我感兴趣的是从数据库表中选择第n行的一些(理想的)数据库不可知的方法。看看如何使用以下数据库的本机功能来实现这一点也很有趣:

SQL Server MySQL PostgreSQL SQLite 甲骨文

我目前正在SQL Server 2005中做以下事情,但我有兴趣看到其他更不可知论的方法:

WITH Ordered AS (
SELECT ROW_NUMBER() OVER (ORDER BY OrderID) AS RowNumber, OrderID, OrderDate
FROM Orders)
SELECT *
FROM Ordered
WHERE RowNumber = 1000000

以上SQL: Firoz Ansari的Weblog的功劳

更新:参见Troels Arvin关于SQL标准的回答。Troels,你有我们可以引用的链接吗?


当前回答

难以置信,你能找到一个SQL引擎执行这个…

WITH sentence AS
(SELECT 
    stuff,
    row = ROW_NUMBER() OVER (ORDER BY Id)
FROM 
    SentenceType
    )
SELECT
    sen.stuff
FROM sentence sen
WHERE sen.row = (ABS(CHECKSUM(NEWID())) % 100) + 1

其他回答

在Oracle 12c中,你可以使用OFFSET..FETCH..带有ORDER BY的ROWS选项

例如,要从顶部获取第3条记录:

SELECT * 
FROM   sometable
ORDER BY column_name
OFFSET 2 ROWS FETCH NEXT 1 ROWS ONLY;

SQL 2005及以上版本内置了这个特性。使用ROW_NUMBER()函数。它非常适合浏览<< Prev和Next >>样式的网页:

语法:

SELECT
    *
FROM
    (
        SELECT
            ROW_NUMBER () OVER (ORDER BY MyColumnToOrderBy) AS RowNum,
            *
        FROM
            Table_1
    ) sub
WHERE
    RowNum = 23

难以置信,你能找到一个SQL引擎执行这个…

WITH sentence AS
(SELECT 
    stuff,
    row = ROW_NUMBER() OVER (ORDER BY Id)
FROM 
    SentenceType
    )
SELECT
    sen.stuff
FROM sentence sen
WHERE sen.row = (ABS(CHECKSUM(NEWID())) % 100) + 1

我不确定其他的,但我知道SQLite和MySQL没有任何“默认”行排序。至少在这两种方言中,下面的代码片段从the_table中抓取了第15个条目,按添加的日期/时间排序:

SELECT * 
FROM the_table 
ORDER BY added DESC 
LIMIT 1,15

(当然,您需要添加一个DATETIME字段,并将其设置为条目添加的日期/时间…)

在我看来,为了提高效率,您需要1)生成一个小于数据库记录数量的0到1之间的随机数,2)能够选择该位置的行。不幸的是,不同的数据库有不同的随机数生成器,以及在结果集中的某个位置选择一行的不同方法——通常您指定要跳过多少行和需要多少行,但不同的数据库有不同的做法。下面是在SQLite中为我工作的一些东西:

select * 
from Table 
limit abs(random()) % (select count(*) from Words), 1;

It does depend on being able to use a subquery in the limit clause (which in SQLite is LIMIT <recs to skip>,<recs to take>) Selecting the number of records in a table should be particularly efficient, being part of the database's meta data, but that depends on the database's implementation. Also, I don't know if the query will actually build the result set before retrieving the Nth record, but I would hope that it doesn't need to. Note that I'm not specifying an "order by" clause. It might be better to "order by" something like the primary key, which will have an index - getting the Nth record from an index might be faster if the database can't get the Nth record from the database itself without building the result set.