我有一个循环,开头为for I,范围为(0,100)。正常情况下,它可以正常运行,但有时由于网络条件而出现故障。目前,我已经设置它,以便在失败时,它将继续在except子句中(继续到I的下一个数字)。
我是否可以将相同的数字重新分配给i,并再次运行失败的循环迭代?
我有一个循环,开头为for I,范围为(0,100)。正常情况下,它可以正常运行,但有时由于网络条件而出现故障。目前,我已经设置它,以便在失败时,它将继续在except子句中(继续到I的下一个数字)。
我是否可以将相同的数字重新分配给i,并再次运行失败的循环迭代?
当前回答
尝试次数= 3 而尝试: 试一试: ... ... <状态好了> 打破 除了: 尝试- = 1 Else: #已执行的唯一break未被引发 < >失败状态
其他回答
Decorator是一个很好的方法。
from functools import wraps
import time
class retry:
def __init__(self, success=lambda r:True, times=3, delay=1, raiseexception=True, echo=True):
self.success = success
self.times = times
self.raiseexception = raiseexception
self.echo = echo
self.delay = delay
def retry(fun, *args, success=lambda r:True, times=3, delay=1, raiseexception=True, echo=True, **kwargs):
ex = Exception(f"{fun} failed.")
r = None
for i in range(times):
if i > 0:
time.sleep(delay*2**(i-1))
try:
r = fun(*args, **kwargs)
s = success(r)
except Exception as e:
s = False
ex = e
# raise e
if not s:
continue
return r
else:
if echo:
print(f"{fun} failed.", "args:", args, kwargs, "\nresult: %s"%r)
if raiseexception:
raise ex
def __call__(self, fun):
@wraps(fun)
def wraper(*args, retry=0, **kwargs):
retry = retry if retry>0 else self.times
return self.__class__.retry(fun, *args,
success=self.success,
times=retry,
delay=self.delay,
raiseexception = self.raiseexception,
echo = self.echo,
**kwargs)
return wraper
一些用法示例:
@retry(success=lambda x:x>3, times=4, delay=0.1)
def rf1(x=[]):
x.append(1)
print(x)
return len(x)
> rf1()
[1]
[1, 1]
[1, 1, 1]
[1, 1, 1, 1]
4
@retry(success=lambda x:x>3, times=4, delay=0.1)
def rf2(l=[], v=1):
l.append(v)
print(l)
assert len(l)>4
return len(l)
> rf2(v=2, retry=10) #overwite times=4
[2]
[2, 2]
[2, 2, 2]
[2, 2, 2, 2]
[2, 2, 2, 2, 2]
5
> retry.retry(lambda a,b:a+b, 1, 2, times=2)
3
> retry.retry(lambda a,b:a+b, 1, "2", times=2)
TypeError: unsupported operand type(s) for +: 'int' and 'str'
如果你想要一个没有嵌套循环和成功调用break的解决方案,你可以为任何可迭代对象开发一个快速的可检索包装。这里有一个我经常遇到的网络问题的例子——保存的身份验证过期。它的用法是这样的:
client = get_client()
smart_loop = retriable(list_of_values):
for value in smart_loop:
try:
client.do_something_with(value)
except ClientAuthExpired:
client = get_client()
smart_loop.retry()
continue
except NetworkTimeout:
smart_loop.retry()
continue
使用递归
for i in range(100):
def do():
try:
## Network related scripts
except SpecificException as ex:
do()
do() ## invoke do() whenever required inside this loop
我喜欢laurent-laporte的回答。下面是我的版本,它包装在一个类与静态方法和一些例子。我实现了重试计数作为另一种重试方式。还增加了kwargs。
from typing import List
import time
class Retry:
@staticmethod
def onerror_retry(exception, callback, retries: int = 0, timeout: float = 0, timedelta: float = 0,
errors: List = None, **kwargs):
"""
@param exception: The exception to trigger retry handling with.
@param callback: The function that will potentially fail with an exception
@param retries: Optional total number of retries, regardless of timing if this threshold is met, the call will
raise the exception.
@param timeout: Optional total amount of time to do retries after which the call will raise an exception
@param timedelta: Optional amount of time to sleep in between calls
@param errors: A list to receive all the exceptions that were caught.
@param kwargs: An optional key value parameters to pass to the function to retry.
"""
for retry in Retry.__onerror_retry(exception, callback, retries, timeout, timedelta, errors, **kwargs):
if retry: retry(**kwargs) # retry will be None when all retries fail.
@staticmethod
def __onerror_retry(exception, callback, retries: int = 0, timeout: float = 0, timedelta: float = 0,
errors: List = None, **kwargs):
end_time = time.time() + timeout
continues = 0
while True:
try:
yield callback(**kwargs)
break
except exception as ex:
print(ex)
if errors:
errors.append(ex)
continues += 1
if 0 < retries < continues:
print('ran out of retries')
raise
if timeout > 0 and time.time() > end_time:
print('ran out of time')
raise
elif timedelta > 0:
time.sleep(timedelta)
err = 0
#
# sample dumb fail function
def fail_many_times(**kwargs):
global err
err += 1
max_errors = kwargs.pop('max_errors', '') or 1
if err < max_errors:
raise ValueError("I made boo boo.")
print("Successfully did something.")
#
# Example calls
try:
#
# retries with a parameter that overrides retries... just because
Retry.onerror_retry(ValueError, fail_many_times, retries=5, max_errors=3)
err = 0
#
# retries that run out of time, with 1 second sleep between retries.
Retry.onerror_retry(ValueError, fail_many_times, timeout=5, timedelta=1, max_errors=30)
except Exception as err:
print(err)
你可以使用Python重试包。 重试
它是用Python编写的,目的是简化向几乎任何东西添加重试行为的任务。