在PHP中,您可以。。。
range(1, 3); // Array(1, 2, 3)
range("A", "C"); // Array("A", "B", "C")
也就是说,有一个函数可以通过传递上下限来获得一系列数字或字符。
JavaScript本机是否有内置的功能?如果没有,我将如何实施?
在PHP中,您可以。。。
range(1, 3); // Array(1, 2, 3)
range("A", "C"); // Array("A", "B", "C")
也就是说,有一个函数可以通过传递上下限来获得一系列数字或字符。
JavaScript本机是否有内置的功能?如果没有,我将如何实施?
当前回答
https://stackoverflow.com/a/49577331/8784402
带增量/步长
smallest and one-liner[...Array(N)].map((_, i) => from + i * step);
示例和其他备选方案
[...Array(10)].map((_, i) => 4 + i * 2);
//=> [4, 6, 8, 10, 12, 14, 16, 18, 20, 22]
Array.from(Array(10)).map((_, i) => 4 + i * 2);
//=> [4, 6, 8, 10, 12, 14, 16, 18, 20, 22]
Array.from(Array(10).keys()).map(i => 4 + i * 2);
//=> [4, 6, 8, 10, 12, 14, 16, 18, 20, 22]
[...Array(10).keys()].map(i => 4 + i * -2);
//=> [4, 2, 0, -2, -4, -6, -8, -10, -12, -14]
Array(10).fill(0).map((_, i) => 4 + i * 2);
//=> [4, 6, 8, 10, 12, 14, 16, 18, 20, 22]
Array(10).fill().map((_, i) => 4 + i * -2);
//=> [4, 2, 0, -2, -4, -6, -8, -10, -12, -14]
Range Function
const range = (from, to, step) =>
[...Array(Math.floor((to - from) / step) + 1)].map((_, i) => from + i * step);
range(0, 9, 2);
//=> [0, 2, 4, 6, 8]
// can also assign range function as static method in Array class (but not recommended )
Array.range = (from, to, step) =>
[...Array(Math.floor((to - from) / step) + 1)].map((_, i) => from + i * step);
Array.range(2, 10, 2);
//=> [2, 4, 6, 8, 10]
Array.range(0, 10, 1);
//=> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
Array.range(2, 10, -1);
//=> []
Array.range(3, 0, -1);
//=> [3, 2, 1, 0]
As Iterators
class Range {
constructor(total = 0, step = 1, from = 0) {
this[Symbol.iterator] = function* () {
for (let i = 0; i < total; yield from + i++ * step) {}
};
}
}
[...new Range(5)]; // Five Elements
//=> [0, 1, 2, 3, 4]
[...new Range(5, 2)]; // Five Elements With Step 2
//=> [0, 2, 4, 6, 8]
[...new Range(5, -2, 10)]; // Five Elements With Step -2 From 10
//=>[10, 8, 6, 4, 2]
[...new Range(5, -2, -10)]; // Five Elements With Step -2 From -10
//=> [-10, -12, -14, -16, -18]
// Also works with for..of loop
for (i of new Range(5, -2, 10)) console.log(i);
// 10 8 6 4 2
As Generators Only
const Range = function* (total = 0, step = 1, from = 0) {
for (let i = 0; i < total; yield from + i++ * step) {}
};
Array.from(Range(5, -2, -10));
//=> [-10, -12, -14, -16, -18]
[...Range(5, -2, -10)]; // Five Elements With Step -2 From -10
//=> [-10, -12, -14, -16, -18]
// Also works with for..of loop
for (i of Range(5, -2, 10)) console.log(i);
// 10 8 6 4 2
// Lazy loaded way
const number0toInf = Range(Infinity);
number0toInf.next().value;
//=> 0
number0toInf.next().value;
//=> 1
// ...
带步长/增量的从到
using iteratorsclass Range2 {
constructor(to = 0, step = 1, from = 0) {
this[Symbol.iterator] = function* () {
let i = 0,
length = Math.floor((to - from) / step) + 1;
while (i < length) yield from + i++ * step;
};
}
}
[...new Range2(5)]; // First 5 Whole Numbers
//=> [0, 1, 2, 3, 4, 5]
[...new Range2(5, 2)]; // From 0 to 5 with step 2
//=> [0, 2, 4]
[...new Range2(5, -2, 10)]; // From 10 to 5 with step -2
//=> [10, 8, 6]
using Generators
const Range2 = function* (to = 0, step = 1, from = 0) {
let i = 0,
length = Math.floor((to - from) / step) + 1;
while (i < length) yield from + i++ * step;
};
[...Range2(5, -2, 10)]; // From 10 to 5 with step -2
//=> [10, 8, 6]
let even4to10 = Range2(10, 2, 4);
even4to10.next().value;
//=> 4
even4to10.next().value;
//=> 6
even4to10.next().value;
//=> 8
even4to10.next().value;
//=> 10
even4to10.next().value;
//=> undefined
对于字体
class _Array<T> extends Array<T> {
static range(from: number, to: number, step: number): number[] {
return Array.from(Array(Math.floor((to - from) / step) + 1)).map(
(v, k) => from + k * step
);
}
}
_Array.range(0, 9, 1);
https://stackoverflow.com/a/64599169/8784402
用一行代码生成字符列表
constcharList=(a,z,d=1)=>(a=a.charCodeAt(),z=z.charCodeAt(),[…数组(Math.floor((z-a)/d)+1)].map((_,i)=>String.fromCharCode(a+i*d)));console.log(“从A到G”,charList('A','G'));console.log(“从A到Z,步长/增量为2”,charList('A','Z',2));console.log(“从Z到P的反向顺序”,charList('Z','P',-1));console.log(“从0到5”,charList(“0”,“5”,1));console.log(“从9到5”,charList('9','5',-1));console.log(“从0到8,步骤2”,charList('0','8',2));console.log(“从α到ω”,charList(“α”,“ω”));console.log(“印地语字符来自क 到ह“,charList('क', 'ह'));console.log(“从А到Е的俄语字符”,charList(“А”,“Е”));
For TypeScriptconst charList = (p: string, q: string, d = 1) => {
const a = p.charCodeAt(0),
z = q.charCodeAt(0);
return [...Array(Math.floor((z - a) / d) + 1)].map((_, i) =>
String.fromCharCode(a + i * d)
);
};
其他回答
我发现了一个与PHP中的函数相当的JS范围函数,在这里工作得非常棒。向前和向后工作,可以处理整数、浮点数和字母!
function range(low, high, step) {
// discuss at: http://phpjs.org/functions/range/
// original by: Waldo Malqui Silva
// example 1: range ( 0, 12 );
// returns 1: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
// example 2: range( 0, 100, 10 );
// returns 2: [0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
// example 3: range( 'a', 'i' );
// returns 3: ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i']
// example 4: range( 'c', 'a' );
// returns 4: ['c', 'b', 'a']
var matrix = [];
var inival, endval, plus;
var walker = step || 1;
var chars = false;
if (!isNaN(low) && !isNaN(high)) {
inival = low;
endval = high;
} else if (isNaN(low) && isNaN(high)) {
chars = true;
inival = low.charCodeAt(0);
endval = high.charCodeAt(0);
} else {
inival = (isNaN(low) ? 0 : low);
endval = (isNaN(high) ? 0 : high);
}
plus = ((inival > endval) ? false : true);
if (plus) {
while (inival <= endval) {
matrix.push(((chars) ? String.fromCharCode(inival) : inival));
inival += walker;
}
} else {
while (inival >= endval) {
matrix.push(((chars) ? String.fromCharCode(inival) : inival));
inival -= walker;
}
}
return matrix;
}
这是缩小版:
function range(h,c,b){var i=[];var d,f,e;var a=b||1;var g=false;if(!isNaN(h)&&!isNaN(c)){d=h;f=c}else{if(isNaN(h)&&isNaN(c)){g=true;d=h.charCodeAt(0);f=c.charCodeAt(0)}else{d=(isNaN(h)?0:h);f=(isNaN(c)?0:c)}}e=((d>f)?false:true);if(e){while(d<=f){i.push(((g)?String.fromCharCode(d):d));d+=a}}else{while(d>=f){i.push(((g)?String.fromCharCode(d):d));d-=a}}return i};
标准的Javascript没有生成范围的内置函数。有几个javascript框架添加了对这些功能的支持,或者正如其他人所指出的那样,您可以一直使用自己的功能。
如果您想再次检查,确定的资源是ECMA-262标准。
…更大范围,使用生成器功能。
function range(s, e, str){
// create generator that handles numbers & strings.
function *gen(s, e, str){
while(s <= e){
yield (!str) ? s : str[s]
s++
}
}
if (typeof s === 'string' && !str)
str = 'abcdefghijklmnopqrstuvwxyz'
const from = (!str) ? s : str.indexOf(s)
const to = (!str) ? e : str.indexOf(e)
// use the generator and return.
return [...gen(from, to, str)]
}
// usage ...
console.log(range('l', 'w'))
//=> [ 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w' ]
console.log(range(7, 12))
//=> [ 7, 8, 9, 10, 11, 12 ]
// first 'o' to first 't' of passed in string.
console.log(range('o', 't', "ssshhhooooouuut!!!!"))
// => [ 'o', 'o', 'o', 'o', 'o', 'u', 'u', 'u', 't' ]
// only lowercase args allowed here, but ...
console.log(range('m', 'v').map(v=>v.toUpperCase()))
//=> [ 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V' ]
// => and decreasing range ...
console.log(range('m', 'v').map(v=>v.toUpperCase()).reverse())
// => ... and with a step
console.log(range('m', 'v')
.map(v=>v.toUpperCase())
.reverse()
.reduce((acc, c, i) => (i % 2) ? acc.concat(c) : acc, []))
// ... etc, etc.
希望这有用。
var range = (l,r) => new Array(r - l).fill().map((_,k) => k + l);
我想补充一点,我认为这是一个非常可调的版本,速度非常快。
const range = (start, end) => {
let all = [];
if (typeof start === "string" && typeof end === "string") {
// Return the range of characters using utf-8 least to greatest
const s = start.charCodeAt(0);
const e = end.charCodeAt(0);
for (let i = s; i <= e; i++) {
all.push(String.fromCharCode(i));
}
} else if (typeof start === "number" && typeof end === "number") {
// Return the range of numbers from least to greatest
for(let i = end; i >= start; i--) {
all.push(i);
}
} else {
throw new Error("Did not supply matching types number or string.");
}
return all;
}
// usage
const aTod = range("a", "d");
如果您愿意,也可以使用打字机
const range = (start: string | number, end: string | number): string[] | number[] => {
const all: string[] | number[] = [];
if (typeof start === "string" && typeof end === "string") {
const s: number = start.charCodeAt(0);
const e: number = end.charCodeAt(0);
for (let i = s; i <= e; i++) {
all.push(String.fromCharCode(i));
}
} else if (typeof start === "number" && typeof end === "number") {
for (let i = end; i >= start; i--) {
all.push(i);
}
} else {
throw new Error("Did not supply matching types number or string.");
}
return all;
}
// Usage
const negTenToten: number[] = range(-10, 10) as number[];
受到其他答案的影响。用户已离开。