这将在用户按下返回键时为您提供一个可调用的函数。

fun EditText.setLineBreakListener(onLineBreak: () -> Unit) {
    val lineBreak = "\n"
    doOnTextChanged { text, _, _, _ ->
        val currentText = text.toString()

        // Check if text contains a line break
        if (currentText.contains(lineBreak)) {

            // Uncommenting the lines below will remove the line break from the string
            // and set the cursor back to the end of the line

            // val cleanedString = currentText.replace(lineBreak, "")
            // setText(cleanedString)
            // setSelection(cleanedString.length)

            onLineBreak()
        }
    }
}

使用

editText.setLineBreakListener {
    doSomething()
}

我想知道是否有办法 处理用户按Enter键时 输入EditText之类的 onSubmit HTML事件。

是的。

也在想有没有办法 操作虚拟键盘 就像“完成”按钮一样 标记其他东西(例如 “Go”)并执行某个动作 当点击(再次，像onSubmit)。

也没错。

你会想看看android:imeActionId和android:imeOptions属性，加上setOnEditorActionListener()方法，所有的TextView。

要将“Done”按钮的文本更改为自定义字符串，请使用:

mEditText.setImeActionLabel("Custom text", KeyEvent.KEYCODE_ENTER);

A dependable way to respond to an <enter> in an EditText is with a TextWatcher, a LocalBroadcastManager, and a BroadcastReceiver. You need to add the v4 support library to use the LocalBroadcastManager. I use the tutorial at vogella.com: 7.3 "Local broadcast events with LocalBroadcastManager" because of its complete concise code Example. In onTextChanged before is the index of the end of the change before the change>;minus start. When in the TextWatcher the UI thread is busy updating editText's editable, so we send an Intent to wake up the BroadcastReceiver when the UI thread is done updating editText.

import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.text.Editable;
//in onCreate:
editText.addTextChangedListener(new TextWatcher() {
  public void onTextChanged
  (CharSequence s, int start, int before, int count) {
    //check if exactly one char was added and it was an <enter>
    if (before==0 && count==1 && s.charAt(start)=='\n') {
    Intent intent=new Intent("enter")
    Integer startInteger=new Integer(start);
    intent.putExtra("Start", startInteger.toString()); // Add data
    mySendBroadcast(intent);
//in the BroadcastReceiver's onReceive:
int start=Integer.parseInt(intent.getStringExtra("Start"));
editText.getText().replace(start, start+1,""); //remove the <enter>
//respond to the <enter> here

本页详细描述了如何做到这一点。

https://developer.android.com/training/keyboard-input/style.html

设置android:imeOptions，然后检查onEditorAction中的actionId。因此，如果你设置imeOptions为“actionDone”，那么你会检查“actionId == EditorInfo”。onEditorAction中的IME_ACTION_DONE `。另外，确保设置android:inputType。

如果使用材质设计，将代码放在TextInputEditText中。

下面是上面链接的例子中的EditText:

<EditText
    android:id="@+id/search"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:hint="@string/search_hint"
    android:inputType="text"
    android:imeOptions="actionSend" />

您还可以使用setImeOptions(int)函数以编程方式设置此选项。下面是上面链接的例子中的OnEditorActionListener:

EditText editText = (EditText) findViewById(R.id.search);
editText.setOnEditorActionListener(new OnEditorActionListener() {
    @Override
    public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
        boolean handled = false;
        if (actionId == EditorInfo.IME_ACTION_SEND) {
            sendMessage();
            handled = true;
        }
        return handled;
    }
});

Kotlin解决方案的反应进入按使用Lambda表达式:

        editText.setOnKeyListener { _, keyCode, event ->
            if(keyCode == KeyEvent.KEYCODE_ENTER && event.action==KeyEvent.ACTION_DOWN){
            //react to enter press here
            }
            true
        }

不做额外的检查类型的事件将导致这个监听器被调用两次时按一次(一次为ACTION_DOWN，一次为ACTION_UP)

     password.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            if(event != null && event.getKeyCode() == KeyEvent.KEYCODE_ENTER && event.getAction() == KeyEvent.ACTION_DOWN) {
                InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
                imm.toggleSoftInput(InputMethodManager.SHOW_IMPLICIT, 0);
                submit.performClick();
                return true;
            }
            return false;
        }
    });

对我来说很好 另外隐藏键盘