如何从内置web浏览器而不是应用程序中的代码打开URL？
我试过了：
try {
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(download_link));
startActivity(myIntent);
} catch (ActivityNotFoundException e) {
Toast.makeText(this, "No application can handle this request."
+ " Please install a webbrowser", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
但我有个例外：
No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com
当前回答
尝试此代码
AndroidManifest.xml
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
package="com.example.myapplication5">
<uses-permission android:name="android.permission.INTERNET" />
<application
android:usesCleartextTraffic="true"
android:allowBackup="true"
.....
/>
<activity android:name=".MainActivity"
android:screenOrientation="portrait"
tools:ignore="LockedOrientationActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
主要活动.java
import android.app.Activity;
import android.content.res.Resources;
import android.os.Bundle;
import android.view.View;
import android.view.Window;
import android.webkit.WebSettings;
import android.webkit.WebView;
import android.webkit.WebViewClient;
import android.widget.Toast;
public class MainActivity extends Activity {
private WebView mWebview;
String link = "";// global variable
Resources res;// global variable
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_NO_TITLE);
setContentView(R.layout.home);
loadWebPage();
}
public void loadWebPage()
{
mWebview = (WebView) findViewById(R.id.webView);
WebSettings webSettings = mWebview.getSettings();
webSettings.setJavaScriptEnabled(true);
webSettings.setUseWideViewPort(true);
webSettings.setLoadWithOverviewMode(true);
final Activity activity = this;
mWebview.setWebViewClient(new WebViewClient() {
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
Toast.makeText(activity, description, Toast.LENGTH_SHORT).show();
}
});
mWebview.loadUrl("http://www.google.com");
}
public void reLoad(View v)
{
loadWebPage();
}
}
布局.xml
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical">
<TextView
android:id="@+id/textView"
android:layout_width="335dp"
android:layout_height="47dp"
android:layout_alignParentStart="true"
android:layout_alignParentTop="true"
android:layout_marginStart="9dp"
android:layout_marginTop="8dp"
android:paddingLeft="10dp"
android:paddingTop="5dp"
android:text="URL : https://ktmmovie.co/"
android:textSize="18dp"
android:layout_marginLeft="9dp"
android:layout_alignParentLeft="true" />
<com.google.android.material.floatingactionbutton.FloatingActionButton
android:id="@+id/floatingActionButton2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_alignParentEnd="true"
android:layout_marginStart="7dp"
android:layout_marginLeft="7dp"
android:layout_marginEnd="8dp"
android:layout_toEndOf="@+id/textView"
android:layout_toRightOf="@+id/textView"
android:clickable="true"
android:src="@android:drawable/ic_popup_sync"
android:layout_marginRight="8dp"
android:layout_alignParentRight="true"
android:onClick="reLoad"/>
<WebView
android:id="@+id/webView"
android:layout_width="401dp"
android:layout_height="665dp"
android:layout_below="@+id/textView"
android:layout_alignParentStart="true"
android:layout_alignParentLeft="true"
android:layout_alignParentBottom="true"
android:layout_centerHorizontal="true"
android:layout_marginStart="3dp"
android:layout_marginLeft="3dp"
android:layout_marginTop="3dp"
android:layout_marginBottom="7dp" />
</RelativeLayout>
其他回答
kolin扩展函数。
fun Activity.openWebPage(url: String?) = url?.let {
val intent = Intent(Intent.ACTION_VIEW, Uri.parse(it))
if (intent.resolveActivity(packageManager) != null) startActivity(intent)
}
就像其他人写的解决方案一样（效果很好），我想回答同样的问题，但我认为大多数人更愿意使用一个提示。
如果您希望在新任务中开始打开应用程序，独立于您自己，而不是停留在同一堆栈中，您可以使用以下代码：
final Intent intent=new Intent(Intent.ACTION_VIEW,Uri.parse(url));
intent.addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY|Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET|Intent.FLAG_ACTIVITY_NEW_TASK|Intent.FLAG_ACTIVITY_MULTIPLE_TASK);
startActivity(intent);
还有一种方法可以在Chrome自定义选项卡中打开URL。Kotlin示例：
@JvmStatic
fun openWebsite(activity: Activity, websiteUrl: String, useWebBrowserAppAsFallbackIfPossible: Boolean) {
var websiteUrl = websiteUrl
if (TextUtils.isEmpty(websiteUrl))
return
if (websiteUrl.startsWith("www"))
websiteUrl = "http://$websiteUrl"
else if (!websiteUrl.startsWith("http"))
websiteUrl = "http://www.$websiteUrl"
val finalWebsiteUrl = websiteUrl
//https://github.com/GoogleChrome/custom-tabs-client
val webviewFallback = object : CustomTabActivityHelper.CustomTabFallback {
override fun openUri(activity: Activity, uri: Uri?) {
var intent: Intent
if (useWebBrowserAppAsFallbackIfPossible) {
intent = Intent(Intent.ACTION_VIEW, Uri.parse(finalWebsiteUrl))
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK or Intent.FLAG_ACTIVITY_NO_HISTORY
or Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET or Intent.FLAG_ACTIVITY_MULTIPLE_TASK)
if (!CollectionUtil.isEmpty(activity.packageManager.queryIntentActivities(intent, 0))) {
activity.startActivity(intent)
return
}
}
// open our own Activity to show the URL
intent = Intent(activity, WebViewActivity::class.java)
WebViewActivity.prepareIntent(intent, finalWebsiteUrl)
activity.startActivity(intent)
}
}
val uri = Uri.parse(finalWebsiteUrl)
val intentBuilder = CustomTabsIntent.Builder()
val customTabsIntent = intentBuilder.build()
customTabsIntent.intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK or Intent.FLAG_ACTIVITY_NO_HISTORY
or Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET or Intent.FLAG_ACTIVITY_MULTIPLE_TASK)
CustomTabActivityHelper.openCustomTab(activity, customTabsIntent, uri, webviewFallback)
}
Webview可用于在应用程序中加载Url。用户可以在文本视图中提供URL，也可以对其进行硬编码。
也不要忘记AndroidManifest中的互联网权限。
String url="http://developer.android.com/index.html"
WebView wv=(WebView)findViewById(R.id.webView);
wv.setWebViewClient(new MyBrowser());
wv.getSettings().setLoadsImagesAutomatically(true);
wv.getSettings().setJavaScriptEnabled(true);
wv.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
wv.loadUrl(url);
private class MyBrowser extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
String url = "http://www.example.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
Kotlin溶液
所有答案都是在该url的默认应用程序中打开该url。我想总是在浏览器中打开任何url。我需要一些kotlin的解决方案，并实现了下面的代码。
fun getPackageNameForUrl(context: Context, url: String): String? {
val intent = Intent(Intent.ACTION_VIEW, Uri.parse(url))
val resolveInfo = context.packageManager.resolveActivity(intent, PackageManager.MATCH_DEFAULT_ONLY)
return resolveInfo?.activityInfo?.packageName
}
fun openInBrowser(context: Context, url: String) {
val intent = Intent(Intent.ACTION_VIEW, Uri.parse(url))
val packageName = getPackageNameForUrl(context, "http://")
packageName?.takeIf {
it == "android"
}?.let { intent.setPackage(defaultBrowserPackageName); }
startActivity(context, intent, null)
}
