是否有办法在bash上比较这些字符串,例如:2.4.5和2.8和2.4.5.1?
当前回答
这个怎么样?似乎有用?
checkVersion() {
subVer1=$1
subVer2=$2
[ "$subVer1" == "$subVer2" ] && echo "Version is same"
echo "Version 1 is $subVer1"
testVer1=$subVer1
echo "Test version 1 is $testVer1"
x=0
while [[ $testVer1 != "" ]]
do
((x++))
testVer1=`echo $subVer1|cut -d "." -f $x`
echo "testVer1 now is $testVer1"
testVer2=`echo $subVer2|cut -d "." -f $x`
echo "testVer2 now is $testVer2"
if [[ $testVer1 -gt $testVer2 ]]
then
echo "$ver1 is greater than $ver2"
break
elif [[ "$testVer2" -gt "$testVer1" ]]
then
echo "$ver2 is greater than $ver1"
break
fi
echo "This is the sub verion for first value $testVer1"
echo "This is the sub verion for second value $testVer2"
done
}
ver1=$1
ver2=$2
checkVersion "$ver1" "$ver2"
其他回答
如果你有coreutils-7 (Ubuntu Karmic,而不是Jaunty),那么你的排序命令应该有一个-V选项(版本排序),你可以使用它来进行比较:
verlte() {
[ "$1" = "`echo -e "$1\n$2" | sort -V | head -n1`" ]
}
verlt() {
[ "$1" = "$2" ] && return 1 || verlte $1 $2
}
verlte 2.5.7 2.5.6 && echo "yes" || echo "no" # no
verlt 2.4.10 2.4.9 && echo "yes" || echo "no" # no
verlt 2.4.8 2.4.10 && echo "yes" || echo "no" # yes
verlte 2.5.6 2.5.6 && echo "yes" || echo "no" # yes
verlt 2.5.6 2.5.6 && echo "yes" || echo "no" # no
你可以递归地拆分。和下面的算法进行比较,从这里开始。如果版本相同则返回10,如果版本1大于版本2则返回11,否则返回9。
#!/bin/bash
do_version_check() {
[ "$1" == "$2" ] && return 10
ver1front=`echo $1 | cut -d "." -f -1`
ver1back=`echo $1 | cut -d "." -f 2-`
ver2front=`echo $2 | cut -d "." -f -1`
ver2back=`echo $2 | cut -d "." -f 2-`
if [ "$ver1front" != "$1" ] || [ "$ver2front" != "$2" ]; then
[ "$ver1front" -gt "$ver2front" ] && return 11
[ "$ver1front" -lt "$ver2front" ] && return 9
[ "$ver1front" == "$1" ] || [ -z "$ver1back" ] && ver1back=0
[ "$ver2front" == "$2" ] || [ -z "$ver2back" ] && ver2back=0
do_version_check "$ver1back" "$ver2back"
return $?
else
[ "$1" -gt "$2" ] && return 11 || return 9
fi
}
do_version_check "$1" "$2"
源
对于旧版本/busybox排序。简单的形式提供了粗略的结果,往往奏效。
sort -n
这是特别有用的版本,其中包含alpha符号,如
10.c.3
10.a.4
2.b.5
与其编写冗长的代码使您的生活过于复杂,不如使用一些已经存在的东西。很多时候,当bash不够用时,python可以提供帮助。你仍然可以很容易地从bash脚本调用它(额外的好处:从bash到python的变量替换):
VERSION1=1.2.3
VERSION2=1.2.4
cat <<EOF | python3 | grep -q True
from packaging import version
print(version.parse("$VERSION1") > version.parse("$VERSION2"))
EOF
if [ "$?" == 0 ]; then
echo "$VERSION1 is greater than $VERSION2"
else
echo "$VERSION2 is greater or equal than $VERSION1"
fi
这里有更多信息:如何比较Python中的版本号?
下面是一个不使用外部命令的简单Bash函数。它适用于包含最多三个数字部分的版本字符串-小于3也是可以的。它可以很容易地扩展为更多。它实现了=、<、<=、>、>=和!=条件。
#!/bin/bash
vercmp() {
version1=$1 version2=$2 condition=$3
IFS=. v1_array=($version1) v2_array=($version2)
v1=$((v1_array[0] * 100 + v1_array[1] * 10 + v1_array[2]))
v2=$((v2_array[0] * 100 + v2_array[1] * 10 + v2_array[2]))
diff=$((v2 - v1))
[[ $condition = '=' ]] && ((diff == 0)) && return 0
[[ $condition = '!=' ]] && ((diff != 0)) && return 0
[[ $condition = '<' ]] && ((diff > 0)) && return 0
[[ $condition = '<=' ]] && ((diff >= 0)) && return 0
[[ $condition = '>' ]] && ((diff < 0)) && return 0
[[ $condition = '>=' ]] && ((diff <= 0)) && return 0
return 1
}
下面是测试:
for tv1 in '*' 1.1.1 2.5.3 7.3.0 0.5.7 10.3.9 8.55.32 0.0.1; do
for tv2 in 3.1.1 1.5.3 4.3.0 0.0.7 0.3.9 11.55.32 10.0.0 '*'; do
for c in '=' '>' '<' '>=' '<=' '!='; do
vercmp "$tv1" "$tv2" "$c" && printf '%s\n' "$tv1 $c $tv2 is true" || printf '%s\n' "$tv1 $c $tv2 is false"
done
done
done
测试输出的子集:
<snip>
* >= * is true
* <= * is true
* != * is true
1.1.1 = 3.1.1 is false
1.1.1 > 3.1.1 is false
1.1.1 < 3.1.1 is true
1.1.1 >= 3.1.1 is false
1.1.1 <= 3.1.1 is true
1.1.1 != 3.1.1 is true
1.1.1 = 1.5.3 is false
1.1.1 > 1.5.3 is false
1.1.1 < 1.5.3 is true
1.1.1 >= 1.5.3 is false
1.1.1 <= 1.5.3 is true
1.1.1 != 1.5.3 is true
1.1.1 = 4.3.0 is false
1.1.1 > 4.3.0 is false
<snip>