最好的解决方案取决于你需要从你的假枚举中得到什么。

简单的枚举:

如果你只需要枚举作为标识不同项目的名称列表，Mark Harrison(上图)的解决方案是很棒的:

Pen, Pencil, Eraser = range(0, 3)

使用范围还允许你设置任何起始值:

Pen, Pencil, Eraser = range(9, 12)

除此之外，如果你还要求项属于某种类型的容器，那么将它们嵌入到一个类中:

class Stationery:
    Pen, Pencil, Eraser = range(0, 3)

要使用枚举项，你现在需要使用容器名和项名:

stype = Stationery.Pen

复杂的枚举:

对于枚举的长列表或更复杂的enum使用，这些解决方案是不够的。你可以参考Will Ware在Python Cookbook中发布的关于在Python中模拟枚举的食谱。这里有一个在线版本。

更多信息:

PEP 354: Python中的枚举有关于Python中的枚举建议的有趣细节，以及为什么它被拒绝。

我使用元类来实现枚举(在我的想法中，它是一个const)。代码如下:

class ConstMeta(type):
    '''
    Metaclass for some class that store constants
    '''
    def __init__(cls, name, bases, dct):
        '''
        init class instance
        '''
        def static_attrs():
            '''
            @rtype: (static_attrs, static_val_set)
            @return: Static attributes in dict format and static value set
            '''
            import types
            attrs = {}
            val_set = set()
            #Maybe more
            filter_names = set(['__doc__', '__init__', '__metaclass__', '__module__', '__main__'])
            for key, value in dct.iteritems():
                if type(value) != types.FunctionType and key not in filter_names:
                    if len(value) != 2:
                        raise NotImplementedError('not support for values that is not 2 elements!')
                    #Check value[0] duplication.
                    if value[0] not in val_set:
                        val_set.add(value[0])
                    else:
                        raise KeyError("%s 's key: %s is duplicated!" % (dict([(key, value)]), value[0]))
                    attrs[key] = value
            return attrs, val_set

        attrs, val_set = static_attrs()
        #Set STATIC_ATTRS to class instance so that can reuse
        setattr(cls, 'STATIC_ATTRS', attrs)
        setattr(cls, 'static_val_set', val_set)
        super(ConstMeta, cls).__init__(name, bases, dct)

    def __getattribute__(cls, name):
        '''
        Rewrite the special function so as to get correct attribute value
        '''
        static_attrs = object.__getattribute__(cls, 'STATIC_ATTRS')
        if name in static_attrs:
            return static_attrs[name][0]
        return object.__getattribute__(cls, name)

    def static_values(cls):
        '''
        Put values in static attribute into a list, use the function to validate value.
        @return: Set of values
        '''
        return cls.static_val_set

    def __getitem__(cls, key):
        '''
        Rewrite to make syntax SomeConstClass[key] works, and return desc string of related static value.
        @return: Desc string of related static value
        '''
        for k, v in cls.STATIC_ATTRS.iteritems():
            if v[0] == key:
                return v[1]
        raise KeyError('Key: %s does not exists in %s !' % (str(key), repr(cls)))


class Const(object):
    '''
    Base class for constant class.

    @usage:

    Definition: (must inherit from Const class!
        >>> class SomeConst(Const):
        >>>   STATUS_NAME_1 = (1, 'desc for the status1')
        >>>   STATUS_NAME_2 = (2, 'desc for the status2')

    Invoke(base upper SomeConst class):
    1) SomeConst.STATUS_NAME_1 returns 1
    2) SomeConst[1] returns 'desc for the status1'
    3) SomeConst.STATIC_ATTRS returns {'STATUS_NAME_1': (1, 'desc for the status1'), 'STATUS_NAME_2': (2, 'desc for the status2')}
    4) SomeConst.static_values() returns set([1, 2])

    Attention:
    SomeCosnt's value 1, 2 can not be duplicated!
    If WrongConst is like this, it will raise KeyError:
    class WrongConst(Const):
        STATUS_NAME_1 = (1, 'desc for the status1')
        STATUS_NAME_2 = (1, 'desc for the status2')
    '''
    __metaclass__ = ConstMeta
##################################################################
#Const Base Class ends
##################################################################


def main():
    class STATUS(Const):
        ERROR = (-3, '??')
        OK = (0, '??')

    print STATUS.ERROR
    print STATUS.static_values()
    print STATUS.STATIC_ATTRS

    #Usage sample:
    user_input = 1
    #Validate input:
    print user_input in STATUS.static_values()
    #Template render like:
    print '<select>'
    for key, value in STATUS.STATIC_ATTRS.items():
        print '<option value="%s">%s</option>' % (value[0], value[1])
    print '</select>'


if __name__ == '__main__':
    main()

这个解决方案是获取定义为列表的枚举类的简单方法(没有更多烦人的整数赋值):

enumeration.py:

import new

def create(class_name, names):
    return new.classobj(
        class_name, (object,), dict((y, x) for x, y in enumerate(names))
    )

example.py:

import enumeration

Colors = enumeration.create('Colors', (
    'red',
    'orange',
    'yellow',
    'green',
    'blue',
    'violet',
))

我喜欢Java枚举，这就是我在Python中的做法:

def enum(clsdef):
    class Enum(object):
        __slots__=tuple([var for var in clsdef.__dict__ if isinstance((getattr(clsdef, var)), tuple) and not var.startswith('__')])

        def __new__(cls, *args, **kwargs):
            if not '_the_instance' in cls.__dict__:
                cls._the_instance = object.__new__(cls, *args, **kwargs)
            return cls._the_instance

        def __init__(self):
            clsdef.values=lambda cls, e=Enum: e.values()
            clsdef.valueOf=lambda cls, n, e=self: e.valueOf(n)
            for ordinal, key in enumerate(self.__class__.__slots__):
                args=getattr(clsdef, key)
                instance=clsdef(*args)
                instance._name=key
                instance._ordinal=ordinal
                setattr(self, key, instance)

        @classmethod
        def values(cls):
            if not hasattr(cls, '_values'):
                cls._values=[getattr(cls, name) for name in cls.__slots__]
            return cls._values

        def valueOf(self, name):
            return getattr(self, name)

        def __repr__(self):
            return ''.join(['<class Enum (', clsdef.__name__, ') at ', str(hex(id(self))), '>'])

    return Enum()

示例使用:

i=2
@enum
class Test(object):
    A=("a",1)
    B=("b",)
    C=("c",2)
    D=tuple()
    E=("e",3)

    while True:
        try:
            F, G, H, I, J, K, L, M, N, O=[tuple() for _ in range(i)]
            break;
        except ValueError:
            i+=1

    def __init__(self, name="default", aparam=0):
        self.name=name
        self.avalue=aparam

所有类变量都定义为元组，就像构造函数一样。到目前为止，还不能使用命名参数。

为什么枚举必须是整数?不幸的是，在不改变Python语言的情况下，我想不出任何好看的构造来生成它，所以我将使用字符串:

class Enumerator(object):
    def __init__(self, name):
        self.name = name

    def __eq__(self, other):
        if self.name == other:
            return True
        return self is other

    def __ne__(self, other):
        if self.name != other:
            return False
        return self is other

    def __repr__(self):
        return 'Enumerator({0})'.format(self.name)

    def __str__(self):
        return self.name

class Enum(object):
    def __init__(self, *enumerators):
        for e in enumerators:
            setattr(self, e, Enumerator(e))
    def __getitem__(self, key):
        return getattr(self, key)

也许现在更好的是，为了配置文件或其他远程输入，我们可以自然地对字符串进行测试。

例子:

class Cow(object):
    State = Enum(
        'standing',
        'walking',
        'eating',
        'mooing',
        'sleeping',
        'dead',
        'dying'
    )
    state = State.standing

In [1]: from enum import Enum

In [2]: c = Cow()

In [3]: c2 = Cow()

In [4]: c.state, c2.state
Out[4]: (Enumerator(standing), Enumerator(standing))

In [5]: c.state == c2.state
Out[5]: True

In [6]: c.State.mooing
Out[6]: Enumerator(mooing)

In [7]: c.State['mooing']
Out[7]: Enumerator(mooing)

In [8]: c.state = Cow.State.dead

In [9]: c.state == c2.state
Out[9]: False

In [10]: c.state == Cow.State.dead
Out[10]: True

In [11]: c.state == 'dead'
Out[11]: True

In [12]: c.state == Cow.State['dead']
Out[11]: True

嗯…我认为最接近枚举的应该是字典，定义如下:

months = {
    'January': 1,
    'February': 2,
    ...
}

or

months = dict(
    January=1,
    February=2,
    ...
)

然后，你可以像这样使用常量的符号名:

mymonth = months['January']

还有其他选项，如元组列表或元组的元组，但字典是唯一提供“符号”(常量字符串)方式来访问 价值。

编辑:我也喜欢亚历山大的答案!