如果我有对象的引用:
var test = {};
可能(但不是立即)具有嵌套对象,例如:
{level1: {level2: {level3: "level3"}}};
检查深度嵌套对象中是否存在属性的最佳方法是什么?
警报(测试级别1);生成未定义,但警告(test.level1.level2.level3);失败。
我目前正在做这样的事情:
if(test.level1 && test.level1.level2 && test.level1.level2.level3) {
alert(test.level1.level2.level3);
}
但我想知道是否有更好的方法。
这个功能怎么样?它不需要单独列出每个嵌套属性,而是保持“dot”语法(尽管是字符串),使其更具可读性。如果未找到属性,则返回undefined或指定的默认值,如果找到,则返回属性的值。
val(obj, element, default_value)
// Recursively checks whether a property of an object exists. Supports multiple-level nested properties separated with '.' characters.
// obj = the object to test
// element = (string or array) the name of the element to test for. To test for a multi-level nested property, separate properties with '.' characters or pass as array)
// default_value = optional default value to return if the item is not found. Returns undefined if no default_value is specified.
// Returns the element if it exists, or undefined or optional default_value if not found.
// Examples: val(obj1, 'prop1.subprop1.subsubprop2');
// val(obj2, 'p.r.o.p', 'default_value');
{
// If no element is being requested, return obj. (ends recursion - exists)
if (!element || element.length == 0) { return obj; }
// if the element isn't an object, then it can't have properties. (ends recursion - does not exist)
if (typeof obj != 'object') { return default_value; }
// Convert element to array.
if (typeof element == 'string') { element = element.split('.') }; // Split on dot (.)
// Recurse into the list of nested properties:
let first = element.shift();
return val(obj[first], element, default_value);
}
这个功能怎么样?它不需要单独列出每个嵌套属性,而是保持“dot”语法(尽管是字符串),使其更具可读性。如果未找到属性,则返回undefined或指定的默认值,如果找到,则返回属性的值。
val(obj, element, default_value)
// Recursively checks whether a property of an object exists. Supports multiple-level nested properties separated with '.' characters.
// obj = the object to test
// element = (string or array) the name of the element to test for. To test for a multi-level nested property, separate properties with '.' characters or pass as array)
// default_value = optional default value to return if the item is not found. Returns undefined if no default_value is specified.
// Returns the element if it exists, or undefined or optional default_value if not found.
// Examples: val(obj1, 'prop1.subprop1.subsubprop2');
// val(obj2, 'p.r.o.p', 'default_value');
{
// If no element is being requested, return obj. (ends recursion - exists)
if (!element || element.length == 0) { return obj; }
// if the element isn't an object, then it can't have properties. (ends recursion - does not exist)
if (typeof obj != 'object') { return default_value; }
// Convert element to array.
if (typeof element == 'string') { element = element.split('.') }; // Split on dot (.)
// Recurse into the list of nested properties:
let first = element.shift();
return val(obj[first], element, default_value);
}
今天刚刚编写了这个函数,它对嵌套对象中的属性进行了深入搜索,如果找到了,则返回该属性的值。
/**
* Performs a deep search looking for the existence of a property in a
* nested object. Supports namespaced search: Passing a string with
* a parent sub-object where the property key may exist speeds up
* search, for instance: Say you have a nested object and you know for
* certain the property/literal you're looking for is within a certain
* sub-object, you can speed the search up by passing "level2Obj.targetProp"
* @param {object} obj Object to search
* @param {object} key Key to search for
* @return {*} Returns the value (if any) located at the key
*/
var getPropByKey = function( obj, key ) {
var ret = false, ns = key.split("."),
args = arguments,
alen = args.length;
// Search starting with provided namespace
if ( ns.length > 1 ) {
obj = (libName).getPropByKey( obj, ns[0] );
key = ns[1];
}
// Look for a property in the object
if ( key in obj ) {
return obj[key];
} else {
for ( var o in obj ) {
if ( (libName).isPlainObject( obj[o] ) ) {
ret = (libName).getPropByKey( obj[o], key );
if ( ret === 0 || ret === undefined || ret ) {
return ret;
}
}
}
}
return false;
}
我的解决方案,我使用了很长时间(使用字符串不幸,找不到更好的)
function get_if_exist(str){
try{return eval(str)}
catch(e){return undefined}
}
// way to use
if(get_if_exist('test.level1.level2.level3')) {
alert(test.level1.level2.level3);
}
// or simply
alert(get_if_exist('test.level1.level2.level3'));
edit:只有当对象“test”具有全局范围/范围时,这才有效。否则您必须执行以下操作:
// i think it's the most beautiful code I have ever write :p
function get_if_exist(obj){
return arguments.length==1 || (obj[arguments[1]] && get_if_exist.apply(this,[obj[arguments[1]]].concat([].slice.call(arguments,2))));
}
alert(get_if_exist(test,'level1','level2','level3'));
编辑最终版本以允许2种调用方法:
function get_if_exist(obj){
var a=arguments, b=a.callee; // replace a.callee by the function name you choose because callee is depreceate, in this case : get_if_exist
// version 1 calling the version 2
if(a[1] && ~a[1].indexOf('.'))
return b.apply(this,[obj].concat(a[1].split('.')));
// version 2
return a.length==1 ? a[0] : (obj[a[1]] && b.apply(this,[obj[a[1]]].concat([].slice.call(a,2))));
}
// method 1
get_if_exist(test,'level1.level2.level3');
// method 2
get_if_exist(test,'level1','level2','level3');