是否有办法在bash上比较这些字符串,例如:2.4.5和2.8和2.4.5.1?
当前回答
这个怎么样?似乎有用?
checkVersion() {
subVer1=$1
subVer2=$2
[ "$subVer1" == "$subVer2" ] && echo "Version is same"
echo "Version 1 is $subVer1"
testVer1=$subVer1
echo "Test version 1 is $testVer1"
x=0
while [[ $testVer1 != "" ]]
do
((x++))
testVer1=`echo $subVer1|cut -d "." -f $x`
echo "testVer1 now is $testVer1"
testVer2=`echo $subVer2|cut -d "." -f $x`
echo "testVer2 now is $testVer2"
if [[ $testVer1 -gt $testVer2 ]]
then
echo "$ver1 is greater than $ver2"
break
elif [[ "$testVer2" -gt "$testVer1" ]]
then
echo "$ver2 is greater than $ver1"
break
fi
echo "This is the sub verion for first value $testVer1"
echo "This is the sub verion for second value $testVer2"
done
}
ver1=$1
ver2=$2
checkVersion "$ver1" "$ver2"
其他回答
与其编写冗长的代码使您的生活过于复杂,不如使用一些已经存在的东西。很多时候,当bash不够用时,python可以提供帮助。你仍然可以很容易地从bash脚本调用它(额外的好处:从bash到python的变量替换):
VERSION1=1.2.3
VERSION2=1.2.4
cat <<EOF | python3 | grep -q True
from packaging import version
print(version.parse("$VERSION1") > version.parse("$VERSION2"))
EOF
if [ "$?" == 0 ]; then
echo "$VERSION1 is greater than $VERSION2"
else
echo "$VERSION2 is greater or equal than $VERSION1"
fi
这里有更多信息:如何比较Python中的版本号?
下面是一个不需要任何外部工具的纯Bash版本:
#!/bin/bash
vercomp () {
if [[ $1 == $2 ]]
then
return 0
fi
local IFS=.
local i ver1=($1) ver2=($2)
# fill empty fields in ver1 with zeros
for ((i=${#ver1[@]}; i<${#ver2[@]}; i++))
do
ver1[i]=0
done
for ((i=0; i<${#ver1[@]}; i++))
do
if [[ -z ${ver2[i]} ]]
then
# fill empty fields in ver2 with zeros
ver2[i]=0
fi
if ((10#${ver1[i]} > 10#${ver2[i]}))
then
return 1
fi
if ((10#${ver1[i]} < 10#${ver2[i]}))
then
return 2
fi
done
return 0
}
testvercomp () {
vercomp $1 $2
case $? in
0) op='=';;
1) op='>';;
2) op='<';;
esac
if [[ $op != $3 ]]
then
echo "FAIL: Expected '$3', Actual '$op', Arg1 '$1', Arg2 '$2'"
else
echo "Pass: '$1 $op $2'"
fi
}
# Run tests
# argument table format:
# testarg1 testarg2 expected_relationship
echo "The following tests should pass"
while read -r test
do
testvercomp $test
done << EOF
1 1 =
2.1 2.2 <
3.0.4.10 3.0.4.2 >
4.08 4.08.01 <
3.2.1.9.8144 3.2 >
3.2 3.2.1.9.8144 <
1.2 2.1 <
2.1 1.2 >
5.6.7 5.6.7 =
1.01.1 1.1.1 =
1.1.1 1.01.1 =
1 1.0 =
1.0 1 =
1.0.2.0 1.0.2 =
1..0 1.0 =
1.0 1..0 =
EOF
echo "The following test should fail (test the tester)"
testvercomp 1 1 '>'
运行测试:
$ . ./vercomp
The following tests should pass
Pass: '1 = 1'
Pass: '2.1 < 2.2'
Pass: '3.0.4.10 > 3.0.4.2'
Pass: '4.08 < 4.08.01'
Pass: '3.2.1.9.8144 > 3.2'
Pass: '3.2 < 3.2.1.9.8144'
Pass: '1.2 < 2.1'
Pass: '2.1 > 1.2'
Pass: '5.6.7 = 5.6.7'
Pass: '1.01.1 = 1.1.1'
Pass: '1.1.1 = 1.01.1'
Pass: '1 = 1.0'
Pass: '1.0 = 1'
Pass: '1.0.2.0 = 1.0.2'
Pass: '1..0 = 1.0'
Pass: '1.0 = 1..0'
The following test should fail (test the tester)
FAIL: Expected '>', Actual '=', Arg1 '1', Arg2 '1'
我希望这对某些人有用(使用awk)
#!/bin/bash
available_version=1.2.3 # or online version
this_version=1.2.1
if [[ "ok" == "$(echo | awk "(${available_version} > ${this_version}) { print \"ok\"; }")" ]]; then
echo "Notice, new version is available"
elif [[ "ok" == "$(echo | awk "(${available_version} == ${this_version}) { print \"ok\"; }")" ]]; then
echo "OK, version is up to date"
else
echo "Warning, the current version is ahead of the online version!"
fi
你可以递归地拆分。和下面的算法进行比较,从这里开始。如果版本相同则返回10,如果版本1大于版本2则返回11,否则返回9。
#!/bin/bash
do_version_check() {
[ "$1" == "$2" ] && return 10
ver1front=`echo $1 | cut -d "." -f -1`
ver1back=`echo $1 | cut -d "." -f 2-`
ver2front=`echo $2 | cut -d "." -f -1`
ver2back=`echo $2 | cut -d "." -f 2-`
if [ "$ver1front" != "$1" ] || [ "$ver2front" != "$2" ]; then
[ "$ver1front" -gt "$ver2front" ] && return 11
[ "$ver1front" -lt "$ver2front" ] && return 9
[ "$ver1front" == "$1" ] || [ -z "$ver1back" ] && ver1back=0
[ "$ver2front" == "$2" ] || [ -z "$ver2back" ] && ver2back=0
do_version_check "$ver1back" "$ver2back"
return $?
else
[ "$1" -gt "$2" ] && return 11 || return 9
fi
}
do_version_check "$1" "$2"
源
这里一个有用的技巧是字符串索引。
$ echo "${BASH_VERSION}"
4.4.23(1)-release
$ echo "${BASH_VERSION:0:1}"
4
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