这个C/ c++代码在Python中的等效代码是什么?
void foo()
{
static int counter = 0;
counter++;
printf("counter is %d\n", counter);
}
具体来说,如何在函数级别实现静态成员,而不是在类级别?将函数放入类中会改变什么吗?
这个C/ c++代码在Python中的等效代码是什么?
void foo()
{
static int counter = 0;
counter++;
printf("counter is %d\n", counter);
}
具体来说,如何在函数级别实现静态成员,而不是在类级别?将函数放入类中会改变什么吗?
当前回答
惯用的方法是使用类,类可以有属性。如果您需要实例不分离,请使用单例。
有许多方法可以将“静态”变量伪造或蒙骗到Python中(到目前为止没有提到的一种方法是使用可变的默认参数),但这不是Python的惯用方法。只需要使用一个类。
如果您的使用模式合适,也可以使用生成器。
其他回答
许多人已经建议测试“hasattr”,但有一个更简单的答案:
def func():
func.counter = getattr(func, 'counter', 0) + 1
没有try/except,没有测试hasattr,只有默认的getattr。
Python没有静态变量,但你可以通过定义一个可调用的类对象,然后将其用作函数来伪装它。也可以看看这个答案。
class Foo(object):
# Class variable, shared by all instances of this class
counter = 0
def __call__(self):
Foo.counter += 1
print Foo.counter
# Create an object instance of class "Foo," called "foo"
foo = Foo()
# Make calls to the "__call__" method, via the object's name itself
foo() #prints 1
foo() #prints 2
foo() #prints 3
注意,__call__使类(对象)的实例可以通过自己的名称调用。这就是为什么上面调用foo()会调用类的__call__方法。从文档中可以看到:
任意类的实例都可以通过在类中定义__call__()方法来实现可调用。
在尝试了几种方法后,我最终使用了@warvariuc的答案的改进版本:
import types
def func(_static=types.SimpleNamespace(counter=0)):
_static.counter += 1
print(_static.counter)
我个人更喜欢下面的装饰。各有各的。
def staticize(name, factory):
"""Makes a pseudo-static variable in calling function.
If name `name` exists in calling function, return it.
Otherwise, saves return value of `factory()` in
name `name` of calling function and return it.
:param name: name to use to store static object
in calling function
:type name: String
:param factory: used to initialize name `name`
in calling function
:type factory: function
:rtype: `type(factory())`
>>> def steveholt(z):
... a = staticize('a', list)
... a.append(z)
>>> steveholt.a
Traceback (most recent call last):
...
AttributeError: 'function' object has no attribute 'a'
>>> steveholt(1)
>>> steveholt.a
[1]
>>> steveholt('a')
>>> steveholt.a
[1, 'a']
>>> steveholt.a = []
>>> steveholt.a
[]
>>> steveholt('zzz')
>>> steveholt.a
['zzz']
"""
from inspect import stack
# get scope enclosing calling function
calling_fn_scope = stack()[2][0]
# get calling function
calling_fn_name = stack()[1][3]
calling_fn = calling_fn_scope.f_locals[calling_fn_name]
if not hasattr(calling_fn, name):
setattr(calling_fn, name, factory())
return getattr(calling_fn, name)
鉴于这个问题,我可以提出另一个可能更好用的替代方案,对方法和函数看起来都是一样的:
@static_var2('seed',0)
def funccounter(statics, add=1):
statics.seed += add
return statics.seed
print funccounter() #1
print funccounter(add=2) #3
print funccounter() #4
class ACircle(object):
@static_var2('seed',0)
def counter(statics, self, add=1):
statics.seed += add
return statics.seed
c = ACircle()
print c.counter() #1
print c.counter(add=2) #3
print c.counter() #4
d = ACircle()
print d.counter() #5
print d.counter(add=2) #7
print d.counter() #8
如果你喜欢这种用法,下面是它的实现:
class StaticMan(object):
def __init__(self):
self.__dict__['_d'] = {}
def __getattr__(self, name):
return self.__dict__['_d'][name]
def __getitem__(self, name):
return self.__dict__['_d'][name]
def __setattr__(self, name, val):
self.__dict__['_d'][name] = val
def __setitem__(self, name, val):
self.__dict__['_d'][name] = val
def static_var2(name, val):
def decorator(original):
if not hasattr(original, ':staticman'):
def wrapped(*args, **kwargs):
return original(getattr(wrapped, ':staticman'), *args, **kwargs)
setattr(wrapped, ':staticman', StaticMan())
f = wrapped
else:
f = original #already wrapped
getattr(f, ':staticman')[name] = val
return f
return decorator