最简单的java方法是:在你的pojo/model类中实现serializable

推荐用于Android的性能视图:使模型可封装

你可以通过intent发送可序列化对象

// send where details is object
ClassName details = new ClassName();
Intent i = new Intent(context, EditActivity.class);
i.putExtra("Editing", details);
startActivity(i);


//receive
ClassName model = (ClassName) getIntent().getSerializableExtra("Editing");

And 

Class ClassName implements Serializable {
} 

快速需求的简短回答

1. 将类实现为可序列化的。

如果你有任何内部类，不要忘记将它们实现为Serializable !!

public class SportsData implements  Serializable
public class Sport implements  Serializable

List<Sport> clickedObj;

2. 将你的对象放入Intent中

 Intent intent = new Intent(SportsAct.this, SportSubAct.class);
            intent.putExtra("sport", clickedObj);
            startActivity(intent);

3.并在另一个活动类中接收您的对象

Intent intent = getIntent();
    Sport cust = (Sport) intent.getSerializableExtra("sport");

你可以使用putExtra(Serializable..)和getSerializableExtra()方法来传递和检索你的类类型的对象;你必须将你的类标记为Serializable，并确保你所有的成员变量也是Serializable…

We can send data one Activty1 to Activity2 with multiple ways like.
1- Intent
2- bundle
3- create an object and send through intent
.................................................
1 - Using intent
Pass the data through intent
Intent intentActivity1 = new Intent(Activity1.this, Activity2.class);
intentActivity1.putExtra("name", "Android");
startActivity(intentActivity1);
Get the data in Activity2 calss
Intent intent = getIntent();
if(intent.hasExtra("name")){
     String userName = getIntent().getStringExtra("name");
}
..................................................
2- Using Bundle
Intent intentActivity1 = new Intent(Activity1.this, Activity2.class);
Bundle bundle = new Bundle();
bundle.putExtra("name", "Android");
intentActivity1.putExtra(bundle);
startActivity(bundle);
Get the data in Activity2 calss
Intent intent = getIntent();
if(intent.hasExtra("name")){
     String userName = getIntent().getStringExtra("name");
}
..................................................
3-  Put your Object into Intent
Intent intentActivity1 = new Intent(Activity1.this, Activity2.class);
            intentActivity1.putExtra("myobject", myObject);
            startActivity(intentActivity1); 
 Receive object in the Activity2 Class
Intent intent = getIntent();
    Myobject obj  = (Myobject) intent.getSerializableExtra("myobject");

在类中实现serializable

public class Place implements Serializable{
        private int id;
        private String name;

        public void setId(int id) {
           this.id = id;
        }
        public int getId() {
           return id;
        }
        public String getName() {
           return name;
        }

        public void setName(String name) {
           this.name = name;
        }
}

然后你可以意图传递这个对象

     Intent intent = new Intent(this, SecondAct.class);
     intent.putExtra("PLACE", Place);
     startActivity(intent);

在第二个活动中，你可以得到这样的数据

     Place place= (Place) getIntent().getSerializableExtra("PLACE");

但是当数据量变大时，这种方法会变慢。