如何在Python中从字典中删除项目?
在不修改原始词典的情况下,如何获取删除了该项的另一个词典?
如何在Python中从字典中删除项目?
在不修改原始词典的情况下,如何获取删除了该项的另一个词典?
当前回答
# mutate/remove with a default
ret_val = body.pop('key', 5)
# no mutation with a default
ret_val = body.get('key', 5)
其他回答
# mutate/remove with a default
ret_val = body.pop('key', 5)
# no mutation with a default
ret_val = body.get('key', 5)
下面的代码片段肯定会帮助您,我在每行中都添加了注释,这将帮助您理解代码。
def execute():
dic = {'a':1,'b':2}
dic2 = remove_key_from_dict(dic, 'b')
print(dict2) # {'a': 1}
print(dict) # {'a':1,'b':2}
def remove_key_from_dict(dictionary_to_use, key_to_delete):
copy_of_dict = dict(dictionary_to_use) # creating clone/copy of the dictionary
if key_to_delete in copy_of_dict : # checking given key is present in the dictionary
del copy_of_dict [key_to_delete] # deleting the key from the dictionary
return copy_of_dict # returning the final dictionary
或者也可以使用dict.pop()
d = {"a": 1, "b": 2}
res = d.pop("c") # No `KeyError` here
print (res) # this line will not execute
或者更好的方法是
res = d.pop("c", "key not found")
print (res) # key not found
print (d) # {"a": 1, "b": 2}
res = d.pop("b", "key not found")
print (res) # 2
print (d) # {"a": 1}
d = {1: 2, '2': 3, 5: 7}
del d[5]
print 'd = ', d
结果:d={1:2,“2”:3}
这里是顶级设计方法:
def eraseElement(d,k):
if isinstance(d, dict):
if k in d:
d.pop(k)
print(d)
else:
print("Cannot find matching key")
else:
print("Not able to delete")
exp = {'A':34, 'B':55, 'C':87}
eraseElement(exp, 'C')
我将字典和我想要的键传递到我的函数中,验证它是否是字典,以及键是否正常,如果两者都存在,则从字典中删除值并打印出剩余的值。
输出:{“B”:55,“A”:34}
希望这有帮助!
pop改变了字典。
>>> lol = {"hello": "gdbye"}
>>> lol.pop("hello")
'gdbye'
>>> lol
{}
如果你想保留原件,你可以复制它。