filter_names:
if len(value) != 2:
raise NotImplementedError('not support for values that is not 2 elements!')
#Check value[0] duplication.
if value[0] not in val_set:
val_set.add(value[0])
else:
raise KeyError("%s 's key: %s is duplicated!" % (dict([(key, value)]), value[0]))
attrs[key] = value
return attrs, val_set
attrs, val_set = static_attrs()
#Set STATIC_ATTRS to class instance so that can reuse
setattr(cls, 'STATIC_ATTRS', attrs)
setattr(cls, 'static_val_set', val_set)
super(ConstMeta, cls).__init__(name, bases, dct)
def __getattribute__(cls, name):
'''
Rewrite the special function so as to get correct attribute value
'''
static_attrs = object.__getattribute__(cls, 'STATIC_ATTRS')
if name in static_attrs:
return static_attrs[name][0]
return object.__getattribute__(cls, name)
def static_values(cls):
'''
Put values in static attribute into a list, use the function to validate value.
@return: Set of values
'''
return cls.static_val_set
def __getitem__(cls, key):
'''
Rewrite to make syntax SomeConstClass[key] works, and return desc string of related static value.
@return: Desc string of related static value
'''
for k, v in cls.STATIC_ATTRS.iteritems():
if v[0] == key:
return v[1]
raise KeyError('Key: %s does not exists in %s !' % (str(key), repr(cls)))
class Const(object):
'''
Base class for constant class.
@usage:
Definition: (must inherit from Const class!
>>> class SomeConst(Const):
>>> STATUS_NAME_1 = (1, 'desc for the status1')
>>> STATUS_NAME_2 = (2, 'desc for the status2')
Invoke(base upper SomeConst class):
1) SomeConst.STATUS_NAME_1 returns 1
2) SomeConst[1] returns 'desc for the status1'
3) SomeConst.STATIC_ATTRS returns {'STATUS_NAME_1': (1, 'desc for the status1'), 'STATUS_NAME_2': (2, 'desc for the status2')}
4) SomeConst.static_values() returns set([1, 2])
Attention:
SomeCosnt's value 1, 2 can not be duplicated!
If WrongConst is like this, it will raise KeyError:
class WrongConst(Const):
STATUS_NAME_1 = (1, 'desc for the status1')
STATUS_NAME_2 = (1, 'desc for the status2')
'''
__metaclass__ = ConstMeta
##################################################################
#Const Base Class ends
##################################################################
def main():
class STATUS(Const):
ERROR = (-3, '??')
OK = (0, '??')
print STATUS.ERROR
print STATUS.static_values()
print STATUS.STATIC_ATTRS
#Usage sample:
user_input = 1
#Validate input:
print user_input in STATUS.static_values()
#Template render like:
print '<select>'
for key, value in STATUS.STATIC_ATTRS.items():
print '<option value="%s">%s</option>' % (value[0], value[1])
print '</select>'
if __name__ == '__main__':
main()
Python没有内置的enum,其他答案有实现自己的enum的想法(您可能也对Python烹饪书中的顶部版本感兴趣)。
然而,在C中调用枚举的情况下,我通常只使用简单的字符串:由于对象/属性的实现方式,(C)Python已经优化为使用短字符串工作得非常快,因此使用整数并没有任何性能上的好处。为了防止输入错误/无效值,可以在选定的位置插入检查。
ANIMALS = ['cat', 'dog', 'python']
def take_for_a_walk(animal):
assert animal in ANIMALS
...
(与使用类相比,一个缺点是您失去了自动完成的好处)
使用下面的方法。
TYPE = {'EAN13': u'EAN-13',
'CODE39': u'Code 39',
'CODE128': u'Code 128',
'i25': u'Interleaved 2 of 5',}
>>> TYPE.items()
[('EAN13', u'EAN-13'), ('i25', u'Interleaved 2 of 5'), ('CODE39', u'Code 39'), ('CODE128', u'Code 128')]
>>> TYPE.keys()
['EAN13', 'i25', 'CODE39', 'CODE128']
>>> TYPE.values()
[u'EAN-13', u'Interleaved 2 of 5', u'Code 39', u'Code 128']
我用它来选择Django模型,它看起来非常python化。它不是一个真正的Enum,但它完成了这项工作。