I wanted to add a comment but I have less than 50 pts so I can only "Answer". Be aware that if you use the "VisualTreeHelper" method to retrieve XAML "TextBlock" objects then it will also grab XAML "Button" objects. If you re-initialize the "TextBlock" object by writing to the Textblock.Text parameter then you will no longer be able to change the Button text using the Button.Content parameter. The Button will permanently show the text written to it from the Textblock.Text write action (from when it was retrieved --

foreach (TextBlock tb in FindVisualChildren<TextBlock>(window))
{
// do something with tb here
   tb.Text = ""; //this will overwrite Button.Content and render the 
                 //Button.Content{set} permanently disabled.
}

要解决这个问题，您可以尝试使用XAML“文本框”并添加方法(或事件)来模拟XAMAL按钮。XAML“TextBox”不是通过搜索“TextBlock”收集的。

这应该可以达到目的:

public static IEnumerable<T> FindVisualChilds<T>(DependencyObject depObj) where T : DependencyObject
{
    if (depObj == null) yield return (T)Enumerable.Empty<T>();
    for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
    {
        DependencyObject ithChild = VisualTreeHelper.GetChild(depObj, i);
        if (ithChild == null) continue;
        if (ithChild is T t) yield return t;
        foreach (T childOfChild in FindVisualChilds<T>(ithChild)) yield return childOfChild;
    }
}

然后像这样枚举控件

foreach (TextBlock tb in FindVisualChildren<TextBlock>(window))
{
    // do something with tb here
}

这是最简单的方法:

IEnumerable<myType> collection = control.Children.OfType<myType>(); 

其中控件是窗口的根元素。

编辑-正如评论中指出的那样。这只是一个层次的深度。查看一个更深入的选项的公认答案。

这就是它向上的工作原理

    private T FindParent<T>(DependencyObject item, Type StopAt) where T : class
    {
        if (item is T)
        {
            return item as T;
        }
        else
        {
            DependencyObject _parent = VisualTreeHelper.GetParent(item);
            if (_parent == null)
            {
                return default(T);
            }
            else
            {
                Type _type = _parent.GetType();
                if (StopAt != null)
                {
                    if ((_type.IsSubclassOf(StopAt) == true) || (_type == StopAt))
                    {
                        return null;
                    }
                }

                if ((_type.IsSubclassOf(typeof(T)) == true) || (_type == typeof(T)))
                {
                    return _parent as T;
                }
                else
                {
                    return FindParent<T>(_parent, StopAt);
                }
            }
        }
    }

我根据@Mathias Lykkegaard Lorenzen的建议改编了@Bryce Kahle的回答，并使用了LogicalTreeHelper。

看起来还行。；）

public static IEnumerable<T> FindLogicalChildren<T> ( DependencyObject depObj ) where T : DependencyObject
{
    if( depObj != null )
    {
        foreach( object rawChild in LogicalTreeHelper.GetChildren( depObj ) )
        {
            if( rawChild is DependencyObject )
            {
                DependencyObject child = (DependencyObject)rawChild;
                if( child is T )
                {
                    yield return (T)child;
                }

                foreach( T childOfChild in FindLogicalChildren<T>( child ) ) 
                {
                    yield return childOfChild;
                }
            }
        }
    }
}

(它仍然不会检查@Benjamin Berry和@David R分别提到的组框中的选项卡控件或网格。) (也遵循@noonand的建议&删除多余的子!= null)

对递归做了一点小小的改变，例如，你可以找到一个标签控件的子标签控件。

    public static DependencyObject FindInVisualTreeDown(DependencyObject obj, Type type)
    {
        if (obj != null)
        {
            for (int i = 0; i < VisualTreeHelper.GetChildrenCount(obj); i++)
            {
                DependencyObject child = VisualTreeHelper.GetChild(obj, i);

                if (child.GetType() == type)
                {
                    return child;
                }

                DependencyObject childReturn = FindInVisualTreeDown(child, type);
                if (childReturn != null)
                {
                    return childReturn;
                }
            }
        }

        return null;
    }