我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。

还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。


当前回答

完美的工作

public class MainActivity extends AppCompatActivity {  
TextView t;
Button b;
EditText e;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    b = (Button) findViewById(R.id.b);
    e = (EditText) findViewById(R.id.e);

    e.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

            if (before == 0 && count == 1 && s.charAt(start) == '\n') {

                b.performClick();
                e.getText().replace(start, start + 1, ""); //remove the <enter>
            }

        }
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {}
        @Override
        public void afterTextChanged(Editable s) {}
    });

    b.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            b.setText("ok");

        }
    });
}

}

完美的工作

其他回答

完美的工作

public class MainActivity extends AppCompatActivity {  
TextView t;
Button b;
EditText e;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    b = (Button) findViewById(R.id.b);
    e = (EditText) findViewById(R.id.e);

    e.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

            if (before == 0 && count == 1 && s.charAt(start) == '\n') {

                b.performClick();
                e.getText().replace(start, start + 1, ""); //remove the <enter>
            }

        }
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {}
        @Override
        public void afterTextChanged(Editable s) {}
    });

    b.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            b.setText("ok");

        }
    });
}

}

完美的工作

作为Chad响应的补充(对我来说几乎完美),我发现我需要在KeyEvent操作类型上添加一个检查,以防止代码执行两次(一次在key-up事件上执行,一次在key-down事件上执行)。

if (actionId == EditorInfo.IME_NULL && event.getAction() == KeyEvent.ACTION_DOWN)
{
    // your code here
}

有关重复动作事件(按住enter键)的信息,请参见http://developer.android.com/reference/android/view/KeyEvent.html。

editText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            if (actionId != 0 || event.getAction() == KeyEvent.ACTION_DOWN) {
                // Action
                return true;
            } else {
                return false;
            }
        }
    });

Xml

<EditText
        android:id="@+id/editText2"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:hint="@string/password"
        android:imeOptions="actionGo|flagNoFullscreen"
        android:inputType="textPassword"
        android:maxLines="1" />

如果使用DataBinding,请参见https://stackoverflow.com/a/52902266/2914140和https://stackoverflow.com/a/67933283/2914140。

Bindings.kt:

@BindingAdapter("onEditorEnterAction")
fun EditText.onEditorEnterAction(callback: OnActionListener?) {
    if (callback == null) setOnEditorActionListener(null)
    else setOnEditorActionListener { v, actionId, event ->
        val imeAction = when (actionId) {
            EditorInfo.IME_ACTION_DONE,
            EditorInfo.IME_ACTION_SEND,
            EditorInfo.IME_ACTION_GO -> true
            else -> false
        }

        val keydownEvent = event?.keyCode == KeyEvent.KEYCODE_ENTER 
            && event.action == KeyEvent.ACTION_DOWN

        if (imeAction or keydownEvent) {
            callback.enterPressed()
            return@setOnEditorActionListener true
        }
        return@setOnEditorActionListener false
    }
}

interface OnActionListener {
    fun enterPressed()
}

layout.xml:

<data>
    <variable
        name="viewModel"
        type="YourViewModel" />
</data>    

<EditText
    android:imeOptions="actionDone|actionSend|actionGo"
    android:singleLine="true"
    android:text="@={viewModel.message}"
    app:onEditorEnterAction="@{() -> viewModel.send()}" />

I had a similar purpose. I wanted to resolve pressing the "Enter" key on the keyboard (which I wanted to customize) in an AutoCompleteTextView which extends TextView. I tried different solutions from above and they seemed to work. BUT I experienced some problems when I switched the input type on my device (Nexus 4 with AOKP ROM) from SwiftKey 3 (where it worked perfectly) to the standard Android keyboard (where instead of handling my code from the listener, a new line was entered after pressing the "Enter" key. It took me a while to handle this problem, but I don't know if it will work under all circumstances no matter which input type you use.

这是我的解决方案:

在xml中设置TextView的输入类型属性为"text":

android:inputType="text"

自定义键盘上“Enter”键的标签:

myTextView.setImeActionLabel("Custom text", KeyEvent.KEYCODE_ENTER);

将OnEditorActionListener设置为TextView:

myTextView.setOnEditorActionListener(new OnEditorActionListener()
{
    @Override
    public boolean onEditorAction(TextView v, int actionId,
        KeyEvent event)
    {
    boolean handled = false;
    if (event.getAction() == KeyEvent.KEYCODE_ENTER)
    {
        // Handle pressing "Enter" key here

        handled = true;
    }
    return handled;
    }
});

我希望这能帮助其他人避免我遇到的问题,因为它们几乎把我逼疯了。