如何从内置web浏览器而不是应用程序中的代码打开URL？
我试过了：
try {
Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(download_link));
startActivity(myIntent);
} catch (ActivityNotFoundException e) {
Toast.makeText(this, "No application can handle this request."
+ " Please install a webbrowser", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
但我有个例外：
No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com
当前回答
Intent getWebPage = new Intent(Intent.ACTION_VIEW, Uri.parse(MyLink));
startActivity(getWebPage);
其他回答
实现这一点的常见方法是使用以下代码：
String url = "http://www.stackoverflow.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
可以更改为短代码版本。。。
Intent intent = new Intent(Intent.ACTION_VIEW).setData(Uri.parse("http://www.stackoverflow.com"));
startActivity(intent);
or :
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.stackoverflow.com"));
startActivity(intent);
最短！：
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.stackoverflow.com")));
在Android 11中打开URL链接的新的更好方法。
try {
val intent = Intent(ACTION_VIEW, Uri.parse(url)).apply {
// The URL should either launch directly in a non-browser app
// (if it’s the default), or in the disambiguation dialog
addCategory(CATEGORY_BROWSABLE)
flags = FLAG_ACTIVITY_NEW_TASK or FLAG_ACTIVITY_REQUIRE_NON_BROWSER or
FLAG_ACTIVITY_REQUIRE_DEFAULT
}
startActivity(intent)
} catch (e: ActivityNotFoundException) {
// Only browser apps are available, or a browser is the default app for this intent
// This code executes in one of the following cases:
// 1. Only browser apps can handle the intent.
// 2. The user has set a browser app as the default app.
// 3. The user hasn't set any app as the default for handling this URL.
openInCustomTabs(url)
}
参考文献：
https://medium.com/androiddevelopers/package-visibility-in-android-11-cc857f221cd9和https://developer.android.com/training/package-visibility/use-cases#avoid-a-消除歧义对话框
Webview可用于在应用程序中加载Url。用户可以在文本视图中提供URL，也可以对其进行硬编码。
也不要忘记AndroidManifest中的互联网权限。
String url="http://developer.android.com/index.html"
WebView wv=(WebView)findViewById(R.id.webView);
wv.setWebViewClient(new MyBrowser());
wv.getSettings().setLoadsImagesAutomatically(true);
wv.getSettings().setJavaScriptEnabled(true);
wv.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
wv.loadUrl(url);
private class MyBrowser extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
简短甜美的Kotlin助手功能：
private fun openUrl(link: String) =
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(link)))
android.webkit.URLUtil自Api级别1（android 1.0）以来，guessUrl（String）方法工作得非常好（即使使用file://或data://）。用作：
String url = URLUtil.guessUrl(link);
// url.com -> http://url.com/ (adds http://)
// http://url -> http://url.com/ (adds .com)
// https://url -> https://url.com/ (adds .com)
// url -> http://www.url.com/ (adds http://www. and .com)
// http://www.url.com -> http://www.url.com/
// https://url.com -> https://url.com/
// file://dir/to/file -> file://dir/to/file
// data://dataline -> data://dataline
// content://test -> content://test
在“活动”调用中：
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(URLUtil.guessUrl(download_link)));
if (intent.resolveActivity(getPackageManager()) != null)
startActivity(intent);
有关详细信息，请查看完整的guessUrl代码。
