是的,我知道有AlertDialog。但我很惊讶地知道在Android中显示对话框有多么困难(好吧,至少不是程序员友好的)。

我曾经是一名。net开发人员,我想知道在android上是否有类似的功能?

if (MessageBox.Show("Sure?", "", MessageBoxButtons.YesNo) == DialogResult.Yes){
    // Do something...
}

当前回答

试试这个:

AlertDialog.Builder builder = new AlertDialog.Builder(this);

builder.setTitle("Confirm");
builder.setMessage("Are you sure?");

builder.setPositiveButton("YES", new DialogInterface.OnClickListener() {

    public void onClick(DialogInterface dialog, int which) {
        // Do nothing but close the dialog

        dialog.dismiss();
    }
});

builder.setNegativeButton("NO", new DialogInterface.OnClickListener() {

    @Override
    public void onClick(DialogInterface dialog, int which) {

        // Do nothing
        dialog.dismiss();
    }
});

AlertDialog alert = builder.create();
alert.show();

其他回答

AlertDialog.Builder altBx = new AlertDialog.Builder(this);
    altBx.setTitle("My dialog box");
    altBx.setMessage("Welcome, Please Enter your name");
    altBx.setIcon(R.drawable.logo);

    altBx.setPositiveButton("Ok", new DialogInterface.OnClickListener()
    {
      public void onClick(DialogInterface dialog, int which)
      {
          if(edt.getText().toString().length()!=0)
          {
              // Show any message
          }
          else 
          {

          }
      }
    });
    altBx.setNeutralButton("Cancel", new DialogInterface.OnClickListener()
    {
      public void onClick(DialogInterface dialog, int which)
      {
          //show any message
      }

    });
  altBx.show();  

在芬兰湾的科特林:

AlertDialog.Builder(this)
    .setTitle(R.string.question_title)
    .setMessage(R.string.question_message)
    .setPositiveButton(android.R.string.yes) { _, _ -> yesClicked() }
    .setNegativeButton(android.R.string.no) { _, _ -> noClicked() }
    .show()

AlertDialog。Builder真的没有那么难用。一开始肯定有点吓人,但一旦你使用了一点,它就变得简单而强大了。我知道你说过你知道如何使用它,但这里只是一个简单的例子:

DialogInterface.OnClickListener dialogClickListener = new DialogInterface.OnClickListener() {
    @Override
    public void onClick(DialogInterface dialog, int which) {
        switch (which){
        case DialogInterface.BUTTON_POSITIVE:
            //Yes button clicked
            break;

        case DialogInterface.BUTTON_NEGATIVE:
            //No button clicked
            break;
        }
    }
};

AlertDialog.Builder builder = new AlertDialog.Builder(context);
builder.setMessage("Are you sure?").setPositiveButton("Yes", dialogClickListener)
    .setNegativeButton("No", dialogClickListener).show();

你也可以重用那个DialogInterface。OnClickListener如果你有其他是/否框,应该做同样的事情。

如果你是从视图中创建对话框。OnClickListener,你可以使用view.getContext()来获取Context。或者你也可以使用yourFragmentName.getActivity()。

芬兰湾的科特林的实现。

你可以像这样创建一个简单的函数:

fun dialogYesOrNo(
        activity: Activity,
        title: String,
        message: String,
        listener: DialogInterface.OnClickListener
    ) {
        val builder = AlertDialog.Builder(activity)
        builder.setPositiveButton("Yes", DialogInterface.OnClickListener { dialog, id ->
            dialog.dismiss()
            listener.onClick(dialog, id)
        })
        builder.setNegativeButton("No", null)
        val alert = builder.create()
        alert.setTitle(title)
        alert.setMessage(message)
        alert.show()
    }

像这样叫它:

dialogYesOrNo(
  this,
  "Question",
  "Would you like to eat?",
  DialogInterface.OnClickListener { dialog, id ->
    // do whatever you need to do when user presses "Yes"
  }
})

这里所有的答案都归结为冗长且不利于读者的代码:这正是提问者试图避免的。对我来说,最简单的方法是在这里使用lambdas:

new AlertDialog.Builder(this)
        .setTitle("Are you sure?")
        .setMessage("If you go back you will loose any changes.")
        .setPositiveButton("Yes", (dialog, which) -> {
            doSomething();
            dialog.dismiss();
        })
        .setNegativeButton("No", (dialog, which) -> dialog.dismiss())
        .show();

Android中的Lambdas需要retrolambda插件(https://github.com/evant/gradle-retrolambda),但无论如何,它对编写更清晰的代码非常有帮助。