如果我有对象的引用:
var test = {};
可能(但不是立即)具有嵌套对象,例如:
{level1: {level2: {level3: "level3"}}};
检查深度嵌套对象中是否存在属性的最佳方法是什么?
警报(测试级别1);生成未定义,但警告(test.level1.level2.level3);失败。
我目前正在做这样的事情:
if(test.level1 && test.level1.level2 && test.level1.level2.level3) {
alert(test.level1.level2.level3);
}
但我想知道是否有更好的方法。
我已经使用这个函数来访问深度嵌套对象的财产,它对我来说很有效。。。
这是函数
/**
* get property of object
* @param obj object
* @param path e.g user.name
*/
getProperty(obj, path, defaultValue = '-') {
const value = path.split('.').reduce((o, p) => o && o[p], obj);
return value ? value : defaultValue;
}
这是我访问深度嵌套对象属性的方式
{{ getProperty(object, 'passengerDetails.data.driverInfo.currentVehicle.vehicleType') }}
这是我使用的一个小助手函数,对我来说,它非常简单明了。希望这对一些人有帮助:)。
static issetFromIndices(param, indices, throwException = false) {
var temp = param;
try {
if (!param) {
throw "Parameter is null.";
}
if(!Array.isArray(indices)) {
throw "Indices parameter must be an array.";
}
for (var i = 0; i < indices.length; i++) {
var index = indices[i];
if (typeof temp[index] === "undefined") {
throw "'" + index + "' index is undefined.";
}
temp = temp[index];
}
} catch (e) {
if (throwException) {
throw new Error(e);
} else {
return false;
}
}
return temp;
}
var person = {
hobbies: {
guitar: {
type: "electric"
}
}
};
var indices = ["hobbies", "guitar", "type"];
var throwException = true;
try {
var hobbyGuitarType = issetFromIndices(person, indices, throwException);
console.log("Yay, found index: " + hobbyGuitarType);
} catch(e) {
console.log(e);
}
今天刚刚编写了这个函数,它对嵌套对象中的属性进行了深入搜索,如果找到了,则返回该属性的值。
/**
* Performs a deep search looking for the existence of a property in a
* nested object. Supports namespaced search: Passing a string with
* a parent sub-object where the property key may exist speeds up
* search, for instance: Say you have a nested object and you know for
* certain the property/literal you're looking for is within a certain
* sub-object, you can speed the search up by passing "level2Obj.targetProp"
* @param {object} obj Object to search
* @param {object} key Key to search for
* @return {*} Returns the value (if any) located at the key
*/
var getPropByKey = function( obj, key ) {
var ret = false, ns = key.split("."),
args = arguments,
alen = args.length;
// Search starting with provided namespace
if ( ns.length > 1 ) {
obj = (libName).getPropByKey( obj, ns[0] );
key = ns[1];
}
// Look for a property in the object
if ( key in obj ) {
return obj[key];
} else {
for ( var o in obj ) {
if ( (libName).isPlainObject( obj[o] ) ) {
ret = (libName).getPropByKey( obj[o], key );
if ( ret === 0 || ret === undefined || ret ) {
return ret;
}
}
}
}
return false;
}