不知道为什么，没人提吉特。参见https://stackoverflow.com/a/424142/1657819

Git-tree是首选，因为它是一个管道命令;应该是程序化的(而且可能更快)

(假设基础分支是master)

git diff-tree --no-commit-id --name-only -r master..branch-name

然而，这将显示分支中所有受影响的文件，如果你只想看到显式修改的文件，你可以使用——diff-filter:

git diff-tree --no-commit-id --name-only -r master..branch-name --diff-filter=M

也可以使用——name-status来代替——name-only来查看文件的状态(A/M/D等等)

你所要做的就是:

git checkout <notMainDev>
git diff --name-only <mainDev>

这将只显示两个分支之间不同的文件名。

@Marco Ponti的另一个答案，避免结帐:

git diff --name-only <notMainDev> $(git merge-base <notMainDev> <mainDev>)

如果您的特定shell不理解$()结构，则使用反引号代替。

扩展@twalberg和@iconoclast，如果你因为任何原因使用cmd，你可以使用:

FOR /F "usebackq" %x IN (`"git branch | grep '*' | cut -f2 -d' '"`) DO FOR /F "usebackq" %y IN (`"git merge-base %x master"`) DO git diff --name-only %x %y

考虑到你在一个特性分支上，你想要检查哪些文件与master…就在这个:

git diff --name-only master

2020年11月更新:

要获得当前分支中修改(并提交!)的文件列表，您可以使用使用标准git的最短控制台命令:

Git diff -name-only master…

If your local "master" branch is outdated (behind the remote), add a remote name (assuming it is "origin"): git diff --name-only origin/master... If you want to include uncommitted changes as well, remove the ...: git diff --name-only master If you use different main branch name (eg: "main"), substitute it: git diff --name-only main... If your want to output to stdout (so its copyable): git diff --name-only master... | cat If your want filenames to be clickable in VSCode terminal no matter what folder you are running this command from, add --relative: git diff --name-only --relative master... | cat

每个非常好的详细解释不同的选项https://blog.jpalardy.com/posts/git-how-to-find-modified-files-on-a-branch/