我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。
还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。
我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。
还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。
当前回答
将“txtid”替换为您的EditText ID。
EditText txtinput;
txtinput=findViewById(R.id.txtid)
txtinput.setOnEditorActionListener(new TextView.OnEditorActionListener() {
@Override
public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
if ((event != null && (event.getKeyCode() == KeyEvent.KEYCODE_ENTER)) || (actionId == EditorInfo.IME_ACTION_DONE)) {
//Code for the action you want to proceed with.
InputMethodManager inputManager = (InputMethodManager)
getSystemService(Context.INPUT_METHOD_SERVICE);
inputManager.hideSoftInputFromWindow(getCurrentFocus().getWindowToken(),
InputMethodManager.HIDE_NOT_ALWAYS);
}
return false;
}
});
其他回答
本页详细描述了如何做到这一点。
https://developer.android.com/training/keyboard-input/style.html
设置android:imeOptions,然后检查onEditorAction中的actionId。因此,如果你设置imeOptions为“actionDone”,那么你会检查“actionId == EditorInfo”。onEditorAction中的IME_ACTION_DONE `。另外,确保设置android:inputType。
如果使用材质设计,将代码放在TextInputEditText中。
下面是上面链接的例子中的EditText:
<EditText
android:id="@+id/search"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:hint="@string/search_hint"
android:inputType="text"
android:imeOptions="actionSend" />
您还可以使用setImeOptions(int)函数以编程方式设置此选项。下面是上面链接的例子中的OnEditorActionListener:
EditText editText = (EditText) findViewById(R.id.search);
editText.setOnEditorActionListener(new OnEditorActionListener() {
@Override
public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
boolean handled = false;
if (actionId == EditorInfo.IME_ACTION_SEND) {
sendMessage();
handled = true;
}
return handled;
}
});
final EditText edittext = (EditText) findViewById(R.id.edittext);
edittext.setOnKeyListener(new OnKeyListener() {
public boolean onKey(View v, int keyCode, KeyEvent event) {
// If the event is a key-down event on the "enter" button
if ((event.getAction() == KeyEvent.ACTION_DOWN) &&
(keyCode == KeyEvent.KEYCODE_ENTER)) {
// Perform action on key press
Toast.makeText(HelloFormStuff.this, edittext.getText(), Toast.LENGTH_SHORT).show();
return true;
}
return false;
}
});
这应该可以
input.addTextChangedListener(new TextWatcher() {
@Override
public void afterTextChanged(Editable s) {}
@Override
public void beforeTextChanged(CharSequence s, int start,
int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start,
int before, int count) {
if( -1 != input.getText().toString().indexOf( "\n" ) ){
input.setText("Enter was pressed!");
}
}
});
I had a similar purpose. I wanted to resolve pressing the "Enter" key on the keyboard (which I wanted to customize) in an AutoCompleteTextView which extends TextView. I tried different solutions from above and they seemed to work. BUT I experienced some problems when I switched the input type on my device (Nexus 4 with AOKP ROM) from SwiftKey 3 (where it worked perfectly) to the standard Android keyboard (where instead of handling my code from the listener, a new line was entered after pressing the "Enter" key. It took me a while to handle this problem, but I don't know if it will work under all circumstances no matter which input type you use.
这是我的解决方案:
在xml中设置TextView的输入类型属性为"text":
android:inputType="text"
自定义键盘上“Enter”键的标签:
myTextView.setImeActionLabel("Custom text", KeyEvent.KEYCODE_ENTER);
将OnEditorActionListener设置为TextView:
myTextView.setOnEditorActionListener(new OnEditorActionListener()
{
@Override
public boolean onEditorAction(TextView v, int actionId,
KeyEvent event)
{
boolean handled = false;
if (event.getAction() == KeyEvent.KEYCODE_ENTER)
{
// Handle pressing "Enter" key here
handled = true;
}
return handled;
}
});
我希望这能帮助其他人避免我遇到的问题,因为它们几乎把我逼疯了。
我知道这已经有一年了,但我刚刚发现这非常适合EditText。
EditText textin = (EditText) findViewById(R.id.editText1);
textin.setInputType(InputType.TYPE_CLASS_TEXT);
除了文本和空格,它可以阻止任何东西。我不能制表,“返回”(“\n”),或任何东西。