如果我有值“foo”,和一个HashMap<String> ftw,其中ftw. containsvalue(“foo”)返回真,我怎么能得到相应的键?我需要遍历hashmap吗?最好的方法是什么?


当前回答

如果你在自己的代码中构建映射,尝试将map中的键和值放在一起:

public class KeyValue {
    public Object key;
    public Object value;
    public KeyValue(Object key, Object value) { ... }
}

map.put(key, new KeyValue(key, value));

当你有了一个值,你也就有了键。

其他回答

我的2分钱。 您可以获取数组中的键,然后循环遍历数组。如果映射非常大,这将影响代码块的性能,因为首先获取数组中的键可能会消耗一些时间,然后再进行循环。否则,对于较小的地图,这应该是可以的。

String[] keys =  yourMap.keySet().toArray(new String[0]);

for(int i = 0 ; i < keys.length ; i++){
    //This is your key    
    String key = keys[i];

    //This is your value
    yourMap.get(key)            
}
Iterator<Map.Entry<String,String>> iterator = map.entrySet().iterator();
while (iterator.hasNext()) {
    Map.Entry<String,String> entry = iterator.next();
    if (entry.getValue().equals(value_you_look_for)) {
        String key_you_look_for = entry.getKey();
}
} 

让我们看看我的例子

Map<String, String> mapPeopleAndCountry = new HashMap<>();
mapPeopleAndCountry.put("Matis", "Lithuania");
mapPeopleAndCountry.put("Carlos", "Honduras");
mapPeopleAndCountry.put("Teboho", "Lesotho");
mapPeopleAndCountry.put("Marielos", "Honduras");


List<String> peopleInHonduras = mapPeopleAndCountry.keySet()
    .stream()
    .filter(r -> mapPeopleAndCountry.get(r)
                .equals("Honduras"))
    .stream(Collectors.toList());

// will return ["Carlos", "Marielos"]

注:未经测试,可能含有错别字

听起来最好的方法是使用map.entrySet()来遍历条目,因为map.containsValue()可能会这样做。

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Set;

public class M{
public static void main(String[] args) {

        HashMap<String, List<String>> resultHashMap = new HashMap<String, List<String>>();

        Set<String> newKeyList = resultHashMap.keySet();


        for (Iterator<String> iterator = originalHashMap.keySet().iterator(); iterator.hasNext();) {
            String hashKey = (String) iterator.next();

            if (!newKeyList.contains(originalHashMap.get(hashKey))) {
                List<String> loArrayList = new ArrayList<String>();
                loArrayList.add(hashKey);
                resultHashMap.put(originalHashMap.get(hashKey), loArrayList);
            } else {
                List<String> loArrayList = resultHashMap.get(originalHashMap
                        .get(hashKey));
                loArrayList.add(hashKey);
                resultHashMap.put(originalHashMap.get(hashKey), loArrayList);
            }
        }

        System.out.println("Original HashMap : " + originalHashMap);
        System.out.println("Result HashMap : " + resultHashMap);
    }
}