我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。
还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。
我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。
还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。
当前回答
好吧,如果这些答案都对你不起作用,你还没生气,我有一个解决办法。 使用AppCompatMultiAutoCompleteTextView(是的!)而不是EditText与以下代码(kotlin)
val filter = InputFilter { source, start, end, _, _, _ ->
var keepOriginal = true
val sb = StringBuilder(end - start)
for (i in start until end) {
val c = source[i]
if (c != '\n')
sb.append(c)
else {
keepOriginal = false
//TODO:WRITE YOUR CODE HERE
}
}
if (keepOriginal) null else {
if (source is Spanned) {
val sp = SpannableString(sb)
TextUtils.copySpansFrom(source, start, sb.length, null, sp, 0)
sp
} else {
sb
}
}
}
appCompatMultiAutoCompleteTextView.filters = arrayOf(filter);
它(可能)适用于所有设备,我在android 4.4和10上测试了它。它在小米中也起作用。 我他妈的♥机器人:)
其他回答
我知道这已经有一年了,但我刚刚发现这非常适合EditText。
EditText textin = (EditText) findViewById(R.id.editText1);
textin.setInputType(InputType.TYPE_CLASS_TEXT);
除了文本和空格,它可以阻止任何东西。我不能制表,“返回”(“\n”),或任何东西。
在编辑器中键入这段代码,以便它可以导入必要的模块。
query.setOnEditorActionListener(new TextView.OnEditorActionListener() {
@Override
public boolean onEditorAction(TextView textView, int actionId, KeyEvent keyEvent) {
if(actionId == EditorInfo.IME_ACTION_DONE
|| keyEvent.getAction() == KeyEvent.ACTION_DOWN
|| keyEvent.getAction() == KeyEvent.KEYCODE_ENTER) {
// Put your function here ---!
return true;
}
return false;
}
});
I had a similar purpose. I wanted to resolve pressing the "Enter" key on the keyboard (which I wanted to customize) in an AutoCompleteTextView which extends TextView. I tried different solutions from above and they seemed to work. BUT I experienced some problems when I switched the input type on my device (Nexus 4 with AOKP ROM) from SwiftKey 3 (where it worked perfectly) to the standard Android keyboard (where instead of handling my code from the listener, a new line was entered after pressing the "Enter" key. It took me a while to handle this problem, but I don't know if it will work under all circumstances no matter which input type you use.
这是我的解决方案:
在xml中设置TextView的输入类型属性为"text":
android:inputType="text"
自定义键盘上“Enter”键的标签:
myTextView.setImeActionLabel("Custom text", KeyEvent.KEYCODE_ENTER);
将OnEditorActionListener设置为TextView:
myTextView.setOnEditorActionListener(new OnEditorActionListener()
{
@Override
public boolean onEditorAction(TextView v, int actionId,
KeyEvent event)
{
boolean handled = false;
if (event.getAction() == KeyEvent.KEYCODE_ENTER)
{
// Handle pressing "Enter" key here
handled = true;
}
return handled;
}
});
我希望这能帮助其他人避免我遇到的问题,因为它们几乎把我逼疯了。
password.setOnEditorActionListener(new TextView.OnEditorActionListener() {
public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
if(event != null && event.getKeyCode() == KeyEvent.KEYCODE_ENTER && event.getAction() == KeyEvent.ACTION_DOWN) {
InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
imm.toggleSoftInput(InputMethodManager.SHOW_IMPLICIT, 0);
submit.performClick();
return true;
}
return false;
}
});
对我来说很好 另外隐藏键盘
A dependable way to respond to an <enter> in an EditText is with a TextWatcher, a LocalBroadcastManager, and a BroadcastReceiver. You need to add the v4 support library to use the LocalBroadcastManager. I use the tutorial at vogella.com: 7.3 "Local broadcast events with LocalBroadcastManager" because of its complete concise code Example. In onTextChanged before is the index of the end of the change before the change>;minus start. When in the TextWatcher the UI thread is busy updating editText's editable, so we send an Intent to wake up the BroadcastReceiver when the UI thread is done updating editText.
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.text.Editable;
//in onCreate:
editText.addTextChangedListener(new TextWatcher() {
public void onTextChanged
(CharSequence s, int start, int before, int count) {
//check if exactly one char was added and it was an <enter>
if (before==0 && count==1 && s.charAt(start)=='\n') {
Intent intent=new Intent("enter")
Integer startInteger=new Integer(start);
intent.putExtra("Start", startInteger.toString()); // Add data
mySendBroadcast(intent);
//in the BroadcastReceiver's onReceive:
int start=Integer.parseInt(intent.getStringExtra("Start"));
editText.getText().replace(start, start+1,""); //remove the <enter>
//respond to the <enter> here